search for: b44r15c19

...02 574 629 563 783 3 Control_1 probe~B01R09C01 673 511 521 967 4 Control_3 probe~B01R09C02 53 809 999 50 5 MM0289~RFU:11810.15 probe~B29R13C06 681 34 115 587 6 MM0289~RFU:9238.41 probe~B29R13C05 784 443 20 784 7 MM16597~RFU:36765.38 probe~B44R15C20 719 251 790 445 8 MM16597~RFU:41258.94 probe~B44R15C19 677 363 268 686 NAME ID a b c d 1 Control_1 probe~B01R01C01 381 213 345 653 2 Control_2 probe~B01R01C02 574 629 563 783 3 Control_1 probe~B01R09C01 673 511 521 967 4 Control_3 probe~B01R09C02 53 809 999 50 5 MM0289~RFU:11810.15 probe~B29R13C06 681 34 115 587 6 MM0289~RFU:9238.41 probe~B29R...

...02 574 629 563 783 3 Control_1 probe~B01R09C01 673 511 521 967 4 Control_3 probe~B01R09C02 53 809 999 50 5 MM0289~RFU:11810.15 probe~B29R13C06 681 34 115 587 6 MM0289~RFU:9238.41 probe~B29R13C05 784 443 20 784 7 MM16597~RFU:36765.38 probe~B44R15C20 719 251 790 445 8 MM16597~RFU:41258.94 probe~B44R15C19 677 363 268 686..... I would like to consolidate the data frame by parsing through the rows, and where the NAME is identical, consolidate into one row and return the mean. I can do this for the first lines (Control_1 etc) by using aggregate() aggregate(DF[,-c(1:2)], by=list(DF$NAME), mean) but sinc...