Displaying 1 result from an estimated 1 matches for "avg_weight".
2012 Jan 17
3
Using !is.na() in a HAVING clause in sqldf() XXXX
Hi everyone,
I have the following:
sqldf("select Premie,count(tpounds) N,avg(tpounds) Avg_Weight,
stddev_samp(tpounds) StdDev
from children
group by Premie
having !is.na(Premie)")
sqldf() does not like the !is.na(Premie) specification. How does one
exclude a "missing" group in an aggregated query using sqldf()?
Thanks!
Dan
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