Displaying 1 result from an estimated 1 matches for "averagepm2_5".
2024 Dec 11
2
aggregate produces results in unexpected format
...unction.
xx[,1] <- mean(df)
xx[,2] <- min(df)
xx[,3] <- max(df)
xx[,4] <- length(df)
cat("These are the dimensions of the matrix in the function",dim(xx),"\n")
print(xx)
return(xx)
}
# Create data frame
inJan2Test <- data.frame(MyDay=rep(c(1,2,3),4),AveragePM2_5=c(10,20,30,
11,21,31,
12,22,32,
15,25,35))
str(inJan2Test)
cat("This is the data frame","\n")...