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...ly affect the list structure. And even when I do: attributes(attributes(obj)[names(attributes(obj)) != "names"]) This will keep giving me a named list. Is there any way I can get the attributes() of a list without it reporting the names of a list as attributes? I.e it should hold that: atr1 <- attributes(list(foo="bar")); atr2 <- attributes(list()); identical(atr1,atr2); -- View this message in context: http://r.789695.n4.nabble.com/getting-attributes-of-list-without-the-names-tp3329209p3329209.html Sent from the R help mailing list archive at Nabble.com.