search for: antoniababe

Dear all, I have a dataset Exp name id x1 x2 x3 x4 x5 1 a 1 23 24 23 22 30 1 b 2 25 26 27 23 24 1 c 3 32 19 23 25 28 2 a 4 28 32 24 26 27 2 b 5 23 24 25 26 28 2 c 6 23 31 30 38 23 3 a 7 24 25 31 27 29 3 b 8 28 25 26 32 28 3 c 9 21 31 28 23 29 where each name a,b and c is repeated three times. Now I want to calculate the the averages of

Dear all, I have following data called "paitent" day patient1 patient4 patient5 patient6 0 -0.27842688 -0.04080808 -0.41948398 -0.04508318 56 -0.22275425 -0.01767067 -0.30977249 -0.03168185 112 -0.08217659 -0.26209243 -0.29141451 -0.09876170 252 0.08044537 -0.26701769 0.05727087 -0.09663701 where each patient have response values at four time points. I want to

Dear R-users, Following is part of my data, where slide has 36 levels and block 48 levels. I have done boxplot for each slide on the same graph. There are outliers for each slide and I tried to use indentify functtion to identify outliers in such a way that when I click on an outlier or point, the points will be labelled by either their block or ID or by both but without success. How can I make

Dear R-users, I have a data frame containing 2 colums: column 1 is the patient numbers (totally 36 patients), column 2 is patient's response values (each patient has 100 response values). If I produce a boxplot for each patient on the same graph in order to compare them against each other then the boxplots are very small. How can I instead of creating one graph containing 36 boxplots,

...4:8], DF[2], mean) library(doBy) summaryBy(x1 + x2 + x3 + x4 + x5 ~ name, DF, FUN = mean) # if Exp, name and id columns are factors then this can be reduced to library(doBy) summaryBy(. ~ name, DF, FUN = mean) library(reshape) cast(melt(DF, id = 1:3), name ~ variable, fun = mean) On 10/18/06, antoniababe at yahoo.se <antoniababe at yahoo.se> wrote: > Dear all, > > I have a dataset > > Exp name id x1 x2 x3 x4 x5 > 1 a 1 23 24 23 22 30 > 1 b 2 25 26 27 23 24 > 1 c 3 32 19 23 25 28 > 2 a 4 28 32 24 26 27 > 2 b 5 23 24 25 26 28 > 2...