Displaying 5 results from an estimated 5 matches for "animal2".
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2004 Jun 01
1
swapping with data.frame
...data which are convenient to enter as lists. For example:
t1<-list(fname="animal1",testname="hyla",dspkr="left",res1=39.7,res2=15.0)
t2<-list(fname="animal1",testname="bufo",dspkr="left",res1=14.4,res2=56.1)
t3<-list(fname="animal2",testname="hyla",dspkr="right",res1=22.6,res2=11.8)
I would like to generate a dataframe, but *not* the way this approach
works...
fdf<-data.frame(t1,t2,t3)
fdf
fname testname dspkr res1 res2 fname testname dspkr res1 res2 ...
1 animal1 hyla left 39.7 15...
2004 Jan 27
2
Probability for ANOVA
Hi all!
I have 4 treatments on 5 animals
Treat1 Treat2 Treat3 Treat4
Animal1 36 37 35 39
Animal2 33 34 36 37
Animal3 37 35 33 38
Animal4 34 36 34 35
Animal5 35 36 33 36
I use an Anova and i try to verify calcul
So i retrieve:
DF SS MS F P
Between Groups...
2013 Mar 15
1
Reassign values based on multiple conditions
...09/01/2013
2 2 01/01/2013 03/01/2013
2 1 04/01/2013 06/01/2013
I have so far been able to make multi-conditional tests:
animal1test<- (date>=01/01/13 && date<=03/01/13)
animal1test2<- (date>=04/01/13 && date<=06/01/13)
animal2test<- (date>=04/01/13 && date<=06/01/13)
to use in an 'if else' formula:
if(animal1test){
collar[1]="animal1"
} else if(animal1test2){
collar[5]="animal1"
}else if(animal2test)
collar[1]="animal2"
}else "NA"
As I...
2003 Nov 13
0
3.0-cannot create profile directory...
...c:init_sam_from_ldap(460)
init_sam_from_ldap: Entry found for user: leon
[2003/11/13 20:31:03, 2] auth/auth.c:check_ntlm_password(302)
check_ntlm_password: authentication for user [leon] -> [leon] -> [leon]
succeeded
[2003/11/13 20:31:03, 1] smbd/service.c:make_connection_snum(698)
srv-animal2 (10.0.1.10) connect to service netlogon initially as user leon
(uid=12348,
gid=10001) (pid 562)
==> log.nmbd <==
[2003/11/13 20:31:02, 1] nmbd/nmbd_processlogon.c:process_logon_packet(95)
process_logon_packet: Logon from 10.0.1.10: code = 0x12
[2003/11/13 20:31:02, 1] nmbd/nmbd_processlog...
2013 Mar 29
1
Create values based on a table of conditions
...ta.frame", row.names = c(NA,
-76L))
I have so far been able to make some conditional tests, though I would
need to do this for all 76 animals in the
study...
animal1test<- (date>=01/01/13 && date<=03/01/13)
animal1test2<- (date>=04/01/13 && date<=06/01/13)
animal2test<- (date>=04/01/13 && date<=06/01/13)
to use in a giant'if else' formula:
if(animal1test){
collar[1]="animal1"
} else if(animal1test2){
collar[5]="animal1"
}else if(animal2test)
collar[1]="animal2"
}else "NA"...