Displaying 3 results from an estimated 3 matches for "aml3".
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aml
2004 Nov 09
1
survSplit: further exploration and related topics
...u.dk/~bxc/SPE/library/, but built
under 1.9.
I recently tried to build it under 2.0, but it crashed for me and I was
advised to
wait till 2.1 before I had another go at it.
A little further exploration of what goes on in survSplit gives:
> data(aml)
> aml$id <- letters[1:dim(aml)[1]]
> aml3<-survSplit(aml,cut=c(5,10,50),end="time",start="start",
+ event="status",episode="i")
> # Sort the rows sensibly
> aml3 <- aml3[order(aml3$id,aml3$start),]
> aml3$expand <- 1:(dim(aml3)[1])
> aml3[aml3$id=="k"...
2009 Jul 13
1
survSplit with data.frame containing a Surv object
...the modified example from the help page of survSplit. The
original works, as expected. If, however, a Surv object is added to
the data.frame, each record gets doubled.
Is there some solution other than avoiding Surv objects in data.frames?
Thanks,
Heinz
require(survival)
## from the help page
aml3<-survSplit(aml,cut=c(5,10,50),end="time",start="start",
event="status",episode="i")
summary(aml)
summary(aml3)
coxph(Surv(time,status)~x,data=aml)
## the same
coxph(Surv(start,time,status)~x,data=aml3)
## added to show doubling of records
aml.so...
2011 Apr 18
1
time dependent hazard ratios
Hi, I am new to time-dependent Cox model to estimate time dependent hazard
ratios. Let me use aml dataset from survival package:
> aml3<-survSplit(aml2,cut=c(5,10,20),end="time",start="start",
event="status",episode="i")
If I want to esimate hazard ratio for each of the time intervals 0-5, 5-10,
10-20 and >=20, would the following calculate such HRs?
> coxph(Surv(start,time,s...