Displaying 1 result from an estimated 1 matches for "alternatign".
2008 Jan 24
3
Alternating numbers in rep()
All,
I'm trying to obtain a one-liner to generate a certain sequence of
alternatign numbers.
Consider:
> unlist(rep(list(c(1,2), c(3,4)), each = 6))
[1] 1 2 1 2 1 2 1 2 1 2 1 2 3 4 3 4 3 4 3 4 3 4 3 4
I'd like the result to be as above but continue until 38. Of course, I
could hardcode this going up to c(37,38), but is there a more elegant way?
Thanks!
David