search for: alternatign

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2008 Jan 24
3
Alternating numbers in rep()
All, I'm trying to obtain a one-liner to generate a certain sequence of alternatign numbers. Consider: > unlist(rep(list(c(1,2), c(3,4)), each = 6)) [1] 1 2 1 2 1 2 1 2 1 2 1 2 3 4 3 4 3 4 3 4 3 4 3 4 I'd like the result to be as above but continue until 38. Of course, I could hardcode this going up to c(37,38), but is there a more elegant way? Thanks! David