Displaying 2 results from an estimated 2 matches for "alsen".
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allen
2011 Feb 25
1
speed up process
..., name.dat=names(x)[1:3])},
mydata_list, col1=1:3, pos=mypos, MoreArgs=list(xvar=ind.xvar, yvar=k))
Thanks in advance for any hints.
Ivan
#create data (it looks horrible with these datasets but it doesn't
matter here)
mydata1 <- structure(list(species = structure(1:8, .Label = c("alsen",
"gogor", "loalb", "mafas", "pacyn", "patro", "poabe", "thgel"), class =
"factor"), fruit = c(0.52, 0.45, 0.43, 0.82, 0.35, 0.9, 0.68, 0), Asfc =
c(207.463765, 138.5533755, 70.4391735, 160.9742745, 41.455809,...
2011 Feb 28
0
Fwd: Re: speed up process
Dear Jim,
Here is again exactly what I did and with the output of Rprof (with this
reduced dataset and with a simpler function, it is here much faster than
in real life).
Thanks you again for your help!
## CODE ##
mydata1<- structure(list(species = structure(1:8, .Label =
c("alsen","gogor", "loalb", "mafas", "pacyn", "patro", "poabe",
"thgel"), class = "factor"), fruit = c(0.52, 0.45, 0.43, 0.82, 0.35,
0.9, 0.68, 0), Asfc = c(207.463765, 138.5533755, 70.4391735,
160.9742745, 41.455809, 11...