Displaying 20 results from an estimated 104 matches for "allel".
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2024 Nov 15
1
R coding to extract allele frequencies from NCBI for ALL alleles of one SNP?
Dear All,
The following code extracts from NCBI very nice output for ONE allele of a SNP (often the allele with the second largest frequency - usually termed the minor allele). It gives an average minor allele frequency from all NCBI sources (which is what I want, except I'd like the addition of data for all the other alleles of one SNP) plus a table of minor allele frequ...
2003 Sep 04
1
Allelic Differentiation, sampling, unique(), duplicated()
Hi people,
I have made some progress trying to work out how to solve this problem
but I have got a bit stuck - sorry if this turns out to be a simple
exercise . .
Allelic Differentiation (AD) in genetics measures the number of
different alleles between (say) two populations eg:
Organisms in Pop 1 have alleles: a, b, c, d, e
Organisms in Pop 2 have alleles: b, b, c, d, e
Different (unique) alleles (n) are: a
[unique() does not do what I want here for comparin...
2007 Sep 21
1
Help create a loopto conduct multiple pairwise operations
#Hello,
#I have three data frames, X,Y and Z with two columns each and different
numbers of rows.
# creation of data frame X
X.alleles <- c(1,5,6,7,8)
X.Freq <- c(0.35, 0.15, 0.05 , 0.10, 0.35)
Loc1 <- cbind( X.alleles,X.Freq)
X <- data.frame(Loc1)
#creation of data frame Y
Y.alleles <- c(1,4,6,8)
Y.Freq <- c(0.35, 0.35, 0.10, 0.20 )
Loc2 <- cbind(Y.alleles, Y...
2007 Mar 16
1
ideas to speed up code: converting a matrix of integers to a matrix of normally distributed values
...s is a bit hard to describe, so if my initial description is
confusing, please try running my code below]
#WHAT I'M TRYING TO DO
I'd appreciate any help in trying to speed up some code. I've written
a script that converts a matrix of integers (usually between 1-10,000
- these represent allele names) into two new matrices of normally
distributed values (representing genetic effects), such that a given
number in the integer (allele name) matrix always corresponds to the
*same* randomly distributed (genetic) effects.
For example, every time my function sees the allele name "3782&quo...
2008 Aug 10
1
Scripting - query
I have a vector:
alleles.present<-c("D3", "D16", ... )
The alleles present changes given the case I'm dealing with - i.e. either
all of the alleles I use for my calculations are present, or some of them.
Depending on what alleles are present, I need to make matrices and do
calculations on tho...
2008 Apr 19
1
resampling from distributions
...e whether the etiquette is to break up multiple
questions or not but I'll keep them together here for now as it may help put
the questions in context despite the fact that the post may get a little
long.
Question 1:
My first goal is to calculate the proportion of shared 1) behaviours and 2)
alleles between numerous individuals. Pasted below ('propshared' function)
is what I have now and and works very well for calculating the proportion of
shared behaviours where the data is formatted with each column as a
behaviour and each row an individual. Microsatellite genotypes are
formatte...
2009 Jan 19
1
Deleting columns where the frequency of values are too disparate
Hello R-help community,
I have another question about filtering datasets.
Please consider the following "toy" data matrix example, called "x" for simplicity. There are 20 different individuals ("ID"), with information about the alleles (A,T, G, C) at six different loci ("Locus1" - "Locus6") for each of these 20 individuals. At any single locus (e.g., "Locus1" or "Locus2", ... or "Locus6"), the individuals have either one allele (from the set of A,T,C,G) or one other allele (fro...
2002 Nov 27
0
R genetics package now available
...urce and Windows binary formats. The purpose of
this package is to make it easy to create and manipulate genetic
information, and to facility use of this information in statistical models.
The library includes classes and methods for creating, representing, and
manipulating genotypes (unordered allele pairs) and haplotypes (ordered
allele pairs). Genotypes and
haplotypes can be annotated with chromosome, locus, gene, and marker
information. Utility functions compute genotype and allele frequencies, flag
homozygotes or heterozygotes, flag allele carriers
of certain alleles, count the number of...
2002 Nov 27
0
R genetics package now available
...urce and Windows binary formats. The purpose of
this package is to make it easy to create and manipulate genetic
information, and to facility use of this information in statistical models.
The library includes classes and methods for creating, representing, and
manipulating genotypes (unordered allele pairs) and haplotypes (ordered
allele pairs). Genotypes and
haplotypes can be annotated with chromosome, locus, gene, and marker
information. Utility functions compute genotype and allele frequencies, flag
homozygotes or heterozygotes, flag allele carriers
of certain alleles, count the number of...
2007 Aug 30
2
How to multiply all dataframe rows by another dataframe's columns
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles <- c(1,5,6,7,8)
Loc1.Freq <- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 <- cbind( Loc1.alleles,Loc1.Freq)
X <- data.frame(Loc1)
#creation of data frame Y
Loc2.alleles <- c(1,4,6,8)
Loc2.Freq <- c(0.35, 0.35, 0.10, 0.20)
Loc2 <- cbin...
2012 May 13
0
how to calculate risk allele or score allele
Hello,
In a case control study how to calculate the risk allele or score allele.
Regards
GRR
[[alternative HTML version deleted]]
2012 Jun 14
1
Can someone recommend a package for SNP cluster analysis of Fluidigm microarrays?
...t can be
sophisticated enough to set the number of cluster between two or three
within the array.
These genotyping arrays are either 48 samples x 48 assays, 96x96, or 192x24
and it would be nice if it could accommodate any range of samples and
assays.
the data headings from the csv are:
ID,Assay,Allele Y,Allele X,Name,Type,Auto,Confidence,Final,Converted,Allele
Y,Allele X
where Allele Y and Allele X are the plotted values and the vectors within
the data.frame are 9216 (96x96) long.
So what would be the recommended package for moving to a more quantifiable
method of genotyping using cluster ana...
2005 Jul 07
3
What method I should to use for these data?
Dear R user:
I am studying the allele data of two populations.
the following is the data:
a1 a2 a3 a4 a5 a6 a7 a8 a9
a10 a11 a12 a13 a14 a15 a16 a17
pop1 0.0217 0.0000 0.0109 0.0435 0.0435 0.0000 0.0109 0.0543
0.1739 0.0761 0.1413 0.1522 0.1087 0.0870 0.0435 0.0217 0.0109
pop2 0.0213 0.0213 0.0000 0.0000 0.0000...
2006 Jun 05
3
Fastest way to do HWE.exact test on 100K SNP data?
Hi everyone,
I'm using the function 'HWE.exact' of 'genetics' package to compute p-values of
the HWE test. My data set consists of ~600 subjects (cases and controls) typed
at ~ 10K SNP markers; the test is applied separately to cases and controls. The
genotypes are stored in a list of 'genotype' objects, all.geno, and p-values are
calculated inside the loop over all
2011 Dec 09
1
minor allele frequency comparison
...dentify SNPs. One is based on resequencing
the genome and aligning the reads to the sequenced genome to identify SNPs
(data available for 44 individuals). Another is based on SNP array with
selected loci (30000 loci, 870 individuals). I want to compare the results
from the resequencing based minor allele frequency and Array based minor
allele frequency. What statistical test should I use?
My table looks like
Chromosome position Major/minor
Resequencing SNP array
chromosome 1 198432 C/T
75/13 1460/280...
2010 Mar 26
1
how to read this special form of data
Dear R listers,
I have a data file looks like the following:
Testing marker: s_1
---------------------------------------------
Allele df(0) -LnLk(0) df(T) -LnLk(T) ChiSq p
3 7995 29320.30 7994 29311.85 16.90 4e-05 (2229/8000 probands)
Testing marker: s_2
---------------------------------------------
Allele df(0) -LnLk(0) df(T) -LnLk(T) ChiSq p
3 7995 29339.25 7994...
2006 Apr 27
2
Incomplete Trio in TDT analysis
...ile we have many probands and most of
their mothers we only have about 50% of the trios being complete.
I have been running tdt and trio.types. It appears as if it is ignoring the
duos. Sometimes a duo can be informative. For instance
Father ..missing
Mother 1/2
Proband 1/1
This duo shows that for allele 2, this was clearly a case where 2 was
untransmitted.
Yet I do not think this family counts toward the output that is generated.
Am I correct? How do I use R to do TDT analysis where duo's are used if they
are informative?
If you want further details...
I made a subset that I called MessWit...
2007 Jun 19
1
genetics package not working
...[1] "genotype" "factor"
Now when I issue the command:
> summary(founders[,59])
I get:
Error in attr(retval, "which") <- which : attempt to set an attribute on
NULL
In addition: Warning message:
$ operator is deprecated for atomic vectors, returning NULL in:
x$allele.names
Clearly, I am missing something. What am I missing?
--
Farrel Buchinsky
[[alternative HTML version deleted]]
2006 May 05
1
How to a handle an error in a loop
...hen it does, it short
circuits the entire loop. Nothing gets written to Resultdt.
> Resultdt<-lapply(PGWide[,240:389], tdt)
Error in rep.default(1, nrow(U)) : rep() incorrect type for second argument
In addition: Warning messages:
1: 1 misinheritances in: phase.resolve(g.cs, g.mr, g.fr, as.allele.pair =
TRUE, allow.ambiguous = (parent ==
2: 1 misinheritances in: phase.resolve(g.cs, g.mr, g.fr, as.allele.pair =
TRUE, allow.ambiguous = (parent ==
3: 4 misinheritances in: phase.resolve(g.cs, g.mr, g.fr, as.allele.pair =
TRUE, allow.ambiguous = (parent ==
It is very laborious working out...
2006 Dec 29
1
Genotypes are not all the same
...ics package and more specifically have
been using the makeGenotypes and genotypes function. I check my
accomplishments by going
> class(g2)
[1] "genotype" "factor"
and likewise
> class(g1)
[1] "genotype" "factor"
Yet when I execute a command such as allele count I get this
> allele.count(g1)
D I
[1,] 2 0
[2,] 1 1
[3,] 2 0
[4,] 0 2
[5,] 2 0
[6,] 2 0
[7,] 2 0
[8,] 2 0
[9,] 0 2
[10,] NA NA
> allele.count(g2)
list()
If I print the objects I get this
> g1
[1] "D/D" "D/I" "D/D" &q...