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...h matrix @cval produced by ca.jo for the 12 subjects that i tested. Can anyone help me with that? I hope my explanation of the problem is clear. Thanks in advance for any help. -- Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: http://www2.dse.unibo.it/francesca.pancotto/ ---------------------------------- [[alternative HTML version deleted]]

...)-(1/3)))) } fa2b<-c() for (i in 1:3){ fa2b[i]<-(100-(100*abs(fa2[i]/sum(fa2[i])-(1/3)))) } and so on. Is there a more efficient way to do this? Thanks for your time! Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: https://sites.google.com/site/francescapancotto/ ---------------------------------- [[alternative HTML version deleted]]

This is a mixed question, between theory and practice. I have a dataset with a continous variable grouped by a 33 levels factor. After having log-tranformed my original data I can assume the normality of my data but I have two strong departures from the basic assumptions for anova and t tests: *unbalanced data* (some groups contain ten samples, others hundreds) and *non homogenity of variances*

...sed of these distances. I need to repeat this for each of the subsamples. I realize that there arecalculations that are repeated but I did not find a strategy that does not require Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: https://sites.google.com/site/francescapancotto/ ---------------------------------- [[alternative HTML version deleted]]

Dear Contributors, I have an easy question for you which is puzzling me instead. I am running loops similar to the following: for (i in c(100,1000,10000)){ print((mean(i))) #var<-var(rnorm(i,0,1)) } This is what I obtain: [1] 100 [1] 1000 [1] 10000 In this case I ask the software to print out the result, but I would like to store it in an object. I have tried a second loop, because if I