search for: akpbond007

Hi My data looks like this startDate="2008-06-01" dateRange =c( "2008-10-01","2008-12-01") Is there any method to find the week number from the startDate range ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Week-number-from-a-date-tp4410223p4410223.html Sent from the R help mailing list archive at Nabble.com.

Hi I have a data-frame which look like this X1 X2 X3 1 3 5 2 4 6 3 6 1 I want to apply a formula Y=6*X1 + 7*X2 + 8*X3 for every row Thanks in Advance -- View this message in context: http://r.789695.n4.nabble.com/how-to-call-a-function-for-each-row-tp4122906p4122906.html Sent from the R help mailing list archive at Nabble.com.

Hi I have set of records seperated by a separator say "$$$" i want to get the values in a dataframe. eq qwer$$12$$qwre ewrtr$7789$ewwe I want the output as\ V1 V2 V3 qwer 12 qwre ewrtr 7789 ewwwe Please help me ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Help-in-splitting-the-records-tp4650827.html Sent from

Hi I have a variable str = " X", "Y" and values ("0","12") i want to set value for X =0 and Y =12 and use inside the program. how to do this Please anybody help me. -- View this message in context: http://r.789695.n4.nabble.com/Setting-the-Values-tp3823388p3823388.html Sent from the R help mailing list archive at Nabble.com.

Hi I have a data class wise. I want to create a histogram class wise without using for loop as it takes a long time my data looks like this x class 27 1 93 3 65 5 1 2 69 5 2 1 92 4 49 5 55 4 46 1 51 3 100 4 ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Histogram-classwise-tp4528624p4528624.html Sent from the R help mailing list archive

Hi I 've a data a=c(10,20,30) b=c(100,200,300) c=c(50,60,70) I want to compare a[1]<=c[1]<b[1],...... How to compare for all the records ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/comparing-three-vectors-tp4636728.html Sent from the R help mailing list archive at Nabble.com.

I have a long string. i want to sepearate a 10 digit phone no from it. eg "my no is 9876543210 is personal no and my official no is 123-456-8907. you can use any of these" i want to seperate the 9876543210 and 123-456-8907 from this. therev may be many phone nos in the string. how to do it ----- Thanks in Advance Arun -- View this message in context:

Hi How to get p-value and the standard error in PLS I have used the following function to calculate PLS fit1 <- mvr(formula=Y~X1+X2+X3+X4, data=Dataset, comp=4) Please help me -- View this message in context: http://r.789695.n4.nabble.com/getting-p-value-and-standard-error-in-PLS-tp3914760p3914760.html Sent from the R help mailing list archive at Nabble.com.

How to use the segments in the PLS fit1 <- mvr(formula=Y~X1+X2+X3+X4+x5+....+x27, data=Dataset, comp=5,segment =7 ) here when i use segments,the error was like this rror in mvrCv(X, Y, ncomp, method = method, scale = sdscale, ...) : argument 7 matches multiple formal arguments Please help -- View this message in context:

In the lm function the summary(lmobject) we have adjusted.r square and f statistics Do we have similar to the pls package and how to get it -- View this message in context: http://r.789695.n4.nabble.com/R-square-and-F-stats-in-PLS-tp3924484p3924484.html Sent from the R help mailing list archive at Nabble.com.

Hi how do we get intercepts standard error. I'm using the package pls. i got the coefficient but not able to get the stabdard error -- View this message in context: http://r.789695.n4.nabble.com/How-to-get-intecerpt-standard-error-in-PLS-tp3932104p3932104.html Sent from the R help mailing list archive at Nabble.com.

Hi I'm getting the intercepts of the Random effects as 0. Please help me to understand why this is coming Zero This is my R code Data<- read.csv("C:/FE and RE.csv") Formula="Y~X2+X3+X4 + (1|State) + (0+X5|State)" fit=lmer(formula=Formula,data=Data) ranef(fit). My sample Data State Year Y X2 X3 X4 X5 X6 S2 1960 27.8 397.5 42.2 50.7 78.3 65.8 S1 1960 29.9 413.3 38.1

Hi, I want to remove the entire row from the dataset if any of the row contains blank or NA my dataset look like State Year Y X2 X3 X4 X5 X6 State1 1960 27.8 397.5 42.2 50.7 78.3 65.8 State2 1960 29.9 413.3 38.1 52 79.2 66.9 State1 1961 29.8 439.2 40.3 54 79.2 67.8 State2 1961 30.8 459.7 39.5 79.2 69.6 State1 1962 31.2 492.9 37.3 54.7 77.4 68.7 State2 1962 528.6 38.1 80.2 73.6 State1 1963

Hi i have few clarification regarding the output from the fitted(object). I'm creating a object using the following formula dataset <- read.csv("~/data.csv") obj = lm (formula="log(y+1)~log(x1+1)+(log(x2+1)+log(x3+1)", data=dataset) fitted(obj) here the output of the fitted(obj) considers the log(x1+1) or just log(x1). -- View this message in context:

Hi I have a data frame and i need to change the date format in it. my dataframe X Date 1 1/1/2009 2 2/1/2009 3 3/1/2009 I need to change it to 2009-01-01 -- View this message in context: http://r.789695.n4.nabble.com/changing-date-format-in-a-dataframe-tp4076411p4076411.html Sent from the R help mailing list archive at Nabble.com.

Hi I have a function y= x^2 min =10 max=20 increment=0.1 I want to find the value of y for the value of x between min and max by step increment. how to get the values using apply function instead of for loop ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/Help-required-in-using-apply-instead-of-for-loop-tp4344350p4344350.html Sent from the

Hi My data looks like this data is a vector data= var1 var2 var3 100 120 130 i want to put it in an XML xmlOutput=NULL xmlOutput<- newXMLNode("results") for( i in 1 : length(data)) { newXMLNode("variable",attrs=c(name =names(data)[i] ), value = data[i]), parent = xmlOutput) } is it possible to use apply here If there more variables it

Hi, I have a dataset X Y A= 10 15 20 30 40 50 B = X Z 10 30 20 50 I have a table containing X Y Z columns How to insert a data frame into the table without using for loop ? now currently i'm using the for loop with using the insert command? ----- Thanks in Advance Arun -- View this message in

Hi My dataframe looks like this data= id V1 V2 V3 V4 1 5 6 7 8 1 10 20 30 40 2 23 54 54 6 3 43 54 54 33 4 12 34 54 54 4 34 54 23 52 I have to sum by id I used command aggregate(data,by =list(data$id),FUN=sum) Error i face is Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L), na.rm = FALSE) : sum not meaningful for factors Please help me ----- Thanks in Advance Arun --

Hi I've records like this df= x panel 4 1 93 2 21 3 83 4 75 1 87 2 87 3 78 4 50 1 76 2 86 3 65 4 84 1 40 2 39 3 26 4 i want to create histogram out of it . i want all the mid and count values for panel wise my code is histoutput = ddply(df,.(df[2]),hist) i'm not able to get the required result. please help me using for loop takes a lot of time if there are more records ----- Thanks