Displaying 20 results from an estimated 3890 matches for "agly".
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2006 Jun 30
3
data extraction
Dear mailing list I have a data that have 20,000 rows and 20 columns. Io
wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000
th. can you please help me how do I do that.Than kyou.
Example is below.
Inpute:
AG GG GG AG
CC CC CC CC
CT CC CT CT
GG GG GG GG
CC CC CC CC
GG GG GG GG
CC CC CC CC
GG CG CG GG
GG GG GG GG
*CC CC CC CC*
AA AG AG AA
AA AA AA AA
GG AG AG GG
GG AG AG
2013 Jan 09
4
how to count "A","C","T","G" in each row in a big data.frame?
Dear All
I have a data.frame like that:
structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565",
"Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238",
"Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581",
"Gga_rs10728004",
2005 Aug 03
0
Chan_bluetooth and AudioGateway phone [long]
Hello,
I start trying to use a USB dongle and a Bluetooth GSM phone to make GSM
call with asterisk using the BLT channel provided by the GSM phone.
Unfortunately I get a "Everyone is busy/congested at this time" whenever
I try to Dial("IAX2/****@****/2", "BLT/MotorolaLara/3474501***")
For sure I make some mistake in the configuration. Unfortunately I don't
find
2006 Oct 15
0
chan_bluetooth - one way audio
I have compiled chan_bluetooth and I have used it many times before... but
now I have a problem and I can?t find a solution. I have a bluetooth dongle
(MSI) connected to my asterisk and I use a V3 phone to make calls to another
cell phones... the thing is that I just get one way audio.. I can hear
people from my IAX softphone but they can?t hear me... I don?t know what
could be.. anyone had
2010 Mar 09
0
error with adaboost: replacement has 186 rows, data has 62
Hi, all,
When running > AB.fit=adaboost(ylearn, xlearn, xtest, presel=0) I got the
following error:
Error in `[[<-.data.frame`(`*tmp*`, preds, value = c(4L, 6L, 6L, 6L, 3L, :
replacement has 186 rows, data has 62
The data structure is attached below:
[1] "ylearn"
[1] 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0
0 0 0 0
[40] 1 1 1 1 1 1 1 0
2008 Apr 24
1
truncate row names
Hi,
I would like to truncate row names. Is that possible?
I ran a regression with the covariates in a matrix, and in the results the
coefficients have the matrix name concatenated with the variable name:
> full.t.ag <- Icens(lfirst_well, llast_well, lfirst_ill, formula=~ t.ag.X,
breaks=t.ag.int, data=t.ag)
> full.t.ag$cov$coeff
t.ag.Xnyearc t.ag.Xhorse t.ag.Xswine
2006 Jan 11
1
chan_bluetooth problems
Has anyone had experience with Theo's chan_bluetooth with asterisk-1.2.0 on FC3.
When I try to make a call to my home through the channel my phone shows calling but my home phone never rings.
I get this on screen:
== Spawn extension (outgoing, 3234600, 2) exited non-zero on 'SIP/2299-9131'
-- Executing Dial("SIP/2299-7743", "BLT/John/3541107") in new stack
2010 Mar 08
0
error when using svm routine: Error in if (any(co)) { : missing value where TRUE/FALSE needed
Hi,
I met with this error message with the following data set. Do you know how
to resolve it? Thanks.
> data<-read.table("c://temp3//abc.csv", sep = ",", header=T)
> classwt<-c( 0.5806452, 0.4193548)
> y<-data[,1]
> x<-data[,2:ncol(data)]
> print(y)
[1] 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1
[36] 1 1 1 1 2 2 2 2 2 2
2011 Dec 15
1
Am I misunderstanding loop variable assignment or how to use print()?
Given this interactive session:
> an<-ls(pat="anova.ag.m2529")
> an
[1] "anova.ag.m2529.az" "anova.ag.m2529.can" "anova.ag.m2529.fl"
> print(anova.ag.m2529.az)
Analysis of Variance Table
Response: year
Df Sum Sq Mean Sq F value Pr(>F)
time 1 14.823 14.8235 10.598 0.004392 **
Residuals 18 25.177
2013 Apr 23
1
assigning cluster id in cluster package-reg.
Well, you don't give much of an example....
I'm replying CC to the R mailing list. Please ask questions there, rather
than adressing individuals for basic help.
Here is one; does it answer your question ?
data(agriculture)
ag.ag <- agnes(agriculture)
class(ag.ag)
pltree(ag.ag) # the dendrogram, if you want to see it
## cut the dendrogram -> get cluster assignments:
(ck3 <-
2005 Feb 28
2
A problem about outer()
Dear all,
I have something about function outer() that I can't understand. Just see the following example. The two NaNs are due to 0/0, but I can't figure out the cause of the last two errors. I wonder if some one can explain this for me.
___________________________________________________________________
> sx=rbinom(10,1,0.5);ot=rbinom(10,1,0.5);ag <- rbinom(10,100,0.3);ho <-
2006 Jan 27
1
chan_bluetooth: successful compile and outbound cell calls: Still tweaking inbound setup. WAS: Cannot compile chan_bluetooth on Asterisk 1.2.1
Editing subject line to reflect current status.
On 1/26/06, Nilesh Londhe <lvnilesh@gmail.com> wrote:
> Since T616 is not answering (and incoming calls are going to Cingular
> voicemail after 30 sec,) I suspect the problem focus area is...
>
> > -- Executing Answer("BLT/T616", "") in new stack
>
> Is
2013 Feb 13
5
spearman correlation and p-value as a matrix
I have two data matrices that I want to make the correlation between each column from data1 and each column from data 2 and also calculate the p-value Matrices dont have the same size and I tried such a script.
> bg <- read.table (file.choose(), header=T, row.names)
> bg
> Otu00022 Otu00029 Otu00039 Otu00042 Otu00101 Otu00105 Otu00125 Otu00131 Otu00137 Otu00155 Otu00158 Otu00172
2005 Sep 27
2
Integration with NMS AG-E1/T1
I want to replace a custom PBX, that is infront on a IVR system based on OLD NMS AG-E1 Card.
The Cards is configurated with CAS Digitalmode, someone can give me some info about Digim Cards CAS configuration i need a conversion Table?
I wanto to don't touch configuration on winbox, i want only replace HWPBX box with asterisk.
Diagram
Telco E1 ===>Proprietary PBX========(CAS)===>IVR
2005 Oct 28
3
replacing a factor value in a data frame
Hi All,
I have the following problem, that's driving me mad.
I have a dataframe of factors, from a genetic scan of SNPs. I DO have
NAs in the dataframe, which would look like:
V4 V5 V6 V7 V8 V9 V10
1 TT GG TT AC AG AG TT
2 AT CC TT AA AA AA TT
3 AT CC TT AC AA <NA> TT
4 TT CC TT AA AA AA TT
5 AT CG TT CC AA AA TT
6 TT CC TT AA AA AA TT
7 AT CC
2006 Jul 28
1
spliting
Dear mailing list,
I have a big data frame and each element in the matrix has two alphabets. I
want to split those alphabets into two so each element will have one
alphabet and the number of my columns will be doubled . So can some one help
with the code?
Example of what I want is to split them.
Input (three column)
GG AG AG
CC CC CC
CC CC CC
AG
2009 Feb 20
2
System of logistics Equations
Hi R-masters
I need yours help about a problema in one of may ongoing researchers.
In my research the subjects (20 in total) answer 60 questions (20 type
G, 20 type S and 20 type P).
Which questions is classified about 3 factor (2 level each) and the
subject score with 2 scale (not integer value is possible but rare): Val
range -7 to 7 and other Car range 1 to 7.
This a code to fake database
2006 Jun 22
2
*** Spam *** Don't use CDRTool From AG-projescts
This post cannot be left without comment. People who don't know you or Adrian might get a wrong impression.
I know Adrian quite well and know that he is one of the real experts in this industry and he and his stuff does not deserve such a treatment.
I would recommend that you change your attitude. It seems like you did not get what you want (for free) and you complain like a small child. An
2010 May 11
3
Improving loop performance
R-users,
I have the following piece of code which I am trying to run on a dataframe (aga2) with about a half million records. While the code works, it is extremely slow. I've read some of the help archives indicating that I should allocate space to the p1 and ags1 vectors, which I have done, but this doesn't seem to improve speed much. Would anyone be able to provide me with advice on
2009 Mar 20
1
reshape dataframe
Hi,
I have a large dataset on which I would like to do the following:
x<-data.frame(id=c(1,2,3), snp1=c("AA","GG",
"AG"),snp2=c("GG","AG","GG"),snp3=c("GG","AG","AA"))
> x
id snp1 snp2 snp3
1 1 AA GG GG
2 2 GG AG AG
3 3 AG GG AA
And then