search for: aggregive

The documentation for `aggregate` makes it sound like aggregate.formula should behave identically to aggregate.data.frame (apart from the way the parameters are passed). But it looks like aggregate.formula is quietly removing rows where any of the "output" variables (those on the LHS of the formula) are NA. This differs from how aggregate.data.frame works. Is this expected behavior?

Can someone please tell me what is up with na.action in aggregate? My (somewhat) reproducible example: (I say somewhat because some lines wouldn't run in a separate session, more below) set.seed(100) dat=data.frame( x1=sample(c(NA,'m','f'), 100, replace=TRUE), x2=sample(c(NA, 1:10), 100, replace=TRUE), x3=sample(c(NA,letters[1:5]), 100, replace=TRUE),

Hi All, I am currently doing the following to compute summary statistics of aggregated data: a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean) b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum) c = aggregate(warpbreaks$breaks, warpbreaks[,-1], length) ans = cbind(a, b[,3], c[,3]) This seems unnecessarily complex to me so I tried > aggregate(warpbreaks$breaks, warpbreaks[,-1],

----- Original Message ----- > From: "Mehdi Amini via llvm-dev" <llvm-dev at lists.llvm.org> > To: "deadal nix" <deadalnix at gmail.com> > Cc: "llvm-dev" <llvm-dev at lists.llvm.org> > Sent: Wednesday, August 19, 2015 7:24:28 PM > Subject: Re: [llvm-dev] [RFC] Aggreate load/store, proposed plan > > Hi, > > To be sure,

What are the functions available for use with “aggregate”? Where can a reference to them be found? --------------------------------- [[alternative HTML version deleted]]

Hi, I find it a bit annoying that aggregate.default forces the returned object to loose the 'name' of the variable aggregated, replacing it with 'x'. A brief example: > dat <- data.frame(A = runif(100), B = rnorm(100), + Group = gl(4, 25)) > with(dat, aggregate(A, by = list(Group = Group), FUN = mean)) Group x 1 1 0.6523228 2 2

This may not be possible... I have an aggregation of clwholename defined in my model. the aggregation builds clwholename from :first_name, middle_initial, last_name and it generally works fine. I am trying to add a validation so while there may be many ''John'' first_names, and ''Doe'' last_names, I only want one ''John Doe'' so I tried...

----- Original Message ----- > From: "deadal nix" <deadalnix at gmail.com> > To: "Hal Finkel" <hfinkel at anl.gov> > Cc: "Mehdi Amini" <mehdi.amini at apple.com>, "llvm-dev" <llvm-dev at lists.llvm.org> > Sent: Thursday, August 20, 2015 4:09:17 PM > Subject: Re: [llvm-dev] [RFC] Aggreate load/store, proposed plan >

----- Original Message ----- > From: "deadal nix" <deadalnix at gmail.com> > To: "Hal Finkel" <hfinkel at anl.gov> > Cc: "Mehdi Amini" <mehdi.amini at apple.com>, "llvm-dev" <llvm-dev at lists.llvm.org> > Sent: Friday, August 21, 2015 1:24:04 AM > Subject: Re: [llvm-dev] [RFC] Aggreate load/store, proposed plan >

It is pretty clear people need this. Let's get this moving. I'll try to sum up the point that have been made and I'll try to address them carefully. 1/ There is no good solution for large aggregates. That is true. However, I don't think this is a reason to not address smaller aggregates, as they appear to be needed. Realistically, the proportion of aggregates that are very large

Hi R users, I am trying to use the aggregate function with a survey design object and survey functions, but get the following error. I think I am incorrectly using the syntax somehow, and it may not be possible to access variables directly by name in a survey-design object. Am I right? How do I fix this problem? I have used aggregate with "mean" and "weighted.mean", and

I am currently summarising a data set by collapsing data based on common identifiers in a column. I am using the 'aggregate' function to summarise numeric columns, i.e. "aggregate(dat[,3], list(dat$gene), mean)". I also wish to summarise text columns e.g. by concatenating values in a comma separated list, but the aggregate function can only return scalar values and so something

>aggregate(z, identity, mean) 1 2 3 4 5 1.0 3.0 5.0 6.0 7.5 > aggregate(z, mean) Error: length(time(x)) == length(by[[1]]) is not TRUE Can someone help me understand the error above and why "identity" is necessary to satisfy the error -- View this message in context:

Hi, I am using aggregate() to add up groups of data according to year and month. It seems that the function aggregate() automatically sorts the levels of factors of the grouping elements, even if the order of the levels of factors is supplied. I am wondering if this is a bug, or if I missed something important. Below is an example that shows what I mean. Does anyone know if this is just the way

I am trying to understand cut so I can divide a list of numbers into 10 group: 0-9.0 10-10.9 20-20.9 30-30.9, 40-40.9, 50-50.9 60-60.9 70-70.9 80-80.9 90-90.9 As I try to do this, I have been playing with the cut function. Surprising the following for applications of cut give me the exact same groups. This surprises me given that I have varied parameters include.lowest and right. Can someone

On 10-Oct-16 06:45, Aki Tuomi wrote: > Does your build end at some particular point? See **** DETAILS **** for in depth (I hope enough!) study/report. > > Aki I would guess this is not "c99" way... Making all in lib-http source='test-http-auth.c' object='test-http-auth.o' libtool=no DEPDIR=.deps depmode=xlc /bin/sh ../../depcomp xlc_r

On 09-Oct-16 22:51, Aki Tuomi wrote: >> >> Michael > > Does the compiler support C99 standard? > > Aki Yes. Plus extended features. Key difference with GCC, e.g., are the flags to the compiler, but autotools general manages those well. Key difference with platform (well, of of) is that it is not GNU, and how shared libraries are built. Again, libtool in particular,

Hello! I am aggregating using a formula in aggregate - of the type: aggregate(cbind(var1,var2,var3)~factor1+factor2,sum,data=mydata) However, I actually have an object (vector of my variables to be aggregated): myvars<-c("var1","var2","var3") I'd like my aggregate formula (its "cbind" part) to be able to use my "myvars" object. Is it

Hi, R users, I'm wondering how I can aggregate data in R with different functions for different columns. For example: x<-rep(1:5,3) y<-cbind(x,a=1:15,b=21:35) y<-data.frame(y) I want to aggregate "a" and "b" in y by "x". With "a", I want to use function "mean"; with "b", I want to use function "sum". I tried:

Consider the following scrap of code: > x<- ts(1:50,start=c(1,11),freq=12) > y <- aggregate(x,nfreq=4) > c(y) [1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141 > y Error in rep.int("", start.pad) : invalid number of copies in rep.int() > tsp(y) [1] 1.833333 5.583333 4.000000 So we can aggregate into quarters, but we cannot print it using