Displaying 4 results from an estimated 4 matches for "aggegate".
Did you mean:
aggregate
2006 Nov 16
1
How Aggegate Data in R
Hello:
When I use SPSS I execute the AGGREGATE DATA comand for the next data:
2112141123212213212213334
3143244113442312121213344
2114141123112214212113344
2112211122212413421213221
3114444123442414343413344
2312231223212222323223322
2143241123212313131213234
2113241113212313222213333
2113141123112214212113344
2114141123412111114413344
2113211122342314222313234
2114141123112414212113344
2006 Oct 01
3
aggregate function with 'NA'
Dear r-help reader,
I have some problems with the aggregate function.
My datframe looks like
>frame
Day Time V1 V2
1 M 0 3 NA
2 M 0 4 NA
3 M 0 5 2
4 M 1 NA 4
5 M 1 10 6
6 T 0 4 45
7 T 1 4 3
8 T 1 3 2
9 T 1 6 1
I used the aggegate function to obtain the mean in V1 and V2 over the
grouping variable
Time and Day
aggregate(frame[,c(-1)],list(frame$Day,frame$Time),mean)
Group.1 Group.2 Time V1 V2
1 M 0 0 4.000000 NA
2 T 0 0 4.000000 45
3 M 1 1 NA 5
4 T...
2008 Oct 09
1
Basic aggregate help
...uantity=c(1,2,3))
> x
Name Category Quantity
1 A a 1
2 A a 2
3 C b 3
> aggregate(x, by=as.list(setdiff(names(x),"Quantity")), sum)
Error in FUN(X[[1L]], ...) : arguments must have same length
The way I understand it is that 'aggegate' should group the rows that are the same (in the above 1,2 are the same and 3 stands alone) and the FUN should be applied to the ramaining column. I was expecting a data.frame like:
Name Category Quantity
1 A a 3
2 C b 3
But that is not what I got. Would...
2005 Sep 01
1
Strange build message: request help w/resolving
Greetings,
I am attempting to build a R package, however the build fails and the
following message is ouput:
C:\ConstellaGroup\EPA\RAGG\package>R CMD BUILD --binary --force RAGG
* checking for file 'RAGG/DESCRIPTION' ... OK
* preparing 'RAGG':
* checking DESCRIPTION meta-information ... ERROR
Error in if (regexpr(dep_regexp, dep) == -1) { :
missing value where