Displaying 3 results from an estimated 3 matches for "abyb".
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abb
2008 Jul 20
0
Off topic: SS formulae for 3-way repeated measure anova (for when aov() fails)
...==round(summary(this_aov)[[4]][[1]]$Sum[1], 10)
#ok!
#Get ss.d.error
d.cells = aggregate(x, list(d=d, sub=sub), mean)
ss.d.cells = levs.a*levs.b*sum((d.cells$x-grand.mean)^2)
ss.d.error = ss.d.cells - ss.d - ss.subs
round(ss.d.error, 10)==round(summary(this_aov)[[4]][[1]]$Sum[2], 10)
#ok!
#Get ss.aBYb
aBYb.means = aggregate(x, list(a=a, b=b), mean)
ss.aBYb = N*levs.d*sum((aBYb.means$x-grand.mean)^2) - ss.a - ss.b
round(ss.aBYb, 10)==round(summary(this_aov)[[5]][[1]]$Sum[1], 10)
#ok!
#Get ss.aBYb.error
aBYb.cells = aggregate(x, list(a=a, b=b, sub=sub), mean)
ss.aBYb.cells = levs.d*sum((aBYb.cell...
2008 Nov 30
2
Randomization of a two-way ANOVA?
Hello list,
I wish to perform a randomization test on the F-statistics of a 2 way ANOVA
but have not been able to find out how to do so - is there a package /
function that can perform this that I am unaware of?
FactorA has 6 levels (0,1,2,3,4,5) whereas FactorB has 3 (1,2,3). A sample:
Resp. FactorA FactorB
2 0 2
3 1 2
1 2 2
0 3 2
0 4 2
0 5 2
4 0 1
6 1 1
1 2 1
0 3 1
1 4 1
0 5 1
2 0 2
3 1 2
1
2004 Jul 18
2
a problem: factors, names, tables ..
Hi all,
I am *completely* lost in trying to solve a relatively simple task.
I want to compute the relative number of occurences of an event, the data
of which sits in a large table (read from file).
I have the occurences of the events in a table 'tt'
0 2 10 11 13 14 15
15 6 1 3 8 15 10
.. meaning that event of type '0' occurs 15 times, type '2' occurs 6 times