search for: abrahams

This message didn't seem to have been somewhat forgotten. Here is a reply. When you constructed the data.frame, all strings were converted to factors. If you didn't want that, it would have been possible to specify it: df<-data.frame(a=a,b=b,c=c,stringsAsFactors=F) Then everything would work as intended: one.line<-as.character(df[df$a=="Abraham",]) Actually, the real

Hi All, we are using Red Hat 2.1 Kernel e38 along with MSA 1000. ocfs version being used is $ rpm -qa | grep ocfs ocfs-tools-1.0.10-1 ocfs-2.4.9-e-enterprise-1.0.12-1 ocfs-support-1.0.10-1 Database Version is 9.2.0.5 However we find that the performance of the database on OCFS is too slow. even a select count(1) from all_tables takes like a while to complete. We initially assumed RAC is

I'm trying to figure out why when I use as.character() on one row of a data.frame, I get factor numbers instead of a character vector. Any suggestions? See the following code: a<-c("Abraham","Jonah","Moses") b<-c("Sarah","Hannah","Mary") c<-c("Billy","Joe","Bob")

Hi, I'm trying to plot several lag.plots on a page, however the second plot replaces the first one (although it only takes up the upper half as it should): par(mfrow=c(2,1)) a<-sin(1:100) b<-cos(1:100) lag.plot(a) lag.plot(b) What's the trick to this? I'm using R 2.2.1 (2005-12-20 r36812) on Ubuntu Linux. Thanks, Gad -- Gad Abraham Department of Mathematics and

Hi Sunil, I'm looking into this thread now. Does this mean we cannot use FTP option to copy OCFS files to ext3? If so, is there any ftp version available for OCFS, similar to cp --o_direct? Also, is there any version of sync available for OCFS (in normal FS, sync does a refresh of FS from kernel cache so that the FS is consistent). By this can we say that the FS shard by both nodes is

Hello folks, Here's is info on what system I'm working on. > sessionInfo() R version 2.13.0 (2011-04-13) Platform: i686-pc-linux-gnu (32-bit) I'm trying to install the XML package. However, I end up with the following error message. > install.packages("XML") .... checking for xml2-config... no Cannot find xml2-config ERROR: configuration failed for package ‘XML’ *

Hi Sunil, I had filed a bug and saw your response stating that it would be fixed in version 14. In the meanwhile , what we want to know is whether this bug is a minor bug and can be ignored for now. Does reporting 100% inodes cause any problem for the OCFS file system or can we ignore this bug and go into production. Also can you tell us by when version 14 would be released. R'gds

Hi, I'm using zoo because it can automatically label the months of a time series composed of daily observations. This works well for certain time series lengths, but not for others, e.g.: While: > library(zoo) > plot(zoo(runif(10), as.Date("2005-06-01") + 0:50)) Shows up the months and day of month, > plot(zoo(runif(10), as.Date("2005-06-01") + 0:380))

Hi, Can anyone explain how the standard error in arima() is calculated? Also, how can I extract it from the Arima object? I don't see it in there. > x <- rnorm(1000) > a <- arima(x, order = c(4, 0, 0)) > a Call: arima(x = x, order = c(4, 0, 0)) Coefficients: ar1 ar2 ar3 ar4 intercept -0.0451 0.0448 0.0139 -0.0688 0.0010 s.e.

Hi, My name is Abraham and I am a 2nd year college student from Bangalore(India). I was going through your list of project ideas, and the Learning to Rank project really interested me . Unfortunately I don't really have any real experience with "Information Retrieval" and only know the basics of "Machine Learning". I was hoping that somebody could maybe point me in the

I'm trying to find the total number of letters in a row of a data frame. Let's say I have the following data frame. f1 <- data.frame(keyword=c("I live in Denver", I live in Kansas City, MO", "Pizza is good")) The following function gives me the number of characters in each string. So for "I live in Denver", I get 1, 4, 2, and 6. However, I want to

Hi! Is there any way to do just plain vanilla TBF (Token Buck Filter) type shaping on a group of ips/networks, not an entire interface. Currently the only way I know how to shape in Linux is to use HTB or CBQ, but both of these need a total rate and then you need to subdivide that into classes. That is not what I want. All I want is Cisco generic traffic shaping style shaping (or similar to how

Hi, I'm using survreg() from the survival package for parametric survival regression (modelling inter-arrival times of patients to a waiting list as exponentially distributed, with various regressors such as queue size and season). Does anyone know which algorithm survreg() uses for this? Thanks, Gad -- Gad Abraham Department of Mathematics and Statistics The University of Melbourne

I'm trying to run a logit model and plot the probability curve for a number of the important predictors. I'm trying to do this with the Effects package. df=data.frame(income=c(5,5,3,3,6,5), won=c(0,0,1,1,1,0), age=c(18,18,23,50,19,39), home=c(0,0,1,0,0,1)) str(df) md1 = glm(factor(won) ~ income + age + home, data=df,

I'm an R newbie and had a question about the read.xls function. I've heard that this is often not a reliable function to use for importing data. However, I have created numerous xls files which contain information about voter turnout and macroeconomic indicators in India. I'm writing a paper on the relationship between economic growth and voter turnout. This is the command I use:

I'm running a linear model in R using the car package. I have a variable education, which i have recoded and regrouped to my wishes. However, R seems to place each element of that variable in alphabetical order. When I am running the model, don't I need the model order from lowest to highest to make an inference that a one unit change in one variable produced a one unit change in

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OEM software means no CD/DVD, no packing case, no booklets and no overhead cost! So OEM is synonym for lowest price. Buy directly from the manufacturer, pay for software ONLY and save 75-90%! Check discounts and special offers! Find software for home and office! TOP ITEMS Adobe Photoshop CS2 V9.0 $69 Macromedia Flash Prof 8 $49 Adobe Premiere 2.0 $59 MS Office

I'm developing a naive bayes in R. I have the following data and am trying to predict on returned (class). dat = data.frame(home=c(0,1,1,0,0), gender=c("M","M","F","M","F"), returned=c(0,0,1,1,0)) str(dat) dat$home <- as.factor(dat$home) dat$returned <- as.factor(dat$returned) library(e1071) m <- naiveBayes(returned ~ ., dat) m

So I have the following data frame and I want to know how I can remove all "NA" values from each string, and also remove all "|" values from the START of the string. So they should something like "auto|insurance" or "auto|insurance|quote" one = data.frame(keyword=c("|auto", "NA|auto|insurance|quote", "NA|auto|insurance",