search for: abner

Hi All: I'm worse than a newbie at this so if this seems a bit dumb please accept my appologies. I've gone to us1.samba.org/samba/docs/DIAGNOSIS.htm and run all of the tests. My installation appears to pass all of them except for this one: nmblookup -B ABNER Yes, Abner is all in uppercase on both the windoz box and the Linux box. All of the other tests appear fine. The above appears to manifest itself in slow transfer speeds when transfering files to the Linux box from the Windows box when the command is given on the Linux box. The same transfer...

Hello everyone, What is the simplest, most RELIABLE way to import data from MS EXCEL (.xls) format to R? In the past I have used the read.xls() function from the xlsReadWrite package, however, I have been wrestling with it all afternoon long with no success. I continue to receive the following error message: > {widge<-read.xls("F:\\Classes\\Z1.Data\\stat.3010\\WidgeOne.xls", +

Hi everyone, I have the following: sqldf("select Premie,count(tpounds) N,avg(tpounds) Avg_Weight, stddev_samp(tpounds) StdDev from children group by Premie having !is.na(Premie)") sqldf() does not like the !is.na(Premie) specification. How does one exclude a "missing" group in an aggregated query using sqldf()? Thanks! Dan [[alternative HTML version deleted]]

Hi everyone, I understand the process of obtaining the internal integer codes for the raw values of a factor (using as.numeric() as below), but what is the best way to obtain these codes for the levels() of a factor (since the as.numeric() results don't really make clear which code maps to which level)?

Hello everyone, I am trying to add the following text (in proper notation) to a graphic using expression(). X-bar (with a subscript of cv) = XX. Note: Ideally "cv" would be a subscript, but it doesn't have to be. I have the following code: > text(625,.012,expression(bar(X)cv = 552.01)) Error: unexpected symbol in "text(625,.012,expression(bar(X)cv" I have also

Hello everyone, I have the following call to sapply() and error message. Is the most efficient way to deal with this to make sum(!is.na(x)) a function in a separate line prior to this call? If not, please advise. N.Valid=sapply(x,sum(!is.na(x))) Error in match.fun(FUN) : 'sum(!is.na(x))' is not a function, character or symbol Thanks! Dan [[alternative HTML version deleted]]

Hi everyone, Any ideas on troubleshooting this memory issue: > d1<-read.csv("arrears.csv") Error: cannot allocate vector of size 77.3 Mb In addition: Warning messages: 1: In class(data) <- "data.frame" : Reached total allocation of 1535Mb: see help(memory.size) 2: In class(data) <- "data.frame" : Reached total allocation of 1535Mb: see

Hi everyone, How does one place an object name (in this case a vector name) into another object (while essentially masking the values of the first object? For example: > JOBSAT<-rnorm(40) > > CI<-function(x,alpha){ + result<-cbind(x,mean=mean(x),alpha) + print(result) + } > CI(JOBSAT,.05) I want this to return: Variable mean alpha JOBSTAT 0.02844131 0.05

Hello everyone, I am attempting to use the %in% operator with the ! to produce a NOT IN type of operation. Why does this not work? Suggestions? > data2[data1$char1 %in% c("string1","string2"),1]<-min(data1$x1) > data2[data1$char1 ! %in% c("string1","string2"),1]<-max(data1$x1)+1000 Error: unexpected '!' in "data2[data1$char1

Hello everyone, Is it possible to specify a 2 line y-axis label on the same lef-hand side y-axis? I am using the \n regular expression, but only the 2nd line appears (I assume the 1st line is printed off the page...) plot(PRE_SHB,R1, main="Figure 1.1: Scatterplot of Residualized Post Score", xlab = "Pre Score", ylab = "Residualized Post Score \n (Adjusted for Age

Hello everyone, I have 1 data frame (just a vector in the example below) with 12 individuals listed and a separate vector of 36 days (in week intervals). What is the best way to merge these together so that each individual ("specialist" here) has all 36 days matched with their specialist number (a one to many merge in SAS; essentially resulting in long format data).

Hi everyone, What is the easiest way to remove the word Average and strip leading and trailing blanks from the character vector (d5.Region) below? .nrow.d5. d5.Region 1 1 Central Average 2 2 Coastal Average 3 3 East Average 4 4 Metro East Average 5 5 Metro North Average 6 6 Metro South Average 7

Hi all, I want to select all variables in the data.frame with a name that includes are certain string. Something like the following: merge3[,names(merge3) %in% c("Email","Email.x")] But there are too many variations on the Email variable names to list them all. Can anyone advise? Thanks! Dan

Check the string matching functions, e.g. grepl(). -pd > On 16 Apr 2016, at 15:18 , Dan Abner <dan.abner99 at gmail.com> wrote: > > Hi all, > > I want to select all variables in the data.frame with a name that > includes are certain string. Something like the following: > > merge3[,names(merge3) %in% c("Email","Email.x")] > > But ther...

Hi all, I have a situation where I have 16 bins. I generate a random number and then want to know which bin number the random number falls in. Right now, I am using a serious of 16 if() else {} statements which get very complicated with the embedded curly braces. Is there a more efficient (i.e., easier) way to go about this? boundaries<-(0:16)/16 rand<-runif(1) Which bin number (1:16)

Hello everyone, I am writing my own function to return the column index of all variables (these are currently character vectors) in a data frame that contain a dollar sign($). A small piece of the data look like this: can_sta can_zip ind_ite_con ind_uni_con AL 36106 $251,895.80 $22,874.43 AL 35802 $141,373.60 $7,100.00 AL 35201 $273,208.50 $18,193.66 AR 72404 $186,918.00 $25,391.00 AR

Hello everyone, I have the following factor: levels(pp_income) [1] "" "1" "2" "3" "4" "5" "6" "7" [9] "8" "9" "Renter" I want to subset so that only values 1:9 are included. I have the following: > income<-pp_income[pp_income %in%

On 09/28/2017 10:25 PM, Dan Abner wrote: > Hi all, > > I have a large number of text strings to search for enumerated items. > However, I am receiving this error message even though I thought that I > properly escaped the special character closed parenthesis: > > >> Count<-str_count(text3,keywords)...

Hello everyone, I use Bob Muenchen's approach for reading in "in-stream" (to use SAS parlance) delimited data within a script. This works great: mystring <- "id,workshop,gender,q1,q2,q3,q4 1,1,f,1,1,5,1 2,2,f,2,1,4,1 3,1,f,2,2,4,3 4,2, ,3,1, ,3 5,1,m,4,5,2,4 6,2,m,5,4,5,5 7,1,m,5,3,4,4 8,2,m,4,5,5,5" mydata <- read.table( textConnection(mystring),

Hi all, I have a large number of text strings to search for enumerated items. However, I am receiving this error message even though I thought that I properly escaped the special character closed parenthesis: > Count<-str_count(text3,keywords) Error in stri_count_regex(string, pattern, opts_regex = opts(pattern)) : Syntax error in regexp pattern. (U_REGEX_RULE_SYNTAX) === Here is