search for: abcdef

...f new file mode 100644 index 0000000..3704fb9 Binary files /dev/null and b/test/trace/substr-5.swf differ diff --git a/test/trace/substr-5.swf.trace b/test/trace/substr-5.swf.trace new file mode 100644 index 0000000..4bcee52 --- /dev/null +++ b/test/trace/substr-5.swf.trace @@ -0,0 +1,420 @@ +-10 - ABCDEF +-10:-10 - +-10:-9 - +-10:-8 - +-10:-7 - +-10:-6 - +-10:-5 - A +-10:-4 - AB +-10:-3 - ABC +-10:-2 - ABCD +-10:-1 - ABCDE +-10:0 - +-10:1 - A +-10:2 - AB +-10:3 - ABC +-10:4 - ABCD +-10:5 - ABCDE +-10:6 - ABCDEF +-10:7 - ABCDEF +-10:8 - ABCDEF +-10:9 - ABCDEF +-9 - ABCDEF +-9:-10 - +-9:-9 -...

...0 [2015/07/01 16:36:32.935297, 4] ../source4/dsdb/repl/drepl_notify.c:463(dreplsrv_notify_schedule) dreplsrv_notify_schedule(5) scheduled for: Wed Jul 1 16:36:38 2015 CEST [2015/07/01 16:36:36.569356, 3] ../source4/auth/kerberos/krb5_init_context.c:80(smb_krb5_debug_wrapper) Kerberos: AS-REQ abcdef.abcdefg-abcdef at AD.DOMAIN from ipv4: 10.156.248.234:54408 for krbtgt/AD.DOMAIN at AD.DOMAIN [2015/07/01 16:36:36.654528, 3] ../source4/auth/kerberos/krb5_init_context.c:80(smb_krb5_debug_wrapper) Kerberos: Client sent patypes: 128 [2015/07/01 16:36:36.654564, 3] ../source4/auth/kerberos/krb5_...

I am currently attempting to split a long list of strings (let's call it "string.list") that is of the format: "1234567.z3.abcdef-gh.12" I have gotten it to: "1234567" "z3" "abcdef-gh" "12" by use of the strsplit function. This leaves me with each element of "string.list" having a split string of the above format. What I'd like to do now is extract the first two...

Can the path statement in the smb.conf contain two entries as in the example below: path = /u04/abcdef /u03/xyz What I want to do is to essentially have 2 filesystems be part of one share so that the windows users would see all the sub-directories of filesystems /u04/abcdef and /u03/xyz

...ike H:\SOMETH.TXT) the system changes it to lower characters - correct behaviour, If I create same file on sub levels (like h:\TEST\SOMETH.TXT ) it's left in upper case characters. It's correct : [2004/06/17 11:37:40, 3] smbd/reply.c:reply_mv(3943) reply_mv : Neu Textdatei.txt -> ABCDEF.TXT [2004/06/17 11:37:40, 5] smbd/filename.c:unix_convert(114) unix_convert called on file "Neu Textdatei.txt" [2004/06/17 11:37:40, 5] smbd/filename.c:unix_convert(114) unix_convert called on file "ABCDEF.TXT" [2004/06/17 11:37:40, 5] smbd/filename.c:unix_convert(177) uni...

I noticed this issue in stringr::str_replace, but it also affects sub() in base R. If the pattern in a call to one of these needs to be a regular expression, then backslashes in the replacement text are treated specially. For example, gsub("a|b", "\\", "abcdef") gives "def", not "\\\\def" as I wanted. To get the latter, I need to escape the replacement backslashes, e.g. gsub("a|b", "\\\\", "abcdef") which gives "\\\\cdef". I have two questions: 1. Is there a variant on sub or str...

...strwrap, I see that the problem is that "Whitespace ... in the input is destroyed". However, I thought I'd mention it because I'm not sure it is intended behavior for str(). I have a list, and the names of the list have a variable number of characters. > x <- list(A=1:10, ABCDEF=LETTERS[1:10]) > str(x) List of 2 $ A : int [1:10] 1 2 3 4 5 6 7 8 9 10 $ ABCDEF: chr [1:10] "A" "B" "C" "D" ... The above looks as expected in my R session (although it looks a little different when I paste it into this e-mail). There are 5 spaces...

Hi Folks, Ran into something I'd really like to do in R simply/elegantly, but my R - coding skills seem surpassed. This is the thing. Imagine the following data: labs<-c("abcdef","abcgg","tgthefdk","tgtijuel","tgtnjmoi","gbnt","dlift") dat<-c(0.5,0.25,1,2,16,0.250,4) dframe<-data.frame(labs,dat) I would like to average the values in "dat" according to specific string/text in the name of their...

Dear all, let's assume I have a vector of character strings: x <- c("abcdef", "defabc", "qwerty") What I would like to find is the following: all elements where the word 'abc' does not appear (i.e. 3 in this case of 'x'). Since I am not really experienced with regular expressions, I started slowly and thought I find all word were...

...t string is shorter than the portion of the string to be replaced? The documentation to substr (in R 1.3.1) gives me: If the portion to be replaced is longer than the replacement string, then only the portion the length of the string is replaced. And so I try: R> x <- "abcdef" R> substr(x,2,3) <- "xy" #ok R> x [1] "axydef" R> substr(x,2,3) <- "w" #ko R> x [1] "aw" hmm, I would have expected "awdef". Am I reading the docs wrong? (Or am I just blinded to expect this string because that's what...

...t string is shorter than the portion of the string to be replaced? The documentation to substr (in R 1.3.1) gives me: If the portion to be replaced is longer than the replacement string, then only the portion the length of the string is replaced. And so I try: R> x <- "abcdef" R> substr(x,2,3) <- "xy" #ok R> x [1] "axydef" R> substr(x,2,3) <- "w" #ko R> x [1] "aw" hmm, I would have expected "awdef". Am I reading the docs wrong? (Or am I just blinded to expect this string because that's what...

Hi list, I have some questions on how rsync names the temporary files it create during a file transfer. It is my understanding that temporary files are name .<filename>.ABCDEF, where "ABCDEF" is a random 6-chars alphanumeric string. First question: it is correct to say that the random aphanumeric string is _always_ 6 chars long? Second question: it is possibile to define a specific, non-random string? I read what rsync's manpage says about suffixes, bu...

Hi, i have a vector filled with names: [1] Alvaro Adela ... [25] Beatriz Berta ... ... [100000] ... I would like to drop last character in every name. I use the next program: for (i in 1:100000) { ? ? ? ? ? ? ? ? ? ? ? ? ? largo <- nchar(names[i]-1) ? ? ? ? ? ? ? ? ? ? ? ? ? names[i] <- substring (names[i],1,largo] ? ? ? ? ? ? ? ? ? ? ? ? ?} Is another and faster way of do it? Thanks,

On Mon, Oct 11, 2010 at 6:46 PM, Calvin Walton <calvin.walton@gmail.com> wrote: > On Mon, 2010-10-11 at 03:30 +0300, Felipe Contreras wrote: >> I use btrfs on most of my volumes on my laptop, and I''ve always felt >> booting was very slow, but definitely sure is slow, is starting up >> Google Chrome: >> >> encrypted ext4: ~20s >> btrfs: ~2:11s

There looks to be a bug in do_attr() (src/main/attrib.c): incorrect partial matches of attribute names can be returned when there are an odd number of partial matches. E.g.: > x <- c(a=1,b=2) > attr(x, "abcdef") <- 99 > attr(x, "ab") [1] 99 > attr(x, "abc") <- 100 > attr(x, "ab") # correctly returns NULL because of ambig partial match NULL > attr(x, "abcd") <- 101 > attr(x, "ab") # incorrectly returns non-NULL for ambig p...

Hi, I would like to know what is the easiest way to compile two or more set of vectors or data frame, according to their index. They are interrelated to one another by their assigned index. for example: #data set 1 abc #output: X403 X408 X410 X415 X418 X419 X420 X423 X424 X425 X426 X427 549.58 541.91 544.18 549.37 555.54 540.83 543.26 544.26 546.85 548.98 553.10 556.49

...to implement a service on top of an smb named pipe. I go over the samba code and I have seen how to implement the service directly into samba code like the rpc echo server. I wish to do it differently. Is there a way for an external software to register into samba such as all smb messages on \PIPE\ABCDEF (as an example) get transmit directly to it ? If yes, Is there any documentation out that I missed ? Best regards, Jean-Daniel FISCHER

Why doesn't R have one, like "." in Perl or juxtaposition in awk? It does not seem impossible to introduce one, if that would be reasonable. It would seem to involve adding a table entry to main/names.c for the binary operator and a corresponding internal function, say do_dot(). This cannot be simply do_paste(), since the implied separator is "". So, do_dot() might be

I have a huge data set in the form of            V1           V2         V3   V4     V5  V6 1     201005010000201005010000 1.68291.38 1  0 2     201005010000201005010300 0.93335.10 1  0 3     201005010000201005010600 2.25 57.38 1  0 4     201005010000201005010900 0.43 13.76 1  0 5     201005010000201005011200 0.74101.14 1  0 I am interested in interpolating it on an hour basis(it's for avery

...user abc from ::ffff:x.x.x.x Mar 12 15:01:03 server sshd[28503]: Invalid user ab from ::ffff:x.x.x.x Mar 12 15:01:03 server sshd[28507]: Invalid user abcd from ::ffff:x.x.x.x Mar 12 15:01:03 server sshd[28509]: Invalid user abcde from ::ffff:x.x.x.x Mar 12 15:01:03 server sshd[28511]: Invalid user abcdef from ::ffff:x.x.x.x Mar 12 15:01:04 server sshd[28515]: Invalid user abcdefgh from ::ffff:x.x.x.x Mar 12 15:01:04 server sshd[28513]: Invalid user abcdefg from ::ffff:x.x.x.x "abcdefgh" is my username to the different machine in the other domain, x.x.x.x it's my workstation. Yesterda...