search for: aabc

Hi, I have a string vector, say, x <- "a", "aab" and anther string vector, say, y <- "a", "aa", "aab", "aabc". Is there any R function to get the indices of y for the elements of x, that is, foo(x, y) will give me the index vector c(1, 3)? I know i can combine apply() and grep("^aab$", y) to do it. But is there any elegant R function I can use? Thanks, -Luke [[alternative HTML version...

...3 EWST A 2224 7.54688 -0.026210 3 19950331 EWST 10001 3 EWST A 2244 7.50000 0.006377 However when I call the part of the array dealing with the Ticker, I get: > stocks[2,2] [1] EWST 16185 Levels: A AA AAA AAAB AAABB AAB AABC AAC AACB AACC AACE AACI ... ZVXI Thus, when I reference this later, I get a numeric result and not the symbol? Is this because I need to change the format of stocks[,2] or because it has these extra "levels". For example: # START FIRST PORTFOLIO port1=matrix(0, ctr,3)#matr...

...39;, 'C'}; String[] perms = GetPermutations(set); Arrays.sort(perms, String.CASE_INSENSITIVE_ORDER); for(int i=0; i<perms.length; i++){ System.out.println(perms[i]); } } } ------------------------- END JAVA CODE ----------------------------- This code prints the following: AABC AACB ABAC ABCA ACAB ACBA BAAC BACA BCAA CAAB CABA CBAA -- View this message in context: http://www.nabble.com/Multiset-Permutations-tp16529735p16529735.html Sent from the R help mailing list archive at Nabble.com.