Displaying 20 results from an estimated 3520 matches for "aa's".
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a's
2013 Jan 09
4
how to count "A","C","T","G" in each row in a big data.frame?
...+", "+", "+", "+", "+", "+", "+",
"+", "+", "+", "+", "+", "+", "+", "+", "+", "+", "+", "+"),
X2353 = c("AA", "TT", "TT", "CC", "TT", "CC", "CC", "TT",
"CC", "GG", "AG", "AG", "AG", "TT", "CC", "AG", "CC", "AA",
"GG&quo...
2012 Jun 07
0
how lm behaves
...re are 'c' on more days than I have 'h2o2', where treats[,4] is the day. I only want 'c' that correspond to the same days that I have a 'h2o2' also.
>z<-treats[,3] == 'h2o2'
>x<-treats[,4] %in% treats[z,4]
>a<-treats[,3] == 'c'
>aa<-which(a)
>xx<-which(x)
>zz<-which(z)
>aa<-intersect(aa, xx)
>aa<-c(aa, zz)
>a<- count[aa]
>x<-as.vector(treats[aa,2])
>y<-as.vector(treats[aa,4])
>b<-as.vector(treats[aa,5])
>data1<-cbind(a,x,y,b)
>data1<-as.data.frame(data1)
>data...
2006 Jun 30
3
data extraction
...nd 20 columns. Io
wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000
th. can you please help me how do I do that.Than kyou.
Example is below.
Inpute:
AG GG GG AG
CC CC CC CC
CT CC CT CT
GG GG GG GG
CC CC CC CC
GG GG GG GG
CC CC CC CC
GG CG CG GG
GG GG GG GG
*CC CC CC CC*
AA AG AG AA
AA AA AA AA
GG AG AG GG
GG AG AG GG
GG GG GG GG
TT TT TT TT
AA AG AG AA
CT CC CT TT
AG AA AG GG
*AA AA AG AG*
AA AA AA AA
CC CC CC CG
GG GG GG AG
CT TT CT CT
AT AA AT AT
GG GG GG AG
CG CC CG GG
GG GG GG AG
CC CC CC CT
GG GG GG GG
*GG GG AG AG
*CC CC CC CT
TT TT TT CT
AG GG AG AG
GG GG GG G...
2009 Jun 03
1
strsplit for multiple columns
Hi,
I am trying to split multiple columns. One column works just fine, but I
want to do it for multiple columns???
Example
> a
ID V2 V3 V4 V5 V6 V7 V8 V9 V10
1 PBBA0644 -- GG AA -- AA -- AA GG GG
2 PBBA1010 -- GG AA -- AA -- AA GG GG
3 0127ATPR -- GG AA -- AA -- AA GG GG
4 0128EHAB -- GG AA -- AG -- AA AG GG
5 PBBA0829 -- GG AA -- AA -- AA GG AG
6 01605BGA -- GG AA -- AA -- AA GG GG
7 01624BGA -- GG AA -- AG -- AA GG GG
8 01853BGA -- GG...
2010 Nov 24
3
[LLVMdev] Question regarding the alias analysis chaining behaviour
Hi,
I am using LLVM 2.4 on a Linux RHEL5 machine. I was trying to figure out
how the chaining of the alias analysis passes works in LLVM. Here are the
command I used to test the chaining part.
1. ./opt hello_world_1_nest_func.bc -o hello_world_1_nest_func_AA.bc
-no-aa -anders-aa -licm
Result: Anderson's AA and No Alias Analysis both are called.
2. ./opt hello_world_1_nest_func.bc -o hello_world_1_nest_func_AA.bc
-basicaa -anders-aa -licm
Result: Anderson's AA and Basic AA both are called.
3. ./opt hello_world_1_nest_func.bc -o hello_wor...
2010 Oct 08
6
Selección de observaciones
Hola a todos.
Estoy atascado en un sitio que no me he encontrado antes, debe ser fácil y
rápido, a ver si alguien me puede ayudar.
Puesto fácil, tengo:
> aa <- matrix(11:19,3,3)
> aa
[,1] [,2] [,3]
[1,] 11 14 17
[2,] 12 15 18
[3,] 13 16 19
Quiero la fila cuyo primer elemento es 12 y el segundo 15.
> aa[aa[,1:2] == (c(12,15)),]
Error: (subscript) logical subscript too long
¿Entonces?
> aa[aa[,1:2] == t(c(12,15)),]...
2009 Aug 05
1
Decision boundaries for lda function?
...e lda function from the MASS library. I would to find the
decision boundaries of each class and subsequently plot them. I wonder if
anybody can offer any help on this topic?
Below I applied the lda function on a small dataset of mine.
Any help will be much appreciated.
> library(MASS)
> AA<-read.table("http://www.natursyn.dk/online/fingerprinting.txt",header=T)
> aa.lda<-lda(as.matrix[3:9],AA$group)
> aa.ld<-predict(aa.lda,dimen=2)$x
> eqscplot(aa.ld,type="n",xlab="LD1", ylab="LD2",las=1)
> text(aa.ld,c(rep('f',...
2006 Dec 20
4
R windows crash (PR#9426)
...from: (NULL) (61.88.57.1)
R gui exits without warning when I run a function which has an argument with a
default that is not found.
This was a result of an error in a function I wrote, but I thought that it
should exit more gracefully than it does. Here is an example:
testfun <- function(aa=aa) {
aa <- lm(y~x,data=aa)
return(aa)
}
testfun() #R then exits.
Note that
testfun <- function(aa=bb) {
aa <- lm(y~x,data=aa)
return(aa)
}
works as it should, giving "object bb not found".
2005 Oct 28
3
replacing a factor value in a data frame
Hi All,
I have the following problem, that's driving me mad.
I have a dataframe of factors, from a genetic scan of SNPs. I DO have
NAs in the dataframe, which would look like:
V4 V5 V6 V7 V8 V9 V10
1 TT GG TT AC AG AG TT
2 AT CC TT AA AA AA TT
3 AT CC TT AC AA <NA> TT
4 TT CC TT AA AA AA TT
5 AT CG TT CC AA AA TT
6 TT CC TT AA AA AA TT
7 AT CC TT CC <NA> <NA> TT
8 TT CC TT AC AG AG TT
9 AT CC TT CC AG <NA> TT
10 TT CC TT CC GG GG TT
In the dataframe I have 1 c...
1999 Apr 23
1
[S] uniroot -- doesn't work recursively
...he R community ... :-)
Martin Maechler <maechler@stat.math.ethz.ch> http://stat.ethz.ch/~maechler/
Seminar fuer Statistik, ETH-Zentrum SOL G1; Sonneggstr.33
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone: x-41-1-632-3408 fax: ...-1086 <><
>>>>> "AA" == Adelchi Azzalini <aa@gwen.stat.unipd.it> writes
to S-news on 22 Apr 1999 :
AA> Dear S+ users,
AA> has anyone experienced problems with uniroot(), in Splus 4.5?
AA> In my case, it locates a (non-existing) solution outside the
AA> given search in...
2019 May 17
3
nrow(rbind(character(), character())) returns 2 (as documented but very unintuitive, IMHO)
Hi Herve,
Inline.
On Thu, May 16, 2019 at 4:45 PM Pages, Herve <hpages at fredhutch.org> wrote:
> Hi Gabe,
>
> ncol(data.frame(aa=c("a", "b", "c"), AA=c("A", "B", "C")))
> # [1] 2
>
> ncol(data.frame(aa="a", AA="A"))
> # [1] 2
>
> ncol(data.frame(aa=character(0), AA=character(0)))
> # [1] 2
>
> ncol(cbi...
2010 Mar 09
0
error with adaboost: replacement has 186 rows, data has 62
...as 62
The data structure is attached below:
[1] "ylearn"
[1] 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0
0 0 0 0
[40] 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1
[1] "xlearn"
rs2289472 rs1551398 rs7927894
X18 "CT" "AA" "CT"
X19 "TT" "AA" "CC"
X33 "TT" "AG" "TT"
X35 "TT" "AA" "CT"
X36 "CC" "AA" "CT"
X41 "CT" "AA...
2013 Apr 29
3
rbinding some elements from a list and obtain another list
...t;-list(A=data.frame, B=data.frame, C=data.frame, D=data.frame)
I want to rbind some elements of this list.
As an example:
Output<-list(AB=data.frame, CD=data.frame)
Where
AB=rbind(A,B)
CD=rbind(C,D)
I’ve tried:
f<-function(x){
for (i in seq(1,length(names(x)),2)){
aa<-do.call(rbind,x[i:i+1])
aa
}}
bb<-f(mylist)
or
f<-function(x){
for (i in seq(1,length(names(x)),2)){
aa[i]<-do.call(rbind,x[i:i+1])
list(aa[i])
}}
bb<-f (mylist)
but it doesn’t works!!!!
f<-function(x){
+ for (i in seq(1,length(names(x))...
2012 Jan 04
2
[LLVMdev] Comparison of Alias Analysis in LLVM
On Wed, Jan 4, 2012 at 12:10 PM, David Gardner <daveg at xmos.com> wrote:
> Jianzhou Zhao <jianzhou <at> seas.upenn.edu> writes:
>> The documents say that all the aa analysis are chained, and give an
>> example like opt -basicaa -ds-aa -licm. In this case, does ds-aa
>> automatically call basicaa for the case when ds-aa can only return
>> MayAlias? This looks magic to me. Is this handled by AnalysisGroup
>> magically?
>
> As I unde...
2005 Jul 08
2
removing factor level represented by less than x rows
In a number of different situations I'm trying to
remove factor levels that are represented by less than
a certain number of rows, e.g. if I had the dataset aa
below and wanted to remove the species that are
represented in less than 2 rows:
data(iris)
aa <- iris[1:101,]
In this case, since I can see that the species
virginica only has one row, I can write:
table(aa$Species)
setosa versicolor virginica
50 50 1
aa[aa$Speci...
2009 May 14
2
[LLVMdev] alias analysis results
Hi there,
I am trying to understand how AliasAnalysis works out in LLVM. I used
the following simple test-case (test4.c):
--
void test()
{
int *jj, *kk;
int aa = 100;
jj = &aa;
*jj = 300;
}
int main()
{
test();
return 0;
}
--
Then I did "llvm-gcc -emit-llvm -c -o test4.bc test4.c" to get bc. I
tried the following 2 ways to get what I expect to get as
"alias-sets":
1. opt -aa-eval -print-all-alias-modref-info test4....
2010 May 18
2
Counting Frequencies in Data Frame
Hi,
I am sure there is an easy way to do it, but I can't find it.
I have a data frame that has 15 columns and 7000 rows.
The only values inside the data.frame are "aa", "ab", "bb" as you can see an
example bellow.
1 2 3
1 aa ab ab
2 ab ab ab
3 aa aa aa
4 bb bb bb
What I would like to do, is to generate a vector (or another data.frame)
with 7000 rows, and 3 columns. In the first column, the information about
how many aa, the second...
2011 Sep 13
1
error trying to create replicated volume on EC2
...gluster peer probe domU-BB-BB-BB-BB.compute-1.internal
Probe successful
A ~$: gluster peer status
Number of Peers: 1
Hostname: domU-BB-BB-BB-BB.compute-1.internal
Uuid: 8d5d9af4-6a92-4d56-b063-c8fc9ac17a45
State: Peer in Cluster (Connected)
B ~$: gluster peer status
Number of Peers: 1
Hostname: AA-AA-AA-AA (the IP of host A)
Uuid: 8d5d9af4-6a92-4d56-b063-c8fc9ac17a45
State: Peer in Cluster (Connected)
A ~$: sudo gluster volume create test-vol replica 2 transport tcp
domU-AA-AA-AA-AA.compute-1.internal:/mnt/brick1
domU-BB-BB-BB-BB.compute-1.internal:/mnt/brick1
Brick: domU-AA-AA-AA-AA.comput...
2010 Mar 08
0
error when using svm routine: Error in if (any(co)) { : missing value where TRUE/FALSE needed
...sswt<-c( 0.5806452, 0.4193548)
> y<-data[,1]
> x<-data[,2:ncol(data)]
> print(y)
[1] 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 1 1 1 1 1
[36] 1 1 1 1 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2
> print(x)
rs2289472 rs1551398 rs7927894
1 CT AA CT
2 TT AA CC
3 TT AG TT
4 TT AA CT
5 CC AA CT
6 CT AA CT
7 TT AA CT
8 CT AG CT
9 CC AA CT
10 TT AG...
2016 Mar 22
4
Existing studies on the benefits of pointer analysis
It's found more and more like "get CFL-AA turned on by default" might be
a viable GSoC project for the right student. It would require someone
with existing knowledge of AA and a willingness to debug nasty problems,
but it sounds like there's definitely interest in the community in
seeing this happen.
If the student finished...