search for: a_b

...? Should I adorn something with some attributes ? As far as I can tell no, but I am no llvm expert... For what I want to do, i will probably have a few dozen combinable allocas in my produced code each function. So it would be worthwhile to reduce stack space needs. Ciao Nat! --- %struct.a_b = type { i32, i32 } ; Function Attrs: nounwind ssp uwtable define void @g() #0 { entry: %x = alloca %struct.a_b, align 4 %y = alloca %struct.a_b, align 4 %a = getelementptr inbounds %struct.a_b, %struct.a_b* %x, i32 0, i32 0 store i32 1, i32* %a, align 4 %b = getelementptr inbounds...

...ess its argument is marked with the nocapture attribute, the compilation of g() cannot assume that f() has not retained a pointer to the x struct and is using it in the second call. > thanks a lot for the input. Yes, I forgot to that. The C function declaration would have been void f( struct a_b *p); which compiled into declare void @f(%struct.a_b*) #2 with attributes #2 = { "disable-tail-calls"="false" "less-precise-fpmad"="false" "no-frame-pointer-elim"="true" "no-frame-pointer-elim-non-leaf" "no-infs-fp-m...

...t with logical operators: "Select all elements of a vector that start with A (A*) OR that start with B (B*)" Probably that is quite easy. I looked into grep() which I think might perform such tasks, but probably there is a more straigth forward solution. a <- c("A_A","A_B","C_A","BB","A_Asd") a[a=="A_A"| a=="A_B"] # here I'd like an index but with wildcard /johannes --

...3400 3.906 4.1055 23.153 100 b At first I thought the gap was due to the overhead of calling c(a, list(b)). But this turns out not to be the case: make_fn_weird <- function(a, b) as.function(c(a, b), env = parent.frame()) b_wrapped <- list(b) make_fn_weirder <- function(a_b) as.function(a_b, env = parent.frame()) a_b <- c(a, b_wrapped) microbenchmark(make_fn_1(a, b), make_fn_2(a, b), make_fn_weird(a, b_wrapped), make_fn_weirder(a_b)) # Unit: microseconds # expr min lq mean median uq max ne...

...# This is a shell archive. Save it in a file, remove anything before # this line, and then unpack it by entering "sh file". Note, it may # create directories; files and directories will be owned by you and # have default permissions. # # This archive contains: # # Makefile # types.h # a_b.c # a_b_c.c # main.c # echo x - Makefile sed 's/^X//' >Makefile << 'END-of-Makefile' XCFLAGS=-g -O3 -DNDEBUG X X Xall: reuse noreuse X Xa_b1.o: a_b.c X $(CC) $(CFLAGS) -c -o $@ -DREUSE=0 $+ X Xa_b2.o: a_b.c X $(CC) $(CFLAGS) -c -o $@ -DREUSE=1 $+ X Xnoreuse: a_b1.o a_b_c.o...

Hi Experts, This might be silly question that I am asking, but no way as I am new to R. I want to list the files in a directory using regular expression like A_B*_C*.csv etc. How to make this possible in R ? I tried like this list.files(dir=".", pattern="A_B*_C*.csv") but this gives no output, whereas list.files(.... pattern="*.csv") giving all the .csv files in the output, which I do not want. Thanks Sidda -- View thi...

Hello, If I have a dataframe: example(data.frame) zz<-c("aa_bb","bb_cc","cc_dd","dd_ee","ee_ff","ff_gg","gg_hh","ii_jj","jj_kk","kk_ll") ddd <- cbind(dd, group = zz) and I want to divide the column named group by the "_", how would I do this? so inste...

...elongs_to :b end so my Model A has a habtm collection of Bs *plus* a direct belongs_to link to one B (and vice versa). So a = A.find(:first) b = a.bs.first a2 = b.a might not give me back a, because b''s direct belongs_to a reference is clobbered with the reference from the join table a_b (because the foreign keys have the same name)? Or does this only apply to non foreign key attributes? There are no such problems if I''d make a_b a join model and have no habtm, but a has_many :through instead? What other options to circumvent this problem do I have (besides renaming...

...9; header (again, i was figuring out why some of messages cannot be searched). Header: From: =?UTF-8?Q?A=2CB?= <test at example.com> Data send to Solr by Dovecot: <field name="from">A@, B &amp;lt;test at example.com&amp;gt;</field> Header: From: =?UTF-8?Q?A_B=2CC?= <test at example.com> Data send to Solr by Dovecot: <field name="from">A@</field> Header: From: =?UTF-8?B?QSBCLEMK?= <test at example.com> Data send to Solr by Dovecot: <field name="from">A@</field> Dovecot 2.2.27. azur

I have a join table A_B with columns[a_id, b_id, c_data default 1, d_data default 1]. If I do: @aobj.bobjs.push_with_attributes(@bobj,{:c_data => 0}) I find that the row inserted, has d_data set to 0 and not the default value specified in the database, which is 1. So I am having to explicitly set it using : @aobj.bo...

It is minor thing, but how can I avoid converting "_" to "." ? e.g. I have a data set "test.csv" A,A_B,A_C,C,D X,11,0,13,14 Y,21,0,23,24 and when I read it all underscores are converted to dots (:<) > d <- read.csv("test.csv") > d A A.B A.C C D 1 X 11 0 13 14 2 Y 21 0 23 24 Ryszard [[alternative HTML version deleted]]

...As av0 = aov(y ~ tra, data=dF) summary(av0) av1 = aov(y ~ a*b, data=dF) summary(av1) av2 = aov(y ~ a/b, data=dF) b_a = summary(av2, split = list('a:b' = list( 'b1 vs b2/a1' = 1, 'b1 vs b2/a2' = 2, 'b1 vs b2/a3' = 3))) b_a av3 = aov(y ~ b/a, data=dF) a_b = summary(av3, split = list('b:a' = list( 'a/b1' = c(1,3), 'a/b2' = c(2,4)))) a_b # My doubts a) How to make the SSQ decomposition to complete the ANOVA below? -------------------------------------------------------- Df Sum Sq Mean Sq F v...

...order to get features like subscripts in the column headings. I recently had to reinstall xtable and discovered that all my LaTeX column headings were printing out in LaTeX code rather than with LaTeX formatting. For example, with the older xtable I could give my column a name something like "$A_b$" to get printed column heading of "A" with the subscript "b." Now my printed column heading is "$A_b$" and the LaTeX code in the .tex file generated by Sweave is "\$A\_b\$". It seems that the newest version of print.xtable takes all my LaTeX special cha...

Good morning, I have something like this: names(coint_tests) <- apply(b,2,paste, collapse="_") which prints 15 names like: A_B, C_D, E_F, ... AA,B,C,D.. Are time series. Then there is a vector called coint_tests of length 15 which yields "yes" or "no". I need to add a function to plot the time series Ai_Bi if the coint_tests vectors gives me a "YES". I tried: for (i in 1:(length(coint_te...

...lution. This is a pretty basic, easy, and practical application for RoR. If you guys know of any resources on the net to answer these questions let me know. Question 1: Basically, I have a many-to-many relationship that I want to add records to. I use something like this to add records in the A_B table: c.clubs<<Club.find_all_by_name(params[:clubs]) This takes the ones that already exist and establishes a relationship between A and B. What if I want to take ones that don''t exist in params[:clubs] and have those added to Club table? Is there any shortcut operator for doin...

...bol). So I wrote a simple little function to do this: get.first.id.func <- function(vec, splitter){ vec.lst <- strsplit(vec, splitter) first.func <- function(vec1){vec1[1]} vec.out <- sapply(vec.lst, first.func) vec.out } For a trivial example, this works: > a <- c("a_b", "c_d") > get.first.id.func(a, "_") [1] "a" "c" I am running into problems, however, with the real world split of ' \\\ ' I'm not even able to construct a sample vector of my own! Here is what I get: > a <- c('a \\\ b', ...

..._detect(all_comb, cu_al)] > return(res_out) > } > #----------------------- > > Ejemplo: > > > set_examp <- c('a','b','c','d') > > my_choice(set_examp, 'a', 'b') > [1] "a" "b" "a_b" "a_c" "a_d" "b_c" "b_d" > "a_b_c" > [9] "a_b_d" "a_c_d" "b_c_d" "a_b_c_d" > > La función calcula todas las combinaciones sin repetición posibles y > extrae los eleme...

...g out why some of messages cannot be searched). > > > Header: From: =?UTF-8?Q?A=2CB?= <test at example.com> > Data send to Solr by Dovecot: <field name="from">A@, B &amp;lt;test at example.com&amp;gt;</field> > > > Header: From: =?UTF-8?Q?A_B=2CC?= <test at example.com> > Data send to Solr by Dovecot: <field name="from">A@</field> > > > Header: From: =?UTF-8?B?QSBCLEMK?= <test at example.com> > Data send to Solr by Dovecot: <field name="from">A@</field> > >...

Im trying to establish relationships in a many to many table. When I create a user, I do this to insert the different relationships between the user and sports: c.sports<<Sport.find_all_by_name(params[:sports]) where c is the user. The problem is, when I edit this user, and lets say he adds a sport, I can''t use this because I get an error saying that some records already

Hola, tengo que resolver un problema para el que normalmente utilizaría excel, pero me gustaría intentar resolverlo con R. Se trata de lo siguiente: Tengo tres elementos: a, b y c. Dichos elementos están agrupados en siete objetos, producto de todas las combinaciones sin repetición posibles: Objeto 1: a Objeto 2: b Objeto 3: c Objeto 4: a y b Objeto 5: a y c Objeto 6: b y c Objeto 7: a, b y c