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2007 Feb 01
0
traverse through many columns of a matrix in a function
...m = 2) answer <- apply(z[,-1], 2, function(m_index[,1],my.cop) fitCopula(cbind(z[,-1], m_index[,1]), my.cop, start=0.3), my.cop = my.cop) Thanks for help. Adam (aat) -- View this message in context: http://www.nabble.com/traverse-through-many-columns-of-a-matrix-in-a-function-tf3152747.html#a8742152 Sent from the R help mailing list archive at Nabble.com.