search for: a5

Hello, I'm new in R and I want to do one thing that is very easy in excel, however, I cant do it in R. Suppose we have the data frame: data<- data.frame(A=c("a1","a2","a3","a4","a5")) I need to obtain another column in the same data frame (lets say B=c(b1,b2,b3,b4,b5) in the following way: b1=a1/(a1+a2+a3+a4+a5) b2=a2/(a2+a3+a4+a5) b3=a3/(a3+a4+a5) b4=a4/(a4+a5) b5=a5/a5 a1..a5 and b1...b5 are always numeric values (this is just an example, what I rea...

Dear R users, Basically, from the following arbitrary data set: a <- data.frame(id=c(c("A1","A2","A3","A4","A5"),c("A3","A2","A3","A4","A5")),loc=c("B1","B2","B3","B4","B5"),clm=c(rep(("General"),6),rep("Life",4))) > a id loc clm 1 A1 B1 General 2 A2 B2 General 3 A3 B...

...CV_LINK_OPTS) --verbose $(RISCV_OBJDUMP) -d $(WORK_DIR)/build/$@/$@ > $(WORK_DIR)/build/$@/$@.S $(RISCV_LLVM_OBJDUMP) --arch=rv32imac -D $(WORK_DIR)/build/$@/$@ > $(WORK_DIR)/build/$@/$@.ASM ``` gcc objdump result: ``` 4001168: 00052383 lw t2,0(a0) 400116c: 979a add a5,a5,t1 400116e: 439c lw a5,0(a5) 4001170: 0308a533 mulhsu a0,a7,a6 ``` llvm-objdump result: ``` 4001168: 83 23 05 00 lw t2, 0(a0) 400116c: 9a 97 add a5, a5, t1 400116e: 9c 43 lw a5, 0(a5) 4001170: 33...

Dear All, Here is a hypothetical sample (sorry for the clumsy code): A1 <- matrix(1:5, nrow=5, ncol=1) A2 <- matrix(6:10, nrow=5, ncol=1) A3 <- matrix(11:15, nrow=5, ncol=1) A4 <- matrix(16:20, nrow=5, ncol=1) A5 <- matrix(21:25, nrow=5, ncol=1) A6 <- matrix(26:30, nrow=5, ncol=1) B1 <- matrix(c(A1, A2, A3), nrow=5, ncol=3) B2 <- matrix(c(A2, A3, A4), nrow=5, ncol=3) B3 <- matrix(c(A3, A4, A5), nrow=5, ncol=3) C <- array(c(B1, B2, B3), dim = c(5,3,3)) D1 <- matrix(c(A1, A4, A5), nrow...

How can I do something like this: <a id=a7 style="cursor: pointer;" onClick = "new Effect.Fade (''li''); Element.show(''a1'',''a2'',''a3'',''a5'',''a6''); onClick = "new Effect.Fade (''rp''); Element.show(''a1'',''a2'',''a3'',''a5'',''a6'');"> Hide Images</a> Whenever I do this it doesn''t w...

...e output "a1", "a3" as the differing information). The overall purpose would be to remove "a1" and "a3" from dat 1 so both dat1 and dat2 are the same. My R abilities are somewhat limited so any suggestions are greatly appreciated. Alysta dat1 a1 a2 a3 a4 a5 a6 dat2 a2 a4 a5 a6

...On newer machines running Samba 4.5 (Debian Stretch) tdbdump gives an encrypted password such as this: \EE\A9\8D\EF\AD\AC\E2\A1\9D\E2\A0\8C\E3\96\8E\E7\B0\A8\EE\97\AA\E2\8E\9F\E2\A2\8F\EB\85\BF\EE\B7\8B\EA\A7\A9\EA\97\B8\D2\86\E6\83\AB\EE\82\AA\E3\A9\BB\E3\8A\8D\E2\86\9B\E2\8C\92\E6\8C\A6\EA\85\A5\E6\8F\82\EF\96\94\EF\9C\82\E7\8D\B3\E7\8F\93\E7\B8\AA\E7\A7\B7\EE\88\96\E2\A3\9B\EB\AA\B0\E6\B6\A7\EF\B6\B7\EA\A2\AD\EF\A8\88\EA\BB\B6\EE\A4\9A\E3\99\A6\EE\93\96\E2\BD\84\EB\95\93\E3\87\A2\E2\9D\98\EE\BE\8A\E6\8F\A2\EF\AE\91\EB\B5\AA\E7\A5\AF\E7\A4\A6\CD\A5\EF\80\9A\E3\AC\A9\E6\95\9E\E3\A9\BE\EE\94...

Hello I have a data set like below: plate.id well.id Group HYB rlt1 1 P1 A1 Control SKOV3hyb 0.190 2 P1 A2 Control SKOV3hyb 0.210 3 P1 A3 Control SKOV3hyb 0.205 4 P1 A4 Control SKOV3hyb 0.206 5 P1 A5 Control SKOV3hyb 0.184 385 P1 A1 ovca SKOV3hyb 0.184 386 P1 A2 ovca SKOV3hyb 0.229 387 P1 A3 ovca SKOV3hyb 0.214 388 P1 A4 ovca SKOV3hyb 0.226 389 P1 A5 ovca SKOV3hyb 0.217 390 P1 A6 ovca SKOV3hyb 0.207 each plate...

...94F30 UNDI data segment size: 9750 UNDI code segment at: 0009E680 UNDI code segment size: 1706 PXE entry point found (we hope) at 9E68:00F6 My IP address seems to be C0A80117 192.168.1.23 ip=192.168.1.23:0.0.0.0:192.168.1.1:255.255.255.0 TFTP prefix: Trying to load: pxelinux.cfg/01-00-40-63-ca-68-a5 192.168.1.23 is the preferred ip address for this machine. 192.168.1.93 is the dhcp/tftp server. 192.168.1.1 is the router/firewall. I tried tftpd-hpa and atftpd. I used atftpd some time ago (with the exact same pxelinux/debian-installer files), but now this fails. On my dhcp/tftp server i have...

...ear Rxperts, is there way to identify intervals from continuous data (having some kind of a pattern) and then pick the value of most frequency? a1 <- round(rnorm(50,mean=0,0.1),2) a2 <- round(rnorm(50,mean=1,0.2),1) a3 <- round(rnorm(50,mean=5,1),0) a4 <- round(rnorm(50,mean=14,4),0) a5 <- round(rnorm(50,mean=30,8),0) b1 <- rbind(a1,a2,a3,a4,a5) hist(b1,brea=100) # shows intervals and values with varying frequency. unlike the mean values of a1.... a5 above, I don't know the nominal values. I would like an algorithm to identify intervals and pick the value with most fr...

...:30 a1 > 2568307 -rw-rw-r-- 3 mbp mbp 29 Mar 25 17:30 a2 > 2568307 -rw-rw-r-- 3 mbp mbp 29 Mar 25 17:30 a3 > 2568310 -rw-rw-r-- 5 mbp mbp 29 Mar 25 17:30 a4 > 2568310 -rw-rw-r-- 5 mbp mbp 29 Mar 25 17:30 a5 > 2568310 -rw-rw-r-- 5 mbp mbp 29 Mar 25 17:30 b1 > 2568310 -rw-rw-r-- 5 mbp mbp 29 Mar 25 17:30 b2 > 2568310 -rw-rw-r-- 5 mbp mbp 29 Mar 25 17:30 b3 > > /tmp/b: > total 32 > 2568309 -rw-rw-r-- 3 mbp...

[This email is either empty or too large to be displayed at this time]

Hi, How do I rename the column labels in the table? For Instance, if I have a table like this, and I want to have the column labels changed from "A1 A2 A3 A4 A5" to "Mike Kate Michelle Paul Young" A1 A2 A3 A4 A5 1 33 44 55 66 77 2 3 4 5 6 7 7 8 9 and my text file location is: ""/Users/MAC/Desktop/data.txt" When I type in colnames(data.txt)[1] <- "Income", I get an error mess...

...pose we have a list of arrays. a1=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a1=array(a1,dim=c(4,4)); a2=c(4,4,4,4,0,4,4,4,0,3,3,0,0,0,0,0); a2=array(a2,dim=c(4,4)); a3=c(4,4,4,4,0,3,3,4,0,4,4,0,0,0,0,0); a3=array(a3,dim=c(4,4)); a4=c(4,4,4,4,4,0,3,3,3,3,0,4,4,4,0,0,0,0,0,0); a4=array(a4,dim=c(5,4)); a5=c(4,4,4,4,4,0,4,4,4,4,0,3,3,3,0,0,1,1,0,0); a5=array(a5,dim=c(5,4)); a6=c(4,4,4,4,4,0,1,1,1,1,0,4,4,4,0,0,3,3,0,0); a6=array(a6,dim=c(5,4)); a7=c(1,1,1,1,1,0,4,4,4,4,0,3,3,3,0,0,4,4,0,0); a7=array(a7,dim=c(5,4)); a8=c(4,4,4,4,4,0,3,3,3,3,0,1,1,1,0,0,4,4,0,0); a8=array(a8,dim=c(5,4)); l=list(a1,a2,a...

...ines running Samba 4.5 (Debian Stretch) tdbdump gives an encrypted password such as this: > > > \EE\A9\8D\EF\AD\AC\E2\A1\9D\E2\A0\8C\E3\96\8E\E7\B0\A8\EE\97\AA\E2\8E\9F\E2\A2\8F\EB\85\BF\EE\B7\8B\EA\A7\A9\EA\97\B8\D2\86\E6\83\AB\EE\82\AA\E3\A9\BB\E3\8A\8D\E2\86\9B\E2\8C\92\E6\8C\A6\EA\85\A5\E6\8F\82\EF\96\94\EF\9C\82\E7\8D\B3\E7\8F\93\E7\B8\AA\E7\A7\B7\EE\88\96\E2\A3\9B\EB\AA\B0\E6\B6\A7\EF\B6\B7\EA\A2\AD\EF\A8\88\EA\BB\B6\EE\A4\9A\E3\99\A6\EE\93\96\E2\BD\84\EB\95\93\E3\87\A2\E2\9D\98\EE\BE\8A\E6\8F\A2\EF\AE\91\EB\B5\AA\E7\A5\AF\E7\A4\A6\CD\A5\EF\80\9A\E3\AC\A9\E6\95\9E\E3\A9\BE\EE\94...

Hi Guys, I want to create multiple virtual interfaces on a system running linux 2.6. The main requirment being, to assign unique MAC address fo each of the virtual interfaces. I need to know, if this is possible and will really appriciate if someone can provide me pointer in this direction. Thanks a lot. R. Singh _______________________________________________ LARTC mailing list

..., "C", "A", "B", "C", "A", "A", "B", "C", "C") code <- c("a1", "a2", "a2", "a3", "a3", "a3", "a4", "a4", "a4", "a5", "a5", "a6") dat <- data.frame(id=1:12, sp=sp, tr=tr, val=31:42, code=code) and below is what I'd like to obtain. That is, I'd like the tr variable in different columns (as a timevar) with their value (val). sp code tr.A tr.B tr.C a a1 31 NA NA...

...1-d-es-c7s2 (476142:000001) MTRACER num: 007, time: 2009/10/30 11:53:02, loss: 0% ______________________________________________________________________________ | (476157:000002) 1095: Send_IO1 (link-nbr=19, sapi=0, tei=0) : | long: 51 desti: 0 source: 15 cryst: 0 cpl: 19 us: 8 term: 0 type a5 | tei: 0 <<<< message sent : SETUP [05] Call ref : 32 a8 |______________________________________________________________________________ | | IE:[04] BEARER_CAPABILITY (l=3) 80 90 a3 | IE:[18] CHANNEL (l=3) a9 83 9b -> T2 : B channel 27 exclusive | IE:[1e] PROGRESS_ID (l=2) 80...

Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20080804/8b871b75/attachment.pl>

...ng from the estimates reported in JMP. What can I do? Full story: I am collaborating on a project which presently requires the fit of a seven parameter non-linear function to 874 observations. The function is: freeze.d <- deriv3(~ dbh^b * u^dbh * a1 * smi^a2 * exp(a3*pbal) * (1 + a4*exp(a5*ba)) * cr^a6 * dh5^a7, c("a1","a2","a3","a4","a5","a6","a7","b","u"), function(dbh, smi, pbal, ba, cr, dh5, a1, a2, a3, a4, a5, a6, a7, b, u){}) The dbh, smi, pbal, ba, cr, and dh5, are known. The data d...