Displaying 2 results from an estimated 2 matches for "a35641".
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135641
2006 Apr 17
1
Function for computing the difference between 2 dates in months
Folks:
With the help of David L. Reiner, I've developed a function that
computes the number of months between 2 dates, x and y.
num.months <- function ( x , y )
{
x <- as.Date( x )
y <- as.Date( y )
seeq <- seq(from=x , to=y , by="months")
ans <- length( seeq ) - 1
if ( max( seeq) > y ) ans <- ans -1
ans
}
To ease your reading this function, I've
2006 Apr 19
0
Function for computing the difference between 2 dates inmonths
...ws:
date1<-sub(' - -
','',paste(substring(ie[,],257,260),substring(ie[,],255,256),substring(ie[,]
,253,254),sep="-"))
Your functions works well only in example #1 but when I applied a "cycle"
(if clause) doesn't work (example #2 and #3).
Example #1:
a35641<-num.months (dados$date1[35641],dados$date2[35641])
[1] 68
Example #2:
mes1<-with(dados,ifelse(date1!=" - - ",num.months(date1,date2),""))
>Error in fromchar(x) : character string is not in a standard unambiguous
format
Example #3:
mes<-c(rep("NA",le...