Displaying 3 results from an estimated 3 matches for "a2_b2".
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a1_b2
2010 Aug 23
3
extracting p-values from Anova objects (from the car library)
...object
from the car library? I can't seem to locate the p-values using
str(result) or str(summary(result)) in the example below
> A <- factor( rep(1:2,each=3) )
> B <- factor( rep(1:3,times=2) )
> idata <- data.frame(A,B)
> fit <- lm( cbind(a1_b1,a1_b2,a1_b3,a2_b1,a2_b2,a2_b3) ? sex,
data=Data.wide)
> result <- Anova(fit, type="III", test="Wilks", idata=idata, idesign=?A*B)
Any help would be much appreciated!
Many thanks,
Johan
2010 Aug 24
0
mlm for within subject design
...Anova object
from the car library? I can't seem to locate the p-values using
str(result) or str(summary(result)) in the example below
> A <- factor( rep(1:2,each=3) )
> B <- factor( rep(1:3,times=2) )
> idata <- data.frame(A,B)
> fit <- lm( cbind(a1_b1,a1_b2,a1_b3,a2_b1,a2_b2,a2_b3) ? sex,
data=Data.wide)
> result <- Anova(fit, type="III", test="Wilks", idata=idata, idesign=?A*B)
Any help would be much appreciated!
Many thanks,
Johan
--Forwarded Message Attachment--
From: ggrothendieck at gmail.com
CC: r-help at r-project.org
To: f.ver...
2012 May 04
1
Generate strings from multiple variables
Hi,
it is easiest to explain what I want to do by an example:
lets assume there are two factors/variables:
A <- c(1,2,3)
B <- c(1,3,3)
Now I would like to generate a list of strings that should look like
("A1_B1","A1_B2","A2_B1","A2_B2"). So actually the string
contains all possible combinations of A and B (separated by _). This should
be also possible for more variables. Is there simple way
to that? I thought about looping over A and B (nested for-loop)
but maybe there is a straight foward solution to get such strings.
/jo...