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...because abs(0.1) > 0.01. Irrespective of the documentation, the above example should continue to produce what it does now. These numbers are not close to zero (compared to tol), and so relative error should be used. The whole idea of all.equal.numeric() is to use *relative* error/difference __unless__ that is not sensible anymore, namely when the denominator of the ratio which defines the relative error becomes too close to zero (and hence has to be seen as "unstable" / "unreliable"). The exact behavior of all.equal.numeric() has __ I'm pretty sure, but can no longer eas...

Dear all, The documentation for `all.equal.numeric` says Numerical comparisons for ?scale = NULL? (the default) are done by first computing the mean absolute difference of the two numerical vectors. If this is smaller than ?tolerance? or not finite, absolute differences are used, otherwise relative differences scaled by the mean absolute difference. But the actual behaviour