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I have x, y, z data. The x, y fields dont change but Z does. How do I add a very small number onto the end of each x, y data point. For example: Original (X) Original (Y) Original (Z) 15 20 30 15 20 40 New (X) New (Y)

...M, your list maintainer] I am digging in the wrong hole I guess. Where can I find R /S routines for spatial statistics? Also has anyone made an R link to a GIS package? Anyone out there who works in this area? Thanks Richard E. Hoskins WA State Department of Health 1102 Quince Street Olympia, WA 98504-7812 richard.hoskins at doh.wa.gov tel: (360) 236 - 4270 fax: (360) 236 - 4245 GMT -8 Note: All messages to and from the Department of Health may be disclosed to the public. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci....

I looked at the documentation of source() and summary(), and I could not find the reason why calling something like: > summary(resamps) from the command line, works (it prints the summary) whereas calling summary(resampls) from a file that I source with source("my_file.r") does not print anything. How can I get summary(resamps) to print when I source a file with this command?

This may be a really obvious question but I just can't figure out how to do it. I have a small dataset that I am trying to compare to some controls. It is essential that the controls are matched on Cancer Stage (a numerical factor between 1 and 4), and then ideally on Age (integer), Gender (factor), Performance Status(factor). I'm using matchit to try and do this, but it seems to give

...ng the following call source(‘c:/tmp/test_source.R’, print.eval=TRUE) The summary information and dotplot printed just fine. Dan Daniel J. Nordlund Washington State Department of Social and Health Services Planning, Performance, and Accountability Research and Data Analysis Division Olympia, WA 98504-5204 From: James Jong [mailto:ribonucleico@gmail.com] Sent: Thursday, February 07, 2013 1:48 PM To: Nordlund, Dan (DSHS/RDA) Subject: Re: [R] Sourcing my file does not print command outputs Thanks Dan, Here is a minimal full example, where dotplot fails to print anything if I source the file. I...

...t it must be too late on Friday for my brain and caffeine isn't helping. TIA for a hint, Clint -- Clint Bowman INTERNET: clint at ecy.wa.gov Air Quality Modeler INTERNET: clint at math.utah.edu Department of Ecology VOICE: (360) 407-6815 PO Box 47600 FAX: (360) 407-7534 Olympia, WA 98504-7600

Dear all,   I have the following written example > coords <- "51°30'48.58\"N" > > as.integer(strsplit(coords, "°")[[1]][1]) [1] 51 > as.integer(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][1]) [1] 30 > as.numeric(strsplit(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][2],

Does anyone have information about using the National Practitioner Data Bank (NPDB) in R? It's public use data available from the U.S. Department of Health and Human Services that can be downloaded as a .dat or .por file. I can't even figure out how to open the file in R. [[alternative HTML version deleted]]

Hello there, would you please look into my codes? Here I have following: > set.seed(100) > samp <- sample(c(1,-1,0), 20, replace=T); samp [1] 1 1 -1 1 -1 -1 0 -1 -1 1 -1 0 1 -1 0 0 1 -1 -1 0 Here I want to calculate the length of each unique number for above vector. How can I do that? Thanks in advance [[alternative HTML version deleted]]

I'm trying to plot smooth trend using smoothTrend in OpenAir but I'm having problems. I used the following code. --------------------------------------------------------------------------------- #Set my working dir to the dir with my files setwd("c:/R") #Load the openair library library(openair) #Load the data mydata <- read.table("MCNP-pH.csv", header=TRUE,

I have a matrix where one column has a date and another column has a time. I need to delete all times before 6am. I had combined the Date and Time column into DateTime. Mat1: Weight Date Time 7.6 04/28/11 09:03 8.4 04/29/11 03:11 8.6 04/29/11 05:32 8.6 04/29/11 09:53 1.4 05/01/11 19:52 I tried just picking up the time: as.POSIXct(Mat1$Time, format = "%H:%M") but

Hi all, I have a list of numbers, e.g., X = c(60593.23, 71631.17, 75320.1), and want to round them so the output is Y = c(60000, 80000, 80000). I tried Y<-round(X,-4), but it gives me Y = c(60000, 70000, 80000). Do anybody know how to round up a number to 10^4? Thank you in advance. Wendy -- View this message in context:

Hi all, I've simple code to read a file (verify.txt in the same directory as the script file) but when I run this I get "Error in eval(expr, envir, enclos) : object "y" not found". data_model.df = read.table("./verify.txt", header=TRUE, nrows=10); f <- lm(y ~ x) Could someone pls tell me what's wrong with this code? Sincere thanks!

Hi, I am trying to compile a FORTRAN program to call from R under Windows 7 but I am having problem in the compiling step. To demonstrate this is the program testit.f: ------------------------------------------ subroutine TESTIT(x,n,m) dimension x(n) do 10 i=1,n 10 x(i)=x(i)**m end -------------------------------------------- When I compile it with gfortran I get

Hi, I need to do some analysis on historic daily radiosonde data I download from the Wyoming Univ. web page ( http://weather.uwyo.edu/upperair/sounding.html). I am trying to use the RadioSonde package (V 1.3), but the format of the files from Wyoming don't match what RadioSonde is expecting. Has anyone used the Radiosonde package on the Wyoming data? Here is a sample of the Wyoming file

Hello I have a huge file (not an R-file) in which the first column is a string with date, hour, minutes and seconds (For instance, "31-Jul-2010 23:59:00"). I tried as.Date but the error msg was "Error in charToDate(x) : character string is not in a standard unambiguous format". I have checked the help for the function as well as date but to no avail. How can that sort

Hello everyone I have a dataframe with 4 colums (year, month, day, runoff) for 1993-2009. Now I like to calculate the average runoff for each day. Finally I like to plot the median runoff for all this years. I tried with some loops, but it didn't work. Do you have any Tips for my problem? Any help is greatly appreciated! Thank you very much. Dominique -- View this message in context:

Folks: I thought the following excerpt from Bruce McCullough's post would be a good candidate for the R fortunes package -- except that it's about Excel, not R! So I nominate it... but leave it to others to say whether it's really "qualified" to be nominated. ---- "The idea that the Excel solver "has a good reputation for being fast and accurate" does not

Dear R Experts: I am trying to convert a date and time character field to timeDate where the month is presented as three letters, such as "JUN" for June, etc. This is an example of the full character field: "04-MAY-11 1428" What is the proper format syntax? I've tried timeDate("04-MAY-11 1428",format="%d-%m-%y %H%M") but only get GMT [1]

Suppose x and y are numeric vectors of the same length. plot(x,y) #scatterplot lmObj1 <- lm(y~x) # best fit line abline(lmObj1) # good lmObj2 <- lm(x~y) #get best fit but with axes interchanged abline(lmObj2) # not what I want. I want the correct line, drawn on the same graph, but with # response and predictor variables interchanged One way to proceed would be to