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On Nov 28, 2010, at 3:47 PM, John McCall wrote: > So mem2reg would have to split %try and make a phi in %lp, like so: > > try1: unwinds to %lp > %count = load i32* @count > br label %try2 > try2: unwinds to %lp > call void foo() > br label %return > lp: > %t = phi i32 [ i32 0, label %try1 ], [ i32 %count, label %try2 ] > #etc. > > That's a lot of

On Nov 28, 2010, at 1:57 PM, Bill Wendling wrote: > On Nov 28, 2010, at 2:59 AM, John McCall wrote: > >> On Nov 28, 2010, at 2:20 AM, Bill Wendling wrote: >> >>> On Nov 27, 2010, at 4:57 PM, John McCall wrote: >>> >>>> On Nov 25, 2010, at 3:03 AM, Duncan Sands wrote: >>>>> I'm pointing out that if the invoke instruction