search for: 9390

Hi all, here is my situation In my experiment, I expose 10 subjects to 24 different conditions of stimuli. Each condition is exposed to the same subject 3x. This would make each subject have 24x3=72 data points. All the subjects combined would have 72x10=720 data points with each condition having 30 datapoints. To find the grand average of each condition, I find the average of all the

Hi All, I am interested in aggregating a data frame based on 2 categories--mean effect size (r) for each 'id's' 'mod1'. The 'with' function works well when aggregating on one category (e.g., based on 'id' below) but doesnt work if I try 2 categories. How can this be accomplished? # sample data id<-c(1,1,1,rep(4:12)) n<-c(10,20,13,22,28,12,12,36,19,12,

Dear all, I read a file with all numbers with readLines function, as below, > f <- file("data.txt") > a <- readLines(f) but all the values in a are in format "....", and I cannot do the calculation with them since they are not numeric. I wonder how should I skip those quotes, thank you for help! I have to use readLines function instead of scan, read.table or

This message is in MIME format. The first part should be readable text, while the remaining parts are likely unreadable without MIME-aware tools. --27464147-1968795515-1164715405=:5670 Content-Type: TEXT/PLAIN; charset=iso-8859-1; format=flowed Content-Transfer-Encoding: 8BIT You need to re-install packages when you update R, as it says in the rw-FAQ. Use update.packages(checkBuilt=TRUE) to

...>>> PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >>> >> >> >> >> -- >> Jim Holtman >> Cincinnati, OH >> +1 513 646 9390 >> >> What is the problem that you are trying to solve? >> >> >> >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help at r-project.org mailing list >> https://stat.ethz.ch/m...

Hi all, I wonder if there is a way to create a matrix with two (or even more) column/row names? Thank you very much. Have a nice day. -- ??? Hesen Peng http://hesen.peng.googlepages.com/

Dear all, does anybody ever encountered the problem with diagnostic plots? x<-rnorm(100) y<-rnorm(100) plot(lm(x~y)) It gives the following message "Waiting to confirm page change..." and nothing happens. Thanks a lot! [[alternative HTML version deleted]]

...This is is the latest stable release of Samba 3.6. Major enhancements in Samba 3.6.10 include: o Respond correctly to FILE_STREAM_INFO requests (bug #9460). o Fix segfault when "default devmode" is disabled (bug #9433). o Fix segfaults in "log level = 10" on Solaris (bug #9390). Changes since 3.6.9: -------------------- o Jeremy Allison <jra at samba.org> * BUG 9236: ACL masks incorrectly applied when setting ACLs. * BUG 9374: Allow smb2.acls torture test to pass against smbd with a POSIX ACLs backend. o Bj?rn Baumbach <bb at sernet.de>...

...This is is the latest stable release of Samba 3.6. Major enhancements in Samba 3.6.10 include: o Respond correctly to FILE_STREAM_INFO requests (bug #9460). o Fix segfault when "default devmode" is disabled (bug #9433). o Fix segfaults in "log level = 10" on Solaris (bug #9390). Changes since 3.6.9: -------------------- o Jeremy Allison <jra at samba.org> * BUG 9236: ACL masks incorrectly applied when setting ACLs. * BUG 9374: Allow smb2.acls torture test to pass against smbd with a POSIX ACLs backend. o Bj?rn Baumbach <bb at sernet.de>...

Hi, I have a dataframe SDF1 that looks like this: Char1 Char2 Char 3 W.2007.02 W.2007.09 W.2007.16 W.2008.13 A C1 F1 F2 F3 A C2 F4 B C3 F5 F6 I have another dataframe SDF2 with 163 cols that has the following column names Char1 Char2 Char 3 W.2007.02 W.2007.03 W.2007.04

Hi everyone! #I need a loop or a function that creates a X2 variable that is X1 without the extreme values (or X1 winsorized) by industry and year. #My reproducible example: firm<-sort(rep(1:1000,10),decreasing=F) year<-rep(1998:2007,1000) industry<-rep(c(rep(1,10),rep(2,10),rep(3,10),rep(4,10),rep(5,10),rep(6,10),rep(7,10),rep(8,10),rep(9,10), rep(10,10)),1000) X1<-rnorm(10000)

Hi, How can I extract the label only from a given data frame. Fore example from this data frame. > print(dataf) V1 V2 V3 V4 V5 V6 V7 V8 V9 11145 14.3 17.1 31.2 41.7 45.8 49.8 68.6 70.6 72.9 3545 10.2 15.6 20.9 23.2 31.4 31.7 36.2 48.4 51.9 8951 15.2 17.5 20.0 21.4 32.4

Hi All, What is the R function for computing multinomial distribution, e.g. f(2,1,3; 2/9, 1/6, 11/18, 6)? That is, a total of 6 trials, event 1's p1=2/9, x1=2, event 2's p2=1/6, x2=1, and event 3's p3=11/18, x3=3. thanks, Johnny [[alternative HTML version deleted]]

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#Dear R users, #I want six interaction plots to be on one page, #but the following problem occurs: the legend "BMIakt" appears, #but it is exactly on the border of the plots (too far right). #My seccond question is, how I can reduce the empty space in the y-direction #between the plots. #Please have a look at my syntax below. #Many thanks! #Udo myData <-

Hello, it might be a very simple question but I cannot find the solution (I tried a || b, any(a,b)... but none works). My problem is: I have two vectors, a <- c(TRUE,FALSE,FALSE) b <- c(TRUE,FALSE,TRUE) and I would like to obtain a vector that indicates if it is TRUE in any of the two vectors. Hence, the desired output would be: TRUE, FALSE, TRUE Thank you in advance, Federico

...ariables: $ county: Factor w/ 3 levels "Broome","Nassau",..: 3 3 3 3 3 3 3 3 3 3 ... $ item : Factor w/ 28 levels "Access to healthy foods",..: 21 19 20 18 16 3 2 6 17 8 ... $ value : num 8644 15 3.5 3.9 7.7 ... $ low : num 7897 9 2.5 2.6 7 ... $ high : num 9390 22 4.5 5.2 8.4 37 30 23 24 101 ... $ target: num 5034 11 2.7 2.6 6.1 ... $ nys : num 6099 16 3.5 3.3 8 ... > head(chr) county item value low high target nys 1 Sullivan Premature death 8644.0 7897.0 9390.0 5034.0 6099.0 2 Sullivan Poor or f...

Hi, When I run the repeat loop in R for large dataset, I got Memory problem. How can I solve these problem. -- View this message in context: http://n4.nabble.com/Memory-Problem-tp1459740p1459740.html Sent from the R help mailing list archive at Nabble.com.

Dear All, to my surprise as.factor does not accept a levels argument. Maybe I did not read the documentation well enough. See the example below. I wanted to use ch1 as factor in the newdata argument of survfit, so I assumed that I could write as.factor(ch1, levels=ch1), since the order should be kept. But as.factor(ch1, levels=ch1) results in the error: Error in as.factor(ch1, levels = ch1)

Hi, I'm fairly new to R but I have a large dataset (300000 obs) containing patient material. Some patients came 2-9 times during the three year observation period. The patients are identified by a unique idnr, the sessions can be distinguished using the session date. How can I recode the date of the session to a session id (1-9). This would be necessary to obtain information and do some