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...t prime factor. This is trivially easy on a CentOS system (factor is part of coreutils): [lowen at FREE-IP-92 ~]$ factor 6268927 6268927: 7 43 59 353 So you could use 512 times any of these factors, or several of these factors. I would probably use the line: dd if=/dev/sdb of=cubietruck.img bs=9092608 count=353 Note that while dd can use the abbreviation 'k' you would not want to use that here since 2 is not one of the factors of your count. A roughly 9MB blocksize is going to be loads faster than 512, but still manageable. Or you could make it easy on yourself and use either dd_res...

I am building a mailserver and with all the steps, I want to image the drive at various 'checkpoints' so I can go back and redo from a particular point. The image is currently only 4GB on a 120GB drive. Fdisk reports: Disk /dev/sdb: 111.8 GiB, 120034124288 bytes, 234441649 sectors Units: sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size