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On 12/11/13 12:40 PM, Owen Anderson wrote: > > On Dec 11, 2013, at 12:33 PM, Tim Northover <t.p.northover at gmail.com > <mailto:t.p.northover at gmail.com>> wrote: > >> On 11 December 2013 20:25, Raoux, Thomas F <thomas.f.raoux at intel.com >> <mailto:thomas.f.raoux at intel.com>> wrote: >>> Well in IEEE-754 Nan + any value returns Nan,

On Dec 11, 2013, at 12:33 PM, Tim Northover <t.p.northover at gmail.com> wrote: > On 11 December 2013 20:25, Raoux, Thomas F <thomas.f.raoux at intel.com> wrote: >> Well in IEEE-754 Nan + any value returns Nan, so doing Nan + undef -> undef is wrong. > > I see what you mean having re-read the language reference. It looks > like LLVM's "undef" has to

...case for NaN + undef == NaN: while the compiler is free to choose any value for the undef, there is no such value for which the result is not NaN. —Owen -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20131212/746c716f/attachment.html>