search for: 7,3

Hi list, I'd like to make a factor with seven 1s and three 2s using the factor() function. That is, 1 1 1 1 1 1 1 2 2 2 I will then bind this factor to the matrix below using cbind.data.frame(). 0.56 0.48 0.22 0.59 0.32 0.64 0.26 0.60 0.25 0.38 0.24 0.45 0.56 0.67 0.78 0.97 0.87 0.79 0.82 0.85 I am new to R and have been using various manuals and have made many attempts without success any help appreciated. thanks, Simon

...was convenient. -Adam | -----Original Message----- | From: Simon Gao [mailto:gao@schrodinger.com] | Sent: Thursday, October 05, 2006 11:22 AM | To: Adam Crews -X (acrews - Xerox at Cisco) | Cc: xen-users@lists.xensource.com; Mike Freemon | Subject: Re: [Xen-users] Installing Redhat 7,3 with hvm | | Adam, | | That''s good to know. Have you tried to grab a disk image | from standalone | installation of rh7.3? | | Simon | | | Adam Crews -X (acrews - Xerox at Cisco) wrote: | > If anyone is still interested in this old thread, I have | a r...

Hi, I am trying to specify four ticks (at 0,1,2,3 for the y axis) in a persp plot but the defaults overrule my specification and I obtain seven of them. Is it possible to gain full control over them in such a plot? Here is my code: matlines=matrix(c(1:7,3:9,3:9,2:8),nrow=7,ncol=4) persp(x=seq(1,7,1),y=seq(0,3,1),z=matlines,theta=-30,phi=25,zlim=c(0,10),d=5,ticktype="detailed",xlab="x", ylab="y",zlab="z") [[alternative HTML version deleted]]

If anyone is still interested in this old thread, I have a rh7.3 image running under hvm. It''s a hack, but here''s what I did: Install rh7.3 in a vmware machine with vmware server. Booted off a live cd, ( I used a gentoo installer CD, but any live cd should work) Created a lvm volume on my Xen dom0 >From the liveCD, I use dd to copy the d...

...ed zeros when prey types are absent from a stomach instead of NAs, a problem for which I only have a shaky solution at the moment: 1) creation of a dummy dataset: ####### nbpc <- rep(c(20,34), c(110,90)) trip <- c(rep(1:3, c(40, 40, 30)), rep(1:2, c(60,30))) set <- c(rep(1:4, c(10, 8, 7, 15)), rep(c(10,12), c(25,15)), rep(1:3, rep(10,3)), rep(10:12, c(20, 10, 30)), rep(7:8, rep(15,2))) depth <- c(rep(c(100, 150, 200, 250), c(10, 8, 7, 15)), rep(c (100,120), c(25,15)), rep(c(75, 50, 200), rep(10,3)), rep(c(200, 150, 50), c(20, 10, 30)), rep(c(100, 250), re...

...in R. I have two multidimensional independent variables X and Z and I know their densities fx and fz, which are multidimensional arrays. So I have to find the density of Y, such that X+Y=Z. So, first I tried on a simple example, where the variables are one-dimensional, say X is N(0,1) and Z is N(7,3). So I want to find the density of Y (which should be N(7, sqrt(8)). I did: x <- seq(-6, 20, length=500) fx <- dnorm(x) z <- seq(-6, 20, length=500) fz <- dnorm(z, mean=7, sd=3) ffty <- fft(fz)/fft(fx) fy <- fft(ffty, inverse=T)/length(ffty) plot(Re(fy)) But the plot is far fro...

On 2/19/20 7:56 PM, Jason Wang wrote: > diff --git a/drivers/virtio/vdpa/Kconfig b/drivers/virtio/vdpa/Kconfig > index 7a99170e6c30..e3656b722654 100644 > --- a/drivers/virtio/vdpa/Kconfig > +++ b/drivers/virtio/vdpa/Kconfig > @@ -7,3 +7,21 @@ config VDPA > datapath which complies w...

Dear R users, I cannot display ylab with the following code while trying to stack 7 rows of 3 histograms each. Thanks in advance! par(mfrow=c(7,3)) par(mar=c(2,2,2,2)) par(oma=c(5,5,0,0)) with (newdata <- subset(table, Month1 == "1"), hist(newdata$CarapWid, breaks=5*(0:80), col="gray80", main="All individuals", xlab="", xlim =c(15,85),...

Hey, this is happening to anyone who I try this with. We get into the DISA, then hear the dial tone. Dial 1 then start dialing the number, and it hangs up. I thought adding a wait time after the DISA may help, I was wrong. Here is what I have thus far in the DISA extentions. [DISA] exten => 7,1,DISA(no-password||"Scheda" <565> 455-1337) exten => 7,2,Wait(45) exten => 7,3,Goto(8667393960,3) I don't see why it hangs up. Any suggestions?

Looking further into this segfault at settings-parser.c:setting_copy():1519 *dest_size = *src_size; *src_size points to type size_t (typedef unsigned long), a 4-byte aligned value consistent with a 32-bit build. This is mismatched with declared type (gdb) whatis src_size type = const uoff_t * (gdb) whatis uoff_t type = unsigned long long (gdb) p sizeof(uoff_t) $1 = 8 resulting

...insteps. The results where quite different, though. I cannot figure out what went wrong and I do not know which result I can rely on. This is what I did in R library(mirt) #load(file="u3.RData") mirt<-mirt(as.data.frame(pcmdat),1,itemtype="graded",constrain=list(1,5,9,13,17,21,25)) # I was assuming that a GRM with constrained discrimination parameter would equal a PCM cf<-as.data.frame(unlist(coef(mirt))) md1<-cf[c(2,6,10,14,18,22,26),] md2<-cf[c(3,7,11,15,19,23,27),] md3<-cf[c(4,8,12,16,20,24,NA),] mirt<-as.data.frame(cbind(md1,md2,md3)) mirt[7,3]<-...

...ch variance term. To illustrate, here is a matrix for 2 students. The goal is for the correlation between the second variance term for student 1 to be perfectly correlated with the variance term for student 2. In other words, I need to plug in 64 at position (6,2) and (2,6), another 64 at position (7,3) and (3,7) and another 64 at positions (8,4) and (4,8). I'm having some difficulty conceptualizing how to construct this part of the matrix and would appreciate any thoughts. Thank you, Harold [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 0 0 0 0 0 0 0 0 [2,]...

This example, x<-1:10 y1<-x y2<-x+2 plot(x,y1,pch=21,ylim=range(c(y1,y2)),type="o",lty="solid",bg="white") points(x,y2,pch=22,type="o",lty="dashed",bg="white") legend(7,3,legend=c("y1","y2"),pch=c(21,22),lty=c("solid","dashed"),bg="white") works if I use pch = one of 21-25. But if I use pch= one of 0-6, it doesn't work: the line goes through the empty symbols (instead of the symbols appearing solid). I was ju...

...nd plot mean and confidence intervall for a set of data. This is the code that I am currently using: means <- sapply(data, mean, na.rm=TRUE) n <- sapply(data,length) stdev <- sqrt(sapply(data, var, na.rm=TRUE)) ciw <- qt(0.98, n) * stdev / sqrt(n) par(mgp=c(2,0.6,0), las=2, fin=c(7,3), mai=c(1,0.5,0.2,0.2), cex=0.8) plotCI(x=means, uiw=ciw, ylim=c(0,100), col="red",col.axis="black",add=F) The code works fine, just the results are not as expected. I compared the results that R calculates for my variable ciw and noticed differences compared to other calc...

Hi, It would be better if you provided the output of dput(dataset).? I am not sure about the structure of your dataset. Just from reading the data as is shown. dat1<- read.table(text=" separator,tissID >,>,2 ,2,1 ,6,5 ,11,13 >,>,4 ,4,9 ,6,2 ,7,3 ,21,1 ,23,58 ,25,9 ,26,4 >,>,11 ,1,12 >,>,21 ,4,1 ,11,3 ",sep=",",header=TRUE,stringsAsFactors=FALSE,row.names=NULL) indx<-which(grepl(">",dat1[,1])) indx1<-diff(c(indx,nrow(dat1)+1)) res1<-do.call(rbind,lapply(seq_along(indx),function(i) {x1<...

Am 2015-09-17 09:29, schrieb Pasi K?rkk?inen: > > Are you using nfs over UDP or TCP ? > TCP, but Network cant be the bottleneck, have tested it with iperf between bare metal/domU's and the nfs domU and it was perfectly fast... > > I don't think. > > > If you used NFS over...

...message (daytime) ;exten => s,5,Goto(s,4) exten => i,1,Playback(invalid) ; "That's not valid, try again" exten => i,2,Goto(s,4) exten => t,1,Playback(vm-goodbye) exten => t,2,Hangup exten => 2,1,Voicemail(u1000) exten => 5,1,Directory(VYStaff) exten => 7,1,ResponseTimeout(1) exten => 7,2,Voicemail(u70) <-LONG PAUSE COMES HERE exten => 7,3,Playback(vm-goodbye) exten => 7,4,Hangup Asterisk CLI output: -- Set Response Timeout to 1 -- Executing VoiceMail("Zap/1-1", "u70") in new stack == Parsing...

Hello, I want to plot 21 scatter plots in a 7*3 matrix on a single A4 page (using mfcol). Below is an example, which -by and large- looks very close to the desired result. But I do not get it to fill out the whole page. If I specify the a different page size, the plots still do not fill out the whole page. Anybody an idea what to do? Maybe adj...

...y data contains less than 5 items in a group (like in the example above), and the test statistics may not hold: > prop.test(c(9,0), c(111,10)) 2-sample test for equality of proportions with continuity correction data: c(9, 0) out of c(111, 10) X-squared = 0.0941, df = 1, p-value = 0.759 alternative hypothesis: two.sided 95 percent confidence interval: -0.02420252 0.18636468 sample estimates: prop 1 prop 2 0.08108108 0.00000000 Warning message: Chi-squared approximation may be incorrect in: prop.test(c(9, 0), c(111, 10)) Do you have suggestions for an alternativ...

...d some tests of OpenVPN and TINC performance on a Windows client. Specifically, I was looking at the performance of multiple simultaneous transfers and PING latency/packet loss during the transfer. **** Test method: - three simultaneous FTP downloads are started on the Windows computer (file size 7612995 bytes) - at the same time, the Linux computer pings the Windows computer to see the latency and packet loss of the tunnel during the transfer. - record the transfer times, packet loss and latency - repeat three times, calculate the average **** Test setup: Network: 10Mbps switched Ethernet...