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I have found a strange scoping problem in Sweave. The following Rnw file doesn't produce the same output in Sweave as it does if I produce an R file using Stangle and execute that: \documentclass[12pt]{article} \begin{document} <<R>>= election <- data.frame(A=1:3, B=9:7, C=rep(0,3)) partytotal <- rep(0, ncol(election)) for (i in 1:ncol(election)) { partytotal[i] <-

Hi I want to write a little function that takes a matrix X of size m-by-n, and a list L of length "m", whose elements are matrices all of which have the same number of columns but possibly a different number of rows. I then want to get a sort of dumbed-down kronecker product in which X[i,j] is replaced by X[i,j]*L[[j]] where L[[j]] is the j-th of the "m" matrices. For

...ank you in advance for your help, Regards, C. -- Cristina E. Ramalho PhD Candidate MSc in GIS Ecosystem Restoration & Intervention Ecology Research Group School of Plant Biology (M090) The University of Western Australia 35 Stirling Highway, Crawley WA 6009 Perth, Australia Phone: +61 (08) 6488 4655; Fax: +61 (08) 6488 7461 www.plants.uwa.edu.au/research/ecosystem_restoration --------------------------------------------------------------------------------------------------- [[alternative HTML version deleted]]

Hi look at the following session, in which I have a dataframe, and I want to extract the second row, without the first column. Everything works as expected until the last line, where I set the names of x to NULL, and get a non-desired object (I want c(4,3).). Three questions: (1) why is as.vector(a[2,-1]) not a vector? (2) How come setting names to NULL gives me bad weirdness? (3) Can I

..., and why this would be happening in a linux build, but not in windows. In both cases I'm using R 2.10.0. Cheers Pam Dr Pamela McCaskie Assistant Professor Centre for Genetic Epidemiology and Biostatistics M409 University of Western Australia Email: pam.mccaskie@uwa.edu.au Ph: 6488 6741 Fax: 6488 6750 [[alternative HTML version deleted]]

...ors. This I do not know how to do. What is the easiest way to do this in R from this analysis? Kind regards, Burak Pekin Burak Pekin Ecosystem Research Group School of Plant Biology (M090) University of Western Australia 35 Stirling Highway Crawley, WA 6009 Australia Ph: +61 08 6488 7923 Fax: +61 08 6488 1001 [[alternative HTML version deleted]]

...Thank you for your help in advance. Regards, C. ------------------------------------ Cristina Estima Ramalho PhD Candidate MSc in GIS Ecosystem Restoration Lab School of Plant Biology (M090) The University of Western Australia 35 Stirling Highway, Crawley WA 6009 Perth, Australia Phone: +61 (08) 6488 4655; Fax: +61 (08) 6488 7461 www.plants.uwa.edu.au/research/ecosystem_restoration --------------------------------------------------------------------------------- [[alternative HTML version deleted]]

I want to do the following: DEVw=500 DEVh=350 fname="my_plot" dev.print(file=fname, device=FOO, width=DEVw, height=DEVh, bg="transparent") How do I do this such that I can specify FOO to be one of several choices? (GDD, PNG, postscript, etc.) If I make FOO a character variable, then "dev.print" complains. I tried a simpled "substitute" but

What can I do? Thanks a lot! [[alternative HTML version deleted]]

I need to make a bunch of PDF files of histograms. I tried gatelist = unique(mdf$ArrivalGate) for( gate in gatelist) { outfile = paste("../", airport, "/", airport, "taxiHistogram", gate, ".pdf", sep="") pdf(file = outfile, width = 10, height=8, par(lwd=1)) title=paste("Taxi time for Arrival Gate", gate, "by

Dear all, seems that easy question but cannot find the function for that. How to get the elements of the minor diagonal of the matrix? Thanks a lot. [[alternative HTML version deleted]]

Hi, R users, Here is an example. k <- c(1,2,3,4,5) i <- c(0,1,3,2,1) if k=1, then j=0 from i if k=2, then j=0, 1 from i if k=3, then j=0, 1, 2, 3 from i if k=4, then j=0, 1, 2 from i if k=5, then j=0, 1 from i so i'd like to create a list like below. > list k j 1 1 0 2 2 0 3 2 1 4 3 0 5 3 1 6 3 2 7 3 3 8 4 0 9 4 1 10 4 2 11 5 0 12 5 1 I tried expand.grid, but I

Dear R community, I'm fitting a complex mixed-effects model that requires numerous iterations and function evaluations. I note that nlminb accepts a list of control parameters, including eval.max. Is there a way to change the default eval.max value for nlminb when it is being called from lme? Thanks for any thoughts, Andrew -- Andrew Robinson Department of Mathematics and Statistics

## While in R v. 2.3.1 (the mid-July patch for Windows) ## on a Windows XP machine, this call to order() works fine... order(1:10,decreasing = TRUE) ## [1] 10 9 8 7 6 5 4 3 2 1 ## ...however, the argument name 'decreasing' ## must be typed in toto (note the missing 'g' ## in the following): > order(1:10,decreasin = TRUE) ## Error in order(na.last, decreasing, ...) :

I want to know how to get trace of product of matrices **faster** when the matrices are really big. Unfortunately the matrices are not symmetric. If anybody know how to get the trace of it, please help me. An example is as below. n <- 2500 a <- matrix(rnorm(n*n),n,n) b <- matrix(rnorm(n*n),n,n) tr1 <- sum(diag(a %*% b)) tr2 <- sum(diag(a %*% b %*% a %*% b)) Thanks, Yongwan Chun

Hi, I've been trying to get this working for ages, but it causes R to hang. Here is my C code saved as test1.c # include <R.h> # include <Rmath.h> void test1 (double *x, double *result) { result[0] = rgamma(*x, 2.0); } This was compiled using R CMD SHLIB test1.c & loaded in R using: dyn.load("test1.dll") out <-

OK, my last question didn't get any replies so I am going to try and ask a different way. When I generate contrasts with contr.sum() for a 3 level categorical variable I get the 2 orthogonal contrasts: > contr.sum( c(1,2,3) ) [,1] [,2] 1 1 0 2 0 1 3 -1 -1 This provides the contrasts <1-3> and <2-3> as expected. But I also want it to create <1-2> (i.e.

Question: I installed R verison 2-12.0 on my Windows 7 (64 bit) PC. When I was installing it, it did not ask me anything about 32 vs. 64 bit. So, if I run R now - is it running as a 32-bit or a 64-bit? thank you! -- Dimitri Liakhovitski Ninah Consulting www.ninah.com

Hello! I am writing some functions and I repeatedly acces internal factor codes. I figured out that internal codes are 1:n where 1 represents 1st level, 2 2nd level etc. This is not documented and I wonder if this is on purpose and subject to change or would be a good idea to add this to documentation for factor? I can prepair a pacth if this is accepted. -- Lep pozdrav / With regards,

When a graph is saved as PostScript, the bounding box is often too big. A consequence is that when the graph is included in a LaTeX document, the spacing does not look good. Is this a recognized problem? Is someone working on it? Could I help? David