Displaying 2 results from an estimated 2 matches for "60be".
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10be
2013 Mar 09
4
Calculation with date
Hello again,
Let say I have an non-negative integer vector (which may be random):
Vec <- c(0, 13, 10, 4)
And I have a date:
> Date <- as.Date(Sys.time())
> Date
[1] "2013-03-09"
Using these 2 information, I want to get following date-vector:
New_Vec <- c("2013-03-01", "2014-04-01", "2014-01-01", "2013-07-01")
Basically the
2016 Nov 21
2
Winbind traffic not encrypted
...e537 e562 57ee a305 83b1 d39e b3ed a13e .7.bW..........>
0x0a20: eb00 39f1 cd18 3996 e397 d27b 0925 bad7 ..9...9....{.%..
0x0a30: b3a5 7640 58d3 ca93 c8aa f92c 0100 a6a2 ..v at X......,....
0x0a40: dbf9 2b2c 5cd3 960f 0777 05ea c9d0 1582 ..+,\....w......
0x0a50: 96eb a089 60be 351f ed2c 2297 fb99 ....`.5..,"...
16:37:05.534624 IP 192.168.56.32.389 > 192.168.56.33.49418: Flags [.],
ack 2745, win 267, options [nop,nop,TS val 5433975 ecr 5433975], length 0
0x0000: 4500 0034 5589 4000 4006 f3a8 c0a8 3820 E..4U. at .@.....8.
0x0010: c0a8 3821 0185 c10a 6f...