search for: 5954x899

...;, array R-help <r-help at r-project.org> Subject: Re: [R] How to visualise what code is processed within a for loop Hi Rui Thank you for your suggestion, I have tested the code suggested by you against that supplied by Don in terms of timing and results are very much aligned: to populate a 5954x899 0/1 matrix on my machine your procedure took 79 secs, while the one with ifelse employed 80 secs, hence unfortunately not really any significant time saved there. Nevertheless thank you for your contribution. Kind regards, Luca 2018-04-28 23:18 GMT+02:00 Rui Barradas <ruipbarradas at sapo.pt&l...

Hi Rui Thank you for your suggestion, I have tested the code suggested by you against that supplied by Don in terms of timing and results are very much aligned: to populate a 5954x899 0/1 matrix on my machine your procedure took 79 secs, while the one with ifelse employed 80 secs, hence unfortunately not really any significant time saved there. Nevertheless thank you for your contribution. Kind regards, Luca 2018-04-28 23:18 GMT+02:00 Rui Barradas <ruipbarradas at sapo.pt...

...e: [R] How to visualise what code is processed within a for > loop > > > > Hi Rui > > Thank you for your suggestion, > > > > I have tested the code suggested by you against that supplied by Don in > terms of timing and results are very much aligned: to populate a 5954x899 > 0/1 matrix on my machine your procedure took 79 secs, while the one with > ifelse employed 80 secs, hence unfortunately not really any significant > time saved there. > > Nevertheless thank you for your contribution. > > Kind regards, > > > > Luca > > > &...

I forgot to explain why my suggestion. The logical condition returns FALSE/TRUE that in R are coded as 0/1. So all you have to do is coerce to integer. This works because the ifelse will return a 1 or a 0 depending on the condition. Meaning exactly the same values. And is more efficient since ifelse creates both vectors, the true part and the false part, and then indexes those vectors in