Displaying 18 results from an estimated 18 matches for "5.00000".
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0.00000
2005 Nov 08
2
retrieve most abundant species by sample unit
Hi R-users:
[R 2.2 on OSX 10.4.3]
I have a (sparse) vegetation data frame with 500 rows (sampling
units) and 177 columns (plant species) where the data represent %
cover. I need to summarize the cover data by returning the names of
the most dominant and the second most dominant species per plot. I
reduced the data frame to omit cover below 5%; this is what it looks
like stacked. I have
2012 Feb 06
1
Simple lm/regression question
I am trying to use lm for a simple linear fit with weights. The results
I get from IDL (which I am more familiar with) seem correct and
intuitive, but the "lm" function in R gives outputs that seem strange to me.
Unweighted case:
> x<-1:4
> y<-(1:4)^2
> summary(lm(y~x))
Call:
lm(formula = y ~ x)
Residuals:
1 2 3 4
1 -1 -1 1
Coefficients:
2013 Mar 25
2
Ordering a matrix by row value in R2.15
fitz_ra wrote
> I know this is posted a lot, I've been through about 40 messages reading
> how to do this so let me apologize in advance because I can't get this
> operation to work unlike the many examples shown.
>
> I have a 2 row matrix
>> temp
> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
> [,9] [,10]
> [1,] 17.000
2007 Apr 11
3
Help with pexp( )
Dear all,
Sorry for bringing up an old issue:
>pexp(50, 0.5)
[1] 1
In some cases, pexp() gives CDF=1. I read some discussion in 2002 saying it
has been patched. However it's not working in "R2.4.1Patched". Could anyone
help me out?
Thanks a lot,
Jeann
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Fine Dining & Fancy Food. Check Out This
2003 Dec 15
3
Julian Dates
Hi,
I'm a bit confused how julian() works. If I understand right, it returns
the number of days since the origin.
I have a vector:
> SLDATX[1:10]
[1] "1986-01-06" "1986-01-17" "1986-02-02" "1986-02-04"
[5] "1986-02-04" "1986-02-21" "1986-03-06" "1986-03-25"
[9] "1986-04-06"
2020 Oct 23
2
The presence/absence of `zone` in POSIXlt depending on time zone as a cause of possible inconsistences?
Dear all,
I have just detected what seems a minor inconsistence with data types. If one unlists a POSIXlt time with GMT zone gets a numeric vector, since the POSIXlt list has no `zone` element, while if one unlists a POSIXlt time with a non GMT zone (also non specifying tz if the Sys.timezone is not GMT) gets a character vector due to including the `zone` element.
> x <-
2010 Feb 17
1
Replicating output from a function
Hi All,
I have a function that is used with data frames having multiple id's
per row and it aggregates the data down to 1 id per row. It also
randomly selects one of the within-id values of a variable (mod),
which often differ within-id. Assume this data frame (below) is much
larger and I want to repeat this function, say 100 times, and then
derive the mean values of r over those 100
2008 Aug 19
0
R-code: for those who like a challenge; HELP
I'll try to be more clear, but will have to give much more info. Here we go....
As part of my Masters in Public Health I writing a dissertation reviewing the mortality trend of internally displaced persons in camp settings in Sub Saharan Africa. I have 50 surveys with
- crude mortality rate (cmr), CMR lower confidence interval(cmrlci), CMR upper confidence interval(cmruci),
- recall period
2006 May 08
0
Inconsistency in AIC values for glm with family poisson (PR#8841)
This message is in MIME format. The first part should be readable text,
while the remaining parts are likely unreadable without MIME-aware tools.
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On Mon, 8 May 2006, x.sole at iconcologia.net wrote:
> Full_Name: Xavier Sol?
> Version: 2.3.0
> OS: Windows
2020 Oct 23
0
The presence/absence of `zone` in POSIXlt depending on time zone as a cause of possible inconsistences?
?Hi again,
I take advantage of my previous mail to ask you a question for which I was looking for an answer when detected the behaviour I previously told. In the help of DataTimeClasses one can read:
"POSIXlt" objects will often have an attribute "tzone", a character vector of length 3 giving the time zone name from the TZ environment variable and the names of the base time
2005 Apr 06
1
nls.control
Hello everyone,
I'm trying to test the accurracy of R on the Eckerle4 dataset from NIST and
I don't understand how the control option of the nls function works.
I tought nls(...) was equivalent to nls(...control=nls.control()) i.e nls.control() was the default value of control, but here is the error I get :
> n2=nls(V1~(b1/b2) *
2007 Mar 01
1
GLM problems.
Dear R users I'm new in R management and maybe It's a silly question. I'm
working with GLM to obtain predictive models. I have some problesm with the
prediction instruction:
> DatosTotal <- read.csv("Var_perdizcsv.csv", sep =";")
> edvariable <- edit(DatosTotal)
> pre <- predict(rlfinal, DatosTotal, type = 'probs')
Erro en
2012 Jul 05
2
vector entry in matix
hi,
i'm trying to figure out if there's any possibility to write a whole vector
into a matrix or data.frame or something like that. i don't mean
transormation. Here an example:
[,1] [,2]
[1,] "a" "d"
[2,] "b" "e"
[3,] "c" "f"
where e.g. a is a<-c(0,1) vector of length 2, b a vector of length 4,... (i
know that
1998 Mar 18
1
Strange Results of summary()
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Hello,
I run the following job. Please, compare the results of summary and
table concerning berufl. From similar SPSS/PSPP runs, the result of
table is correct.
Did I misunderstand anything or is there a bug?
What does the difference come from?
What does '(other)' mean?
What about the strange
2007 Jul 20
3
binned column in a data.frame
Dear all,
I would like to know how can I create a binned column in a data.frame. The output that I would like is something like this:
Start Binned_Start
1 0-5
2 0-5
6 5-10
8 5-10
13 10-15
...
Best regards
João Fadista
Ph.d. student
UNIVERSITY OF AARHUS
Faculty of Agricultural Sciences
Dept. of Genetics and Biotechnology
Blichers
2003 Jan 29
3
Analyzing an unbalanced AB/BA cross-over design
I am looking for help to analyze an unbalanced AB/BA cross-over design by
requesting the type III SS !
# Example 3.1 from S. Senn (1993). Cross-over Trials in Clinical
Research
outcome<-c(310,310,370,410,250,380,330,270,260,300,390,210,350,365,370,310,380,290,260,90,385,400,410,320,340,220)
subject<-as.factor(c(1,4,6,7,10,11,14,1,4,6,7,10,11,14,2,3,5,9,12,13,2,3,5,9,12,13))
2025 Jan 24
3
Interpreting the output of str on a data frame created using aggregate function
I ran the following code:
marginalcats <- aggregate(meanbyCensusIDAndDay3$cats,
list(meanbyCensusIDAndDay3$CensusID),table)
followed by
str(marginalcats)
I received the following output:
'data.frame': 844 obs. of 2 variables:
$ Group.1: num 6e+09 6e+09 6e+09 6e+09 6e+09 ...
$ x : int [1:844, 1:7] 14 14 14 14 14 14 14 14 14 14 ...
..- attr(*,
2012 Jul 06
3
estimating NA values against selected slots
Dear R Users,
Could you please help me on the following issue?
I have a real large yearly data set. For each year I have
365 flow values. Some of the flow values are not known and that’s why you will
see NA written in those slots. I wanted to know, is there a way that I can
estimate those values? I tried approx command but it seems least helpful for
the kind of issue I am up against.