search for: 4420

...e dataframes. 1) By the following command you can see that the value im transferring is 481844.03 > MatchedValues[Value2,Value] [1] 481844.03 6618 Levels: 1.00E+07 1.01E+07 1.02E+07 1.04E+07 1.05E+07 1.06E+07 ... Raw 2) But when I try to replace the values using the command i get a value of 4420 >ClusteredData[k,Value] <- MatchedValues[Value2,Value] > ClusteredData[k,Value] [1] "4420" 3) So what am I not doing. How can I keep that same value of 481844.03 I have tried > as.double(MatchedValues[Value2,Value]) [1] 4420 > as.numeric(MatchedValues[Value2,Value]...

...3D=3D22324=3D=3D For more details, rerun with: -v =3D=3D22324=3D=3D=20 =3D=3D22324=3D=3D Invalid read of size 4 =3D=3D22324=3D=3D at 0x81255AD: parse_expression (regex.c:5045) =3D=3D22324=3D=3D by 0x8125868: parse_branch (regex.c:4475) =3D=3D22324=3D=3D by 0x8125913: parse_reg_exp (regex.c:4420) =3D=3D22324=3D=3D by 0x81261B3: Rf_regcomp (regex.c:4384) =3D=3D22324=3D=3D Address 0x1C1E23A8 is 0 bytes after a block of size 32 a= lloc'd =3D=3D22324=3D=3D at 0x1B90650D: calloc (in /usr/lib/valgrind/vgpreload_= memcheck.so) =3D=3D22324=3D=3D by 0x81247B5: parse_expression (regex....

...29 1290 4450 2002 3 29 1305 4445 2002 3 29 1320 4440 2002 3 29 1335 4437.5 2002 3 29 1350 4435 2002 3 29 1365 4432.5 2002 3 29 1380 4430 2002 3 29 1395 4427.5 2002 3 29 1410 4425 2002 3 29 1425 4422.5 2002 3 29 1440 4420 2002 3 30 15 4420 2002 3 30 30 4420 2002 3 30 45 4420 2002 3 30 60 4420 2002 3 30 75 4420 2002 3 30 90 4420 2002 3 30 105 4420 2002 3 30 120 4420 2002 3 30 135 4417.5 2002 3 30 150 4415 2002 3 30 165 4412.5 2002...

Hi, all, Does anybody got the most general expression of a unitary matrix? I found one in the book, four entries of the matrix are: (cos\theta) exp(j\alpha); -(sin\theta)exp(j(\alpha-\Omega)); (sin\theta)exp(j(\beta+\Omega)); (cos\theta) exp(j\beta); where "j" is for complex. However, since for any two unitary matrices, their product should also be a unitary matrix. When I

I got a sample data (let's call it sample.data), which is about 2200 by 15. I tried to take a look of all data >sample.data It shows only a part of data that I thought was a corner. It does not really affect my job, but I thought it is nice to have a look of all data. I can see individual records and they are fine. Is this normal because of buffer size or some reasons? Can I use other

Is there a simple function in R to get a moving standard deviation (i.e. for the last x samples)? My goal is to plot bollinger bands around a moving average for price data. I use kernel smoothing for the moving average. cheers and thanks! over and out -- doktora

Dear all, I have a population with three age-classes, at time t=0 the population is: n.zero <- c(1,0,0) I have a transition matrix A which denotes "fertility" and "survival": A <- matrix(c(0,1,5, 0.3,0,0, 0,0.5,0), ncol=3, byrow=TRUE) To obtain the population at t=1, I calculate: A %*% n.zero To obtain the population t=2, I calculate: A %*% (A %*% n.zero) ... and so

Hi, I am a user of R computer language.Several days ago,I download R-2.1.0.From the help manual,I saw there is a function "mle" to find the maximum likelihood estimators.But when I try to use this function,there is no this function.Could you help me to solve this problem? I am looking forward to your answer. Thank you. Jun Liu

...lf. >> >> Viktor > > That's your problem - it needs a privileged container so that the container > can change the permissions on the underlying filing > system. OK, I found some evidence of this here: https://discuss.linuxcontainers.org/t/samba-acls-in-a-lxd-container/4420/7 It seems that changing xattr information requires real root which is why it won't work with an unprivileged container. If what is said in that discussion is true, then the only workaround for a non privileged container is to assume no support for xattr and use posix:eadb in smb.conf. ht...

Hi, The question is as follows: has anyone coded panel data unit root tests with R? Even the "first generation" tests (see e.g. Levin & Lin 1993; Pesaran, & Smith & Im 1996; Maddala & Wu 1999) would be sufficient for my needs. To my understanding, these are rather easy to code, but as I have taken just my first steps in coding with R, existing code would save me

Hey, I am estiamting a partially linear model y=X\beta+f(\theta) where the f(\theta) is estiamted using wavelets. Has anyone heard of methods to test if the betas are significant or to address model fit? Thanks for any thoughts or comments. Elizabeth Lawson __________________________________________________ [[alternative HTML version deleted]]

Dear R-users, Is anyone aware of any function/package for generating a random vector from a joint distribution defined by an independent graph? Or I have to work it out myself? Thanks. Jinfang ------------------------------ Jinfang Wang, Associate Professor Chiba University, Japan

...1, 1, 1, 2, 1, 2, 1, 2, 1, 1, 1, 1, 2, 1), y=cbind( y1<-c(5000, 3820, 4300, 3720, 4370, 4250, 4820, 4060, 4110, 4620, 4580, 3580, 3070, 4030, 3900, 3390, 3880, 4120, 3690, 4130), y2<-c(6160, 5240, 5210, 4650, 5600, 5340, 6020, 5590, 5140, 5640, 5340, 4640, 4650, NA, 5320, 4510, 4910, 4960, 4420, 5150), y3<-c(6720, 6040, 6240, 5550, 6610, 6850, 6760, 6370, 6030, NA, 6880, 5330, 5700, NA, 6220, 5240, 5850, 5960, 4910, 5550), y4<-c(7640, 6840, 6900, 6010, 7780, 7650, 7610, 7000, NA, NA, 7720, 5990, 6340, NA, 7360, 5910, 6310, NA, 5350, 5880)), last=c(4, 4, 4, 4, 4, 4, 4, 4,...

I often use simple nested random-effect models for interlaboratory data. The variance components are important things to know. Is there an R function or package that gets variance components from lm objects? Or can someone point me to a method of doing so?

...etc. How do I specify these models in R? Help would be most appreciated. I am a relatively new user. John Prof John Fresen (PhD) Department of Mathematics and Statistics Medical University of Southern Africa PO Box 107 MEDUNSA 0204 South Africa e-mail: jfresen@medunsa.ac.za tel: +27 12 521 4420 [[alternative HTML version deleted]]

...ks for all your efforts to make R what it is today. Best Wishes, spencer graves -- Spencer Graves, PhD Senior Development Engineer PDF Solutions, Inc. 333 West San Carlos Street Suite 700 San Jose, CA 95110, USA spencer.graves at pdf.com www.pdf.com <http://www.pdf.com> Tel: 408-938-4420 Fax: 408-280-7915

Hi, I would like to get the coefficients of x^0, x^1, x^2, . , x^6 from expansion of (1+x+x^2)^3. The result should be 1, 3, 6, 7, 6, 3, 1; How can I calculate in R? You help will be greatly appreciated. Peter [[alternative HTML version deleted]]

Hello and sorry to disturb. I'm trying to plot the confidence intervals for the fixed effects of a lme. I want to obtain graphically, if it is possible, a bar with Estimate, upper and lower CI for each level of the factors. I know how to do for a lm model but for a lme one, I tried with plot(intervals(...)) and plot(ci(...)) from the gmodels package but it doesn't work well. Thanks

...t? Spencer Graves p.s. I get the same result using several different (US) mirrors. -- Spencer Graves, PhD Senior Development Engineer PDF Solutions, Inc. 333 West San Carlos Street Suite 700 San Jose, CA 95110, USA spencer.graves at pdf.com www.pdf.com <http://www.pdf.com> Tel: 408-938-4420 Fax: 408-280-7915

...############# Thanks for your time in reading this. Best Wishes, Spencer Graves Spencer Graves, PhD Senior Development Engineer PDF Solutions, Inc. 333 West San Carlos Street Suite 700 San Jose, CA 95110, USA spencer.graves at pdf.com www.pdf.com <http://www.pdf.com> Tel: 408-938-4420 Fax: 408-280-7915