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...theta=15) any of you have a better idea (ie more efficient)? Thanks in advance, Patrizio Frederic +------------------------------------------------- | Patrizio Frederic | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...) for computing BSA. Many thanks in advance, Patrizio as usual I apologize for my fragmented English -- +------------------------------------------------- | Patrizio Frederic, PhD | Assistant Professor, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...ven only the geographical location of the sampling points ? Thanks a lot for the attention !!! Stef ------------------------------------------------------------------------ Stefano Marchesi Environmental Epidemiologic Unit Environmental Protection Agency - ARPA Emilia Romagna Via Fontanelli 23 - 41100 Modena (Italy) tel: +39 059 433635 (int. 5035) fax: +39 059 241312 sito web: www.arpa.emr.it/epam

Hi all, I am running a bivariate regression with the following: p1=c(184,155,676,67,922,22,76,24,39) p2=c(1845,1483,2287,367,1693,488,435,1782,745) I1=c(1530,1505,2505,204,2285,269,1271,298,2023) I2=c(8238,6247,6150,2748,4361,5549,2657,3533,5415) R1=I1-p1 R2=I2-p2 x1=cbind(p1,R1) y1=cbind(p2,R2) fit1=lm(y1~-1+x1) summary(fit1) Response 2: Coefficients: Estimate Std. Error t value

...nguage R version.string R version 2.7.0 (2008-04-22) thank you in advance, Patrizio Frederic ------------------------------------------------- | Patrizio Frederic | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...last) V1 V2 V3 1 1 3 0.4 2 2 1 NA 3 3 1 1.1 any hint? Thanks in advance, Patrizio +------------------------------------------------- | Patrizio Frederic, PhD | Research associate in Statistics, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

...2 125 39840 77 126 39900 0 127 39960 0 128 40020 0 129 40080 0 130 40140 0 131 40200 0 132 40260 0 133 40320 0 134 40380 0 135 40440 0 136 40500 0 137 40560 0 138 40620 32 139 40680 32 140 40740 109 141 40800 67 142 40860 92 143 40920 0 144 40980 0 145 41040 0 146 41100 0 147 41160 0 148 41220 0 149 41280 0 150 41340 0 151 41400 0 152 41460 0 153 41520 112 154 41580 0 155 41640 0 156 41700 0 157 41760 0 158 41820 0 159 41880 0 160 41940 0 161 42000 0 162 42060 0 163 42120 0 164 42180 0 165 42240 0 166 42300 0 167 42360 0 1...

...en by later version of R I've no idea of what type 136 is. Any hints? Thanks in advance, Patrizio -- +------------------------------------------------- | Patrizio Frederic, PhD | Assistant Professor, | Department of Economics, | University of Modena and Reggio Emilia, | Via Berengario 51, | 41100 Modena, Italy | | tel: +39 059 205 6727 | fax: +39 059 205 6947 | mail: patrizio.frederic at unimore.it +-------------------------------------------------

Dear all, I'm stuck in a seemingly trivial task that I need to perform for many datasets. Basically, I want to replace NA with 0 in a specified range of columns in a dataframe. I know the first and last column to be recoded only by its name. I can select the columns starting like this a[match('first',names(a)): match('last',names(a))] The question is how can replace all NA

Hi, I would like to generate two correlated variables. I found that funktion for doing that: a <- rmvnorm(n=10000,mean=c(20,20),sigma=matrix(c(5,0.8*sqrt(50), 0.8*sqrt(50),10),2,2)) (using library(mvtnorm)) Now I also want to generate two correlated variables where the error variance vary over the variable-correlation. And I want to plot this for showing heteroscedasticity. Like shown

Hi, In order to use the mle2-function, one has to define the likelihood function itself. As we know, the likelihood function is a sum of the logarithm of probability density functions (pdf). I have implemented myself the pdfs that I am using. My problem is, that the pdfs values are negative and I cann't take the logarithm of them in the log-likelihood function. So how can one take the

Hi, At each iteration in my program,I need to generate tree vectors,X1,X2,X3, from exponential distribution with parameters a1,a2,a3. Can you help me please how can I do it such that it take a little time? thank you khazaei

Dear group, Here are my objects in my environment: > ls() [1] "Pos100415" "Pos100416" "posA" "pose15" "pose16" "pose16t" "position" "trade" "x" I need to pass the object "Pos100415" to a function. This element is a data.frame, obtained through a function: Pos(x)<-myfun(x)

...t leave more giving the message Returning to the previous version all it resumes to work correctly. What I have mistaken? Thanks. _____________________________________________________ Fabrizio Guerriero EDP Manager C.C.M. Coop.Cartai Modenese Soc.coop. Via F. Malavolti, 12 - Torrazzi Sud 41100 Modena - Italia Tel. +39 059 25.89.211 Fax. +39 059 25.89.289 Resp.Edp at coopcartai.it http://www.coopcartai.it <http://www.coopcartai.it%20> Skype : fabrizio.guerriero Le informazioni contenute nella presente comunicazione potrebbero essere riservate e confidenziali. Ove non siate i...

I downloaded wine but when I try to invoke it I get this message ... wine: could not load L"c:\\windows\\system\\program.exe": Module not found What does that mean? how can I fix it? and how can I get Wine to start running?

Hi R-users, I have this code to uniformise the data using gamma: > length(dp1) [1] 696 > dim(dp1) [1] 58 12 > dim(ahall) [1]  1 12 > dim(bhall) [1]  1 12 > trans_dt <- function(dt,a,b) + { n1 <- ncol(dt) +   n2 <- length(dt) +   trans  <- vector(mode='numeric', length=n2) +   dim(trans) <- dim(dt) +   for (i in 1:n1) +   {  dt[,i] <- as.vector(dt[,i])

Dear R Users, I am executing the following command to produce a line graph: matplot(aggregate_1986[,1], aggregate_1986[,2:3], type="l", col=2:3) On the x-axis I have values of Latitude (in column 1) ranging from -60 to +80 (left to right on the x-axis). However, I wish to have these values shown in reverse on the x-axis, going from +80 to -60 (ie. North to South in terms of Latitude).

Hi again! Suppose I have the following: > xy <- round(rexp(20),1) > xy [1] 0.1 3.4 1.6 0.4 1.0 1.4 0.2 0.3 1.6 0.2 0.0 0.1 0.1 1.0 2.0 0.9 2.5 0.1 1.5 0.4 > table(xy) xy 0 0.1 0.2 0.3 0.4 0.9 1 1.4 1.5 1.6 2 2.5 3.4 1 4 2 1 2 1 2 1 1 2 1 1 1 > Is there a way to set things up to have 0 - 0.4 0.5 - 0.9 etc. please? I know there is the cut

...................... configure:7739: result: no configure:7792: gcc -c -I/usr/local/include conftest.m >&5 gcc: error trying to exec 'cc1obj': execvp: No such file or directory configure:7798: $? = 1 configure: failed program was: | /* confdefs.h. */ ...................... configure:41100: gcc -m64 -std=gnu99 -o conftest -mminimal-toc -fno-optimize-sibling-calls -g -O2 -I/usr/local/include -L/usr/local/lib conftest.c -framework vecLib -ldl -lm >&5 gcc: vecLib: No such file or directory cc1: error: unrecognized command line option "-framework" configure:41106: $?...

...2 125 39840 77 126 39900 0 127 39960 0 128 40020 0 129 40080 0 130 40140 0 131 40200 0 132 40260 0 133 40320 0 134 40380 0 135 40440 0 136 40500 0 137 40560 0 138 40620 32 139 40680 32 140 40740 109 141 40800 67 142 40860 92 143 40920 0 144 40980 0 145 41040 0 146 41100 0 147 41160 0 148 41220 0 149 41280 0 150 41340 0 151 41400 0 152 41460 0 153 41520 112 154 41580 0 155 41640 0 156 41700 0 157 41760 0 158 41820 0 159 41880 0 160 41940 0 161 42000 0 162 42060 0 163 42120 0 164 42180 0 165 42240 0 166 42300 0 167 42360 0 1...