search for: 3x3

Dear all, suppose I have a vector with elements as: Vec <- c(2,3,4,5,6) Now I want to have all possible combination of length 3 using those elements and without any repetition. Like, I want to have 1 possibility like 2-3-4 but not 3-2-4. Can somebody guide me how to achieve that in R? Thanks for your help.

Dear Friends, I have been trying to save multiple 3x3 (mfrow=c(3,3) graphics inside a loop using tiff figure format (not using PDF or savePlot functions) with no success. Could you please help? Here is a simplified example code: dat=data.frame (ID=rep(1:10,each=10),IDV=rep(seq(1:10),times=10)) dat$DV <- with(dat, 50+15*IDV) dat=dat[order(dat$...

Dear colleagues, I would need to add text (some rows of information) in a matrix. For example, given this matrix 1 2 3 4 5 6 7 8 9 I would need to add this info: THIS IS AN EXAMPLE OF a 3x3 MATRIX 1 2 3 4 5 6 7 8 9 I have been looking for a function that works similar to "fopen" in matlab, but unfortunately I have not found It in R. Thank you in advance for your help! Carlos Fernandez

I want to form a 3x3 crosstabulation for the signs of two vectors (i.e. Negative, Zero, Positive). The problem is that I am simulating the data so for some iterations one of the categories is absent. Thus the resulting table shrinks to 3x2. I want it to be 3x3 with zero column corresponding to the missing category. Mor...

Hi all, Why cov(y, y) only gives one value, and cov(t(y), t(y)) gives 3x3 NA matrix? Here my y is listed below and it is a 3x1 matrix. I am expecting that if I have a random vector y=[y1 y2 y3]', here " ' " denotes a transposition so that y is a column vector, where y1, y2, y3 are independent random variables... then cov(y, y) should be E[ y * y...

useR's I have a matrix from which I want to take multiple subsets from, according to a particular scheme I will now describe. The matrix below (mat) is 5x5, and I want to take 9 subsets of it, each of dimension 3x3. The best way to explain what the result should look like is with the following: > dat <- c(3,6,1,9,12,9,2,10,6,5,3,13,1,4,8,9,4,6,10,11,2,7,3,5,10) > miss <- c(2,8,10,16,23) > dat[miss] <- NA > mat <- matrix(dat,5,5) > mat [,1] [,2] [,3] [,4] [,5] [1,] 3 9...

Dear List, I have a couple of (~200) 3x3 transition probability matrices (ie each defines a Markov chain). They are all estimated from the same underlying process, so it ie meaningful to take their elemetwise mean and standard deviation. [1] First question: supposing that they are given in a list l, how do I get their elementwise mean an...

...50 Now I'm wondering how can I perform the analysis for 3 genes (and construct the contigency table), as follows: Gene A mutated, Gene A normal, Gene B mutated, Gene B normal, Gene C mutated and Gene C normal. How do I perform a fisher test using fisher.test( ) function using this data (3x3 contigency table)?Can someone help me ? [[alternative HTML version deleted]]

hi all, i'm trying to get elements in a matrix into a vector. i need a "streamlined" way to do it as the way i'm doing it is not very serviceable. an example is a 3x3 matrix like 0 0 3 2 0 0 0 4 0 to a vector like 3 2 4 thanks...mj [[alternative HTML version deleted]]

R-help, I would like to place nine (3X3) plots per page. I am not properly implement mfrow(3,3) in the script below: jpeg("xyplot.jpg") #names output file my_args <- commandArgs() #sets up to take args from dos batch command mfcol(3,3) #set page for 3X3 TEMPS <- c(-15,25,85)#list of temps VBATS <- c(3,3.6,4.7)#list o...

...the first pick, 'B' number of genes in the second pick, and 'C' number of genes in the third pick, I would want to calculate p(n) where n = (A intersection B intersection C). Would fisher exact test be the correct method to evaluate the probability? And if so how can I frame the 3x3 (?) contingency table? I can find numerous examples of 2x2 tables, but none for 3x3. Any guidance would be appreciated. many thanks. [[alternative HTML version deleted]]

Hi guys, I used the following R code to generate one plot library(lattice) xyplot(Y~X1|as.factor(X2)*as.factor(X3), groups = as.factor(X4), data=mydata) Both X2 and X3 have three values. X4 has two values. I got 3x3 grids and in each grid there are two curves about y~x1 for the two X4 values. I am quite happy with the plot except that I need a different layout of the 3x3 layout. For example, X2={"m=2", "m=5", and "m=10"} and it plots with the order "m=10", "m=2&quot...

...s")) x <- seq(-4,4, by=0.1) # case 1x1 a <- c( 1 ) b <- c( 3 ) trel_1 <- xyplot(f(x,a,b) ~ x | a * b, , type = "l", main = "1x1", ylab = "f(x)", xlab = "x", xlim = c(-6,6), ylim = c(-6,6), ) # case 3x3 a <- c(1,2,3) b <- c(1,2,3) trel_3 <- xyplot(f(x,a,b) ~ x | a * b, , type = "l", main = "3x3", ylab = "f(x)", xlab = "x", xlim = c(-6,6), ylim = c(-6,6), ) print(trel_3) #print(trel_1) --- en...

I have created a list of "matrices" using sapply or lapply and wish to extract each of the "matrices" as a matrix. Some of them are 2x2, 3x3, etc. I can do this one at a time as: M1<-as.matrix(D[[1]]) How can repeat this process for an unknown number of entries in the list? In other words, how shall I index M1? Diana

Estimados Para analizar tres muestras cualitativas independientes se utiliza Cochran-Mantel-Haenszel test ?Cual script es el adecuado para analizar tres variables dependientes? en MCNEMAR solo se permite analizar dos variables cualitaticvas dependientes saludos José [[alternative HTML version deleted]]

...yOS configuration is posted in the above forum post, except now I have followed their advice and created 20 tunnels (each subnet to each subnet, if that makes sense). However, when I enabled this, I got the following errors on the Openswan server: Feb 18 01:24:27 OPENSWAN pluto[8010]: "VYOS/3x3" #70: next payload type of ISAKMP Hash Payload has an unknown value: 243 Feb 18 01:24:27 OPENSWAN pluto[8010]: "VYOS/3x3" #70: malformed payload in packet Feb 18 01:24:27 OPENSWAN pluto[8010]: "VYOS/3x3" #70: sending notification PAYLOAD_MALFORMED to <VYOS IP>:500 Feb...

Hi r-help community, This question isn't so much a syntax/coding one, but here goes: Let's say I have matrix of arbitrary dimensions and I'd like to reorder the rows in such a way that I could maximize the sum of the entries along the diagonal. For example, for this 3x3 matrix: [,1] [,2] [,3] [1,] 3 4 13 [2,] 9 1 2 [3,] 2 11 1 rearranging the rows to maximize the sum along the diagonal would produce this matrix: [,1] [,2] [,3] [1,] 9 1 2 [2,] 2 11 1 [3,] 3 4 13 I've been experimenting with some...

...0.0002570286 0.0002117336 Z 0.0007887114 0.0002117336 0.0009168750 And a weight vector generated by w<- read.table("c:/r.weights") X Y Z 1 0.5818416 0.2158531 0.2023053 I want to compute the product of the matrix and vectors termwise to generate a 3x3 matrix, where m[i,j]=w[i]*co[i,j]*w[j]. 0.000423773 7.47216E-08 4.41255E-08 7.47216E-08 1.96566E-11 4.29229E-11 4.41255E-08 4.29229E-11 4.11045E-11 Is this possible without writing explicit loops? Thank you, Dan Stanger Eaton Vance Management 200 State Street Boston, MA 02109 617 598 8261...

...have unable to find the answer for it either in the R-manual or by browsing the web. I would like to know if there is a "mode" function in R, such that from a vector or matrix the function returns the most common value. In other programs I use (such as Matlab) I can have for exampe a 3X3 matrix A, A=[1 2 3; 1 3 2; 3 3 2] and I can find the mode of the rows so that mode(A[1:3,:]) returns a 1X3 matrix [1 3 2]. Is this possible in R as well? If not, how would one go about this? Thank you very much, Bill [[alternative HTML version deleted]]

...ust started learning R. I'm trying to use the Help and the downloadable manuals. I am stuck on trying to multiply matrices. Can anyone please supply a couple of lines of code that I can plug into a fresh console to see how a double precision (1x3) matrix is multiplied by a double precision (3x3) matrix? I keep getting an error message,"Error in x%*%A: requires numeric matrix/vector arguments". I have some VBA and VB experience (thus a little Object Oriented programming experience), am I right in beliving that I am not "dimensioning" correctly? I have been trying th...