search for: 3var

Hi, According to help(sub), the ^ should match the zero-length string at the beginning of a string: sub('^','var',1:3) # "1" "2" "3" sub('$','var',1:3) # "1var" "2var" "3var" # This generates what I expected from the first case: sub('^.','var',11:13) # "var1" "var2" "var3" Dave -- Dr. David Forrest drf at vims.edu (804)684-7900w drf5n at maplepark.com...

...to help(sub), the ^ should match the David> zero-length string at the beginning of a string: yes, indeed. David> sub('^','var',1:3) # "1" "2" "3" David> sub('$','var',1:3) # "1var" "2var" "3var" David> # This generates what I expected from the first case: David> sub('^.','var',11:13) # "var1" "var2" "var3" there are even more fishy things here: 1) In your cases, the integer 'x' argument is auto-coerced to char...