Displaying 2 results from an estimated 2 matches for "3d0a".
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3d0
2006 Dec 26
4
vectorizing an iterative process.
Hi Everyone,
I am stuck with a simple problem. Suppose I have a vector x, and I want
to calculate y[i]=3Dx[i+1]-x[i], it is very easy. I just need to write
y<-x[2:length(x)]-x[1:length(x)-1].
Now if I know y, and want to know the vector x defined by
x[i]=3Dx[i-1]+y[i-1] for all i, how can I do this without a loop?
Thanks,
Geoffrey
PS. Sorry if you see a duplicate message. The previous
2000 Mar 24
2
Samba and DOS
...> ORG:IPI UK Ltd.;Client Services
> TITLE:Client Services Manager - Europe
> TEL;WORK;VOICE:0207 251 6767
> TEL;HOME;VOICE:0207 251 6767
> TEL;CELL;VOICE:0961 171 046
> TEL;HOME;FAX:0207 251 3161
> ADR;WORK;ENCODING=3DQUOTED-PRINTABLE:;IPI London;48-50 St. John =
> St.=3D0D=3D0A;London;;EC1M;united Kingdom
> LABEL;WORK;ENCODING=3DQUOTED-PRINTABLE:IPI London=3D0D=3D0A48-50 St. =
> John St.=3D0D=3D0A=3D0D=3D0ALondon EC1M=3D0D=3D0Aunited Kingdo=3D
> m
> ADR;HOME;ENCODING=3DQUOTED-PRINTABLE:;;8 Edmeston =
> Close=3D0D=3D0A;London;;E9 5TJ;United Kingdom
> LABE...