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Hi, I am using R to fit statistical models to data were the observations are means of the original data. R is used to calculate the mean before fitting the model. My problem is: When R calculates the means using tapply, the class of the means differs from the class of the original data, which gives me trouble when I want to use the original data to calculate model predictions. Here is a simple

  Hi r-users,   I would like to use gev and my data (annual rainfall ) is as follows:   > head(dat,20) A B C D E F G H I J 1 45.1 41.5 58.5 50.1 46.0 49.1 37.7 49.1 59.8 54.0 2 50.3 39.8 49.4 56.4 49.4 48.8 42.1 49.8 49.4 58.3 3 41.7 39.3 44.6 39.1 35.7 41.5 40.8 40.8 38.5 45.6 4 50.7 33.9 48.4 28.2 35.5 39.1 61.4 17.0 30.7 38.3 5 39.3 30.6 46.9 23.8 25.8

Dear helpers I have two data sets saved as vectors (temperature and velocity). Now I need to "take out" a span of temperature and its corresponding velocity in the other vector. How can I achieve that? I tried to write a function,which takes a vector entry and then decides wether to delete the temperature entry or not and simultaneously doing so with same entry in the velocity

Hello, I teach statistics and use R Commander for teaching. I have 2 students out of 169 that can't get scatterplots or plot to work. I have had them update packages, restart R/R Commander/their computers and even reinstall R/R Commander. One is using Windows 7 on a new pc and the other is a pc user (not sure the OS). They are both using R2.11.1 and R Commander 1.6-0. The data look like

Dear r-users,   Originally my data is in notepad.  I use data.frame(...) to convert the data into columns but it has no header.  The data below is what I got in R.  I would like to extract these data:   19710629        39.3  19701126  19720629        33.8  19720517 ... when I use data2_30min[1, cbind(1,3,5)] command the result is NULL.   Then I tried data2_30min[1], it gives me the whole set of

Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:

I'm trying to read a comma delimited dataset that uses '.' for NA. I found that if the last field on a line was a missing '.' it was not read as NA, but just a '.', and the life variable was made a factor. The data looks like this, income,imr,region,oilexprt,imr80,gnp80,life Afghanistan,75,400.0,4,0,185.0,.,37.5 Algeria,400,86.3,2,1,20.5,1920,50.7

Dear r-users,   I have saved data in word pad.  I would like to extract certain part of data only, for example   19710629 080000(PARTIAL) 39.3 at interval beginning 19701126 010326 19720629 080000(PARTIAL) 33.8 at interval beginning 19720517 144507 19730629 080000(PARTIAL) 32.2 at interval beginning 19720910 135747   and so on...   The original data set are given below:      

Nobody seems to use txfax or does nobody have any problems with it? I have sent mails to most lists and get no reply. I cannot get a fax to go through with txfax. I use a call file as a test and all I get on the receiving fax is a bunch of vertical lines. my call file is: Channel:Srx/gout/4658158 MaxRetries: 0 WaitTime: 20 Application:txfax Data:/etc/asterisk/testfax.tif|caller|debug FYI

I started to check what I thought I knew with autocovariance and it doesn’t jive with the the calculations given by ‘R’. I was wondering if there is some scaling or something that I am not aware of. Take the example Ø d <- 1:10 Ø (a <- acf(d, type="covariance", demean=FALSE, plot=FALSE)) Autocovariances of series ‘d’, by lag 0 1 2 3 4 5 6

Dear all, I have a data frame, which looks like this: Subject | Block | Trial | Feature1 | Feature2 .... 1 | 1 | 1 | ... | ... 1 | 1 | 2 | ... | ... 1 | 2 | 1 | ... | ... 1 | 2 | 2 | ... | ... 1 | 3 | 1 | ... | ... ...| ...| ...| ... | ... Can I remove the "Trial" column by averaging all the rows and without using a "for loop"? At the end my data frame should look like

Hello, I am using the lmomco package (lmom.ub and pargev) to compute the GEV parameters (location, scale, and shape), which are used to estimate return values. I was wondering how/if I can calculate upper and lower confidence (CI_u, CI_l) intervals for each return frequency using the GEV parameters to fill-in the table below? Xi (location) = 35.396 Alpha (scale) = 1.726 Kappa (shape) =

Hi All, I have a small dataset named das (43 cases) in which I am trying to create a binary outcome (1/0) based on the following code: if (das$age>65 && das$bmi>30) {das$danger<-1} else das$danger<-0 I am setting a flag called 'danger' to 1 of the subject is over 65 and has a BMI > 30. I find that my statement evaluates the first record in the data.frame and

Hi - I am not R expert and I would appreciate your time if you can help me about my xyplot question. I would like to add text (p-value) in a 4 panels xyplot. I thought panel = function{} should work but I am not sure where I did it wrong. The error message from the following code is "Argument subscripts is missing with no default values" xyplot(GLG ~ PD | factor(TRT) , groups =

Dear R-User, Appreciate any helps. It looks simple, but I don't have a clue. Given that I have a dataframe of tree population with three variables: sp=species , d0=initial_size grow=growth increment from initial size per year How can I calculate the future growth increment of each tree for the next 3 years. The following Rscript was written, #---------- a0 <-

I recently installed rsync 2.5.5 on both my rsync server and client being used. I installed the latest version because I was having problems with rsync stalling with version 2.4.6 (I read that 2.5.5 was supposed to clear this up or at least give more appropriate errors). I am still having problems with rsync stalling even after upgrading to 2.5.5. It only stalls in the "/home" tree

dear useRs, i have a list containing 16 matrices. i want to calculate the column mean of each of them. i tried >sr <- lapply(s,function(x) colMeans(x, na.rm=TRUE)) but i am getting the following error >Error in colMeans(x, na.rm = TRUE) : 'x' must be numeric can it be done in any other way? and why i am getting this error?? thanks in advance.. elisa [[alternative

I am trying to get the temperature of a Poweredge 2850 with CentOS 6.3 on it. Has anybody on this list done this successfully? Thanks -Surya PS: Apologies for cross posting if you are on the Poweredge list. -- Surya Saha Department of Plant Pathology and Plant-Microbe Biology Cornell University, NY, USA http://www.linkedin.com/in/suryasaha

Using caret on the Titanic data from Kaggle, I tried various models, including rfRules which produces a model, partly described as such: > caret.rfRules.cv$finalModel $model len freq err [1,] "2" "0.0368" "0" [2,] "2" "0.032" "0.05" [3,] "2"

Hello, I have two questions regarding a survival analysis I have been working on. Below is the code to date. The variables: 1) recidivism$intDaysUntilFVPO are the number of days before an violent offence was committed - if no offence was committed than the days between court hearing and end of data collection was recorded. 2) recidivism$intDaysUntilFNVPO are the number of days before a