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On 1/8/2013 1:11 PM, Renato Golin wrote: > > Still, doesn't explicitly say it's undefined. I agree this gives the > freedom of implementers to extend naturally, but it's at least arguable. > I have the 2011 draft and couldn't find anything, nor in the current > open issues. It does, actually: C++ 2003 [5.7.5] When an expression that has integral type is added to

On 8 January 2013 18:40, Matthieu Monrocq <matthieu.monrocq at gmail.com>wrote: > I do believe it's undefined. > > §5.2.1 Subscripting [expr.sub] > ... > §5.7 Additive operators [expr.add] > ... > Still, doesn't explicitly say it's undefined. I agree this gives the freedom of implementers to extend naturally, but it's at least arguable. I have the 2011