search for: 2e5

...d (although perhaps not a bug): function(n) { line <- paste(as.character(trunc(runif(n)*100)),collapse=" ") system.time( rep <- gsub("[[:space:]]", "-", line) ) } gives rather long times rising v sharply for big strings (eg 2.2s at n=2e4, 360s at n=2e5 on AMD 1.2GHz). Other languages aren't so slow on this task (eg n=2e5: 0.4s ruby 1.8.1, and 5.2s python 2). Doubtless my extremely-quick-hack benchmarks aren't fair, but the difference still seems rather big. Mark <><

Sorry guys; I got a bit lost about Gene's request on this thread; usually a handle dump like # dh > handles.txt it's all we need to see the relationship between the NBP's device handle and the Service Binding handles. Did you get handles.txt? is it available for download somewhere? >>> Gene, after modifying some of Patrick's code I have been able to get the

...oadFile DevicePath(065F36E00EF,0x1)/IPv4(0.0.0.0)) 2A6: SimpleNetwork PXEBaseCode LoadFile DevicePath(0000:0000:0000:0000:0000:0000)) 2BB: SimpleNetwork PXEBaseCode LoadFile DevicePath(CDCD40CA5F0,0x0)/IPv4(0.0.0.0)) 2D0: SimpleNetwork PXEBaseCode LoadFile DevicePath(0000:0000:0000:0000:0000:0000)) 2E5: SimpleNetwork PXEBaseCode LoadFile DevicePath(CDCD40CA5F4,0x0)/IPv4(0.0.0.0)) 23E: MTFTPv4ServiceBinding DHCPv4ServiceBinding UDPv4ServiceBinding UnknownDevice TCPv4ServiceBinding IPv4ServiceBinding ARPServiceBinding UnknownDevice EfiMtftp6ServiceBindingProtocolGuid IPv4Config EfiDhcp6ServiceBind...

Dear R mailing list, I'm trying to fit a censored regression model to a large (dimension of the design matrix is 2e5 by 7) right truncated data by means of the survreg(Surv()) function, as suggested by Paul Johnson on his "R Tips" web page. Possibly due to the sensitivity to the initial values of the Newton-Raphson routine in use by survreg(), resulting regression outputs turn out to be unreliable....

I am trying to use gee() to calculate the robust standard errors for a logit model. My dataset (zol) has 195019 observations; winner, racebl, raceas, racehi are all binary variables. ID is saved as a vector of length 195019 with alternating 0's and 1's. I get the following error message. I also tried the same command with corstr set to "independence" and got the same

...65F36E00EF,0x1)/IPv4(0.0.0.0)) > 2A6: SimpleNetwork PXEBaseCode LoadFile DevicePath(0000:0000:0000:0000:0000:0000)) > 2BB: SimpleNetwork PXEBaseCode LoadFile DevicePath(CDCD40CA5F0,0x0)/IPv4(0.0.0.0)) > 2D0: SimpleNetwork PXEBaseCode LoadFile DevicePath(0000:0000:0000:0000:0000:0000)) > 2E5: SimpleNetwork PXEBaseCode LoadFile DevicePath(CDCD40CA5F4,0x0)/IPv4(0.0.0.0)) > > 23E: MTFTPv4ServiceBinding DHCPv4ServiceBinding UDPv4ServiceBinding UnknownDevice TCPv4ServiceBinding IPv4ServiceBinding ARPServiceBinding UnknownDevice EfiMtftp6ServiceBindingProtocolGuid IPv4Config EfiDhcp6Se...

Hi! I have a data.frame "data" and splitted it. data <- split(data, data[,1]) This is a quite slow procedure; and I do not want to do it again. So, any unsplit and "resplit" is no option for me. But: I have to cbind "variables" to the splitted data from another list, that contains of vectors with matching sizes, so for (i in 1:length(data)) { data[[i]]

Hi R-ers, I am struggling with my x-axis in a association plot. What I would like is to place the labels of the x-axis between the tick markers and normally the labels are printed at the place where the tick marker is placed. I don???t want to move the tick marker (it gives the switch between one chromosome and the next) but I just want to put the chromosome number in between the

...ot;approximations" in place of the "exact" algorithms. > > The standard deviation for a binomial is sqrt(p*(1-p)/n) = > 0.5/sqrt(2e15), which is roughly 1e-8 in your case. > > > I get the following from both S-Plus and R: > > > pbinom(1e5+c(-1, 0, 1), 2e5, .5) > [1] 0.4991079 0.5008921 0.5026762 > > For the problem you cite, the correct answer should be 0.5 to about 8 > significant digits. Instead, I get 1 from R (as you did) and the > following from S-Plus: > > > pbinom(1e15,2e15,0.5) > [1] 0.7411209 > > Both...

Hi, I am just wondering if there is an easy way to count in a numeric vector how many numbers don't have replicates. For example, a=c(1,1,2,2,3,4,5), how can I know there are three numbers (3, 4 and 5) without replicates? Thank you! Jun =====

Hi, all together. I have - a maybe trivial - problem with aggregating a list of weights. Here is the problem: - At first I have set of nodes (X/Y-coordinates) and associated weights, where the set of nodes is typically not unique - I want to get a set of unique nodes and the sum of associated weights I am grateful for any help See for example: # weights: w <- c(1, 1, 1, 1, 1) #

Dear Sir/Madam, I would like to know what is the maximum number of observations a single file must have when using R. I am asking this because am trying to do research on banking transactions and i have around 49million records. Can R handle this? Advise with regard to this. Mark Nasila Quantitative Analyst CBS Risk Management Personal Banking 7th Floor, 2 First Place, Cnr

Dear all Just for fun, I have just downloaded the paper mentioned below and checked it with R-1.6.1. Everything is ok with exception of Table 2b, where I get always 1 instead of 0.5: > pbinom(1e15,2e15,0.5) [1] 1 Which value should be correct? Best regards Christian Stratowa ============================================== Christian Stratowa, PhD Boehringer Ingelheim Austria Dept NCE Lead

I have very large csv files (up to 1GB each of ASCII text). I'd like to be able to read them directly in to R. The problem I am having is with the variable length of the data in each record. Here's a (simplified) example: $ cat foo.csv Name,Start Month,Data Foo,10,-0.5615,2.3065,0.1589,-0.3649,1.5955