Displaying 7 results from an estimated 7 matches for "2df".
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2d
2008 Oct 31
1
AIC for quasipoisson link
Dear fellows,
I'm trying to extract the AIC statistic from a GLM model with quasipoisson link.
The formula I'm referring to is
AIC = -2(maximum loglik) + 2df * phi
with phi the overdispersion parameter, as reported in:
Peng et al., Model choice in time series studies os air pollution and mortality. J R Stat Soc A, 2006; 162: pag 190.
Unfortunately, the function logLik doesn't work for a quasipoisson link.
Do you know a fast method to extract t...
2011 Sep 23
1
p values in coxph()
...put (shown at the bottom).
I have two questions:
1) What exactly are the p-values in the Pr(>|z|) representing? I understand
that the coefficients have standard errors, etc., but i'm not sure how the
p-value there is calculated.
2) At the bottom, where it shows the results of an LRT with 2df, i don't
quite understand what model the ratio is being tested against. If the
current model has two variables (x1 and x2), and those are the extra degrees
of freedom, then the baseline should then have 0 variables, but that's not
really a Cox model?
thanks for any help.
Brian
> sum...
2002 Mar 01
1
glm with binomial errors in R and GLIM
...-> number of animais alive (the response)
n -> total number of animals
To test proportion of alive, make d/n.
In GLIM:
$yvar d$
$error binomial n$
$fit +h$
scale deviance = 25.730 (change = -9.138) at cycle 4
d.f. = 15 (change = -2)
factor h is significant by chisq? with 2df fron tables = 5.99
$disp e$
estimate se parameter
1 -0.1054 0.2055 1
2 0.7985 0.2961 h(2)
3 0.08827 0.26764 h(3)
Scale parameter taken as 1.000
In R:
> modelo.glex24.1 <- glm((d/n)~h,family=binomial)
Warning message:
non-integer #successes in a binomial glm! in:...
2007 May 18
0
Fwd: Re: Goodness-of-fit test for gamma distribution?
...An example of what I'm looking for would be the "K-squared" statistic
that tests for normality (D'Agostino and Pearson 1973, Biometrika 60:
613, also in Zar, 1996, Biostatistical Analysis, p89). The expected
distribution of the test statistic is approximately chi-squared with
2df, regardless of values of estimated parameters or sample size
(provided sample size is sufficiently large).
Petr's reply:
>Maybe it is easier and sufficient to use the Kolmogorov - Smirnov
>test, that is implemented as ks.test() in R. However, I am not able
>to check your reference...
2011 Sep 21
3
Quelplot
Hi all,
Does anyone have an R implementation of the queplot (K.?M. Goldberg
and B.?Iglewicz. Bivariate extensions of the boxplot. Technometrics,
34(3):pp. 307?320, 1992)? I'm struggling with the estimation of the
asymmetry parameters.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/
2006 Jul 15
0
How to Interpret Results of Regression in R
....3165
house3 1.58 1 530.37 < 2e-16 ***
house4 0.76 1 254.75 < 2e-16 ***
Residuals 8.86 2974
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
GVIF Df GVIF^(1/2Df)
as.factor(parkfee) 1.570 2 1.119
fare 1.562 1 1.250
as.factor(ohouse) 1.063 3 1.010
tripMIN 1.110 1 1.054
as.factor(Devt2) 2.378 3 1.155
cityarea 4.188 1 2.046
coreDistance 7.037 1...
2007 Oct 10
5
chi2
Hello,
I want to use the quantile function so I read the doc but I don't understand with this
> qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
[1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39 63160.27 63205.65 63250.33 63295.04 63340.48 63387.48 63437.03 63490.53 63550.14 63619.68
[18] 63707.24 63837.16
Can you help me please?