Displaying 1 result from an estimated 1 matches for "29v5".
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295
2008 Jul 14
1
Computing row means for sets of 2 columns
...17 27 37 [8,] 8 18 28 38 [9,] 9 19 29 39[10,] 10 20 30 40
> (groups <- rep(1:2, each=2))[1] 1 1 2 2
> (m.mean <- t(aggregate(t(m), by=list(groups), mean))) [,1] [,2]Group.1 1 2V1 6 26V2 7 27V3 8 28V4 9 29V5 10 30V6 11 31V7 12 32V8 13 33V9 14 34V10 15 35
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