search for: 296857

Hi, I am writing a function that includes 'sum' function such as: f<-function(x){ c<-c(-1,0,1) f<-sum(c+x) } expecting f to be -1+x+0+x+1+x=3x. But I found out that f is sum(x). So, f is always a scalar, which means that f(c(0,1)) is not a vector as c(0,3), but 3(0+1)=3. I would like to ask you helping me in solving this problem. I would like to thank you in advance. Sungsu.

Hi Stepan, Sorry for the delay. It's great that you are working on MergeFunctions as well and I agree, we should definitely try to combine our efforts to improve MergeFunctions. Just to give you some context, the pass (with the similar function merging patch) is already being used in a production setting. From my point of view, it would be better if we focus on improving its capability

...18 0 0.03 197218 z42.ll 7 66774 0 0.01 66740 0 0.01 66740 z43.ll 10 162291 0 0.02 162257 0 0.02 162257 z44.ll 7 714200 0 0.06 714166 0 0.06 714166 z45.ll 6 22350 0 0.01 22316 0 0.01 22316 z46.ll 4 463428 0 0.04 463394 0 0.04 463394 z47.ll 5 216156 0 0.03 216122 0 0.02 216122 z48.ll 59 296891 0 0.04 296857 0 0.04 295314 z49.ll 32 342979 0 0.04 342945 0 0.04 342945 z50.ll 23 102145 1 0.02 101702 1 0.02 101702 z51.ll 23 53684 1 0.01 53243 1 0.01 53243 zalloc.ll 3 4819 0 0.01 4803 0 0.01 4803 zarith.ll 12 55152 0 0.02 55128 0 0.02 54189 zarray.ll 5 18535 0 0.01 18511 0 0.01 18511 zchar.ll 20 100759 0 0....