Displaying 1 result from an estimated 1 matches for "26.129".
2012 Aug 06
5
sapply() and by()
Hello everyone,
I have a dataset with 5 colums (4 colums with thresholds of weather
stations and one with month - data of 5 years). Now I would like to
calculate the average for each month.
I tried this unsuccessfully:
lf.med <- sapply(LF[,1:4],mean,LF[,5])
Error in mean.default(X[[1L]], ...) :
'trim' must be numeric and have length 1
With
lf.med <- by(LF[,1:4],LF[,5],mean)