search for: 255b488f

...sing mapply with some line like this : > mapply(if,u$POSITION,==0,print("WARNING:POSITIONS ARE WRONG",quote=F)) But it seems it is not the correct way to pass the various arguments. Any help is appreciated *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F

...419,100420. The object "l" is a list, but can be of any other kind if it can help. I tried something like this : >select<-l[c(x:y)] But it doesn't return the needed result Any help would be appreciated *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F

...te (09/07/10 .). I know the function substr(x, start, stop), but in my case, I need to indicate I want to start from the end of the vector, and I have no idea how to pass this argument. TY for any help *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F *************************** [[alternative HTML version deleted]]

...on. If I do a save(), it will be saved in my directory, but won't see it when I do ls(), even if I do a get() before. What is the process to save these 2 objects in order to access them later in another function? *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F *************************** [[alternative HTML version deleted]]

...was thinking using something like this: >df3$DESCRIPTION<- gsub("here is a regex expression","",df3$DESCRIPTION). Can't write the pattern argument in regex. Any help would be appreciated. TY *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F

...ot; column is character, when I want it numeric. I can't change the column class, even when playing with the read.csv or as.numeric commands and all their arguments. Any help would be appreciate. *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F *************************** [[alternative HTML version deleted]]

I have a data frame called "pose": DESCRIPTION QUANITY CLOSING.PRICE 1 WHEAT May/10 1 467.75 2 WHEAT May/10 2 467.75 3 WHEAT May/10 1 467.75 4 WHEAT May/10 1 467.75 5 COTTON NO.2 May/10 1 78.13 6 COTTON NO.2 May/10 3 78.13 7 COTTON NO.2 May/10 1 78.13

Dear list, here are my two data frames: av <- structure(list(DESCRIPTION = c("COFFEE C Sep/10", "COPPER Sep/10", "CORN Dec/10", "CRUDE OIL miNY Sep/10", "GOLD Aug/10", "HENRY HUB NATURAL GAS Sep/10", "PALLADIUM Sep/10", "SILVER Sep/10", "SOYBEANS Nov/10", "SPCL HIGH GRADE ZINC USD", "SUGAR